For the guys who are saying the formula doesn't work for larger masses. The reason is that once the 30 g is fixed permanently, larger masses will tend to pull the mass upward. Hence, you can't find a balance point at the midpoint. I actually tried out the experiment with masses of 50, 100, 150, 200, and 250. They couldn't balance out. That was why I changed the masses to 10, 20, 30, 40, and 50 on the real practical video.
good morning sir, i want to say a very big thank you sir, i am so grateful for ur effort to see that every student makes it into the tertiary institution, thank you very much sir
@@SmilingFieldHockey-em7rm that's because if the mass is 70, it will pull the 30 g mass up. So, it won't work for 70 g. If the mass is greater than 30 g, 70 g will work
Wow wow.. this is genius! Very helpful sir.. thank you. I have a little problem o.. 1. The Tension, T=0.30N caused by 0.01M, I was expecting T (tension) to vary in proportion to the different masses hung.. but u used 0.30 all through. I still don't get that part clearly. Anticipating your response. Thanks once again.
@SundayEzeh-cs4nj it wasn't assumed. I first converted it kilogram by dividing by 1000 and then to newtons by multiplying by 10. It will still work even if you don't convert it. You can just leave the masses like that.
@@yousciencelab5307 what can I do since neco gave 30g as the fixed mass. And the question might probably require the use of a larger mass. Is there any other formula I can use because when I tried the formula for the angle you gave,it was math error.... Is there any other formula for that sir??
@tundeadeleye1000 If the fixed mass is 30 g, then NECO would provide masses that will fall in the range where the formula will work. For example, if Neco gives masses like 40, 50, 70, 90, 110 or 130, it will be advisable to use 100 g as the fixed mass. If you use a smaller mass like 30, 40 or 50, it won't work. This is because, the bigger masses would just drag them up the pulley.
In situation where NECO asked you to fixed the mass W as 30g..which of course will not work for larger Valur of M from 70g..can we niow change the mass W to higher one ...agaist NECO rewuired Value?
@michaelkayode9912 I'm sure NECO cannot ask you to provide masses which cannot make the whole system stay balanced. Remember, the set of masses must be able to balance each other out.
For the guys who are saying the formula doesn't work for larger masses. The reason is that once the 30 g is fixed permanently, larger masses will tend to pull the mass upward. Hence, you can't find a balance point at the midpoint. I actually tried out the experiment with masses of 50, 100, 150, 200, and 250. They couldn't balance out. That was why I changed the masses to 10, 20, 30, 40, and 50 on the real practical video.
good morning sir, i want to say a very big thank you sir, i am so grateful for ur effort to see that every student makes it into the tertiary institution, thank you very much sir
@@Vision20k good morning. Thanks for your kind words.
My brother when you use big mass like 70g .. The formula won't work
@@SmilingFieldHockey-em7rm that's because if the mass is 70, it will pull the 30 g mass up.
So, it won't work for 70 g.
If the mass is greater than 30 g, 70 g will work
Thank you very much sir
Wow wow.. this is genius!
Very helpful sir.. thank you.
I have a little problem o..
1. The Tension, T=0.30N caused by 0.01M, I was expecting T (tension) to vary in proportion to the different masses hung.. but u used 0.30 all through. I still don't get that part clearly.
Anticipating your response.
Thanks once again.
The 30g mass is fixed and does not change
Yes, the tension varies due to the masses. That's why the angles change.
Am so glad to have seen this video, Thank you sir🎉
@@abdulmuizzsali I'm glad to hear this.
God bless u sir you’re such a genius ❤❤
@@chijiokeemmanuel9265 I appreciate your comment. Thanks.
Thank you so much sir🙂❤
Thank you very much Sir
I want to ask if the 30g you used to divide by 1000 and multipled by 10 to get your newton was an assumed figure?
@SundayEzeh-cs4nj it wasn't assumed. I first converted it kilogram by dividing by 1000 and then to newtons by multiplying by 10.
It will still work even if you don't convert it. You can just leave the masses like that.
Well done sir... But i tried using a mass above 50...like 60 to get my angle,but i couldn't sir...
I dont understand why😢😢
@tundeadeleye1000 of course, it won't work because a mass above taste would slide the 30 g mass up.
For it to work, the 30 g mass has to be higher.
@@yousciencelab5307 what can I do since neco gave 30g as the fixed mass.
And the question might probably require the use of a larger mass.
Is there any other formula I can use because when I tried the formula for the angle you gave,it was math error....
Is there any other formula for that sir??
@tundeadeleye1000 If the fixed mass is 30 g, then NECO would provide masses that will fall in the range where the formula will work.
For example, if Neco gives masses like 40, 50, 70, 90, 110 or 130, it will be advisable to use 100 g as the fixed mass. If you use a smaller mass like 30, 40 or 50, it won't work. This is because, the bigger masses would just drag them up the pulley.
Please sir can you make a video for 2024 NECO further mathematics
@@AfamefunaEmmanuel-jb6sc I'll try. When is the exam?
@@yousciencelab5307 thank you sir
The paper is on Monday 1st of July
God bless you sir ❤
@@OdebiyiMichael-wp1ej God bless you too.
Sir i don't understand how you resolved that Tension to 2Tsin0(teta)
@@AmaechiJeffery check your physics textbooks on how to resolve vectors.
In situation where NECO asked you to fixed the mass W as 30g..which of course will not work for larger Valur of M from 70g..can we niow change the mass W to higher one ...agaist NECO rewuired Value?
@michaelkayode9912 I'm sure NECO cannot ask you to provide masses which cannot make the whole system stay balanced.
Remember, the set of masses must be able to balance each other out.
But sir you readings are different form your previous video
It has to be. First of all, the length AC is not the same in both videos. Secondly, the manipulated values are more accurate.
Is it illegal
@@desmondanthony7135 okay
@@desmondanthony7135 mo
Thanks so much sir