Well explained,just a point,we need to sketch the curve to identify the limits, sometimes it's not direct kama kwa hii question,you may find out that maybe the curve occurs below and above the x axis
sir i have a questioncan we first integrate first from -3 to 0 then 0-5 and then add the answer.I mostly wrong when integrating directly area under a curve. when should we do that
Absolutely yes..that's the best approach and you will get an accurate answer. There are questions you will get wrong when you integrate directly. Begin with a simple sketch of the graph. When you notice some area lies on the negative side of the axis, do it in parts i.e the area on the negative axis then add the area on the positve axis
I dont think there is another way. Just know that when using 5 ordinates, you will need 4 intervals, 6 ordinates, you need 5 intervals and so on... h = interval(b -a) ÷ (ordinates - 1)
Well explained,just a point,we need to sketch the curve to identify the limits, sometimes it's not direct kama kwa hii question,you may find out that maybe the curve occurs below and above the x axis
Thanks..yes sketching is very important..it helps esp where an area lies below the x-axis
sir i have a questioncan we first integrate first from -3 to 0 then 0-5 and then add the answer.I mostly wrong when integrating directly area under a curve. when should we do that
Absolutely yes..that's the best approach and you will get an accurate answer. There are questions you will get wrong when you integrate directly. Begin with a simple sketch of the graph. When you notice some area lies on the negative side of the axis, do it in parts i.e the area on the negative axis then add the area on the positve axis
Thanks but about how we find the h ,,, is there another way ,,, coz it's unclear for mee😢
I dont think there is another way. Just know that when using 5 ordinates, you will need 4 intervals, 6 ordinates, you need 5 intervals and so on...
h = interval(b -a) ÷ (ordinates - 1)
I can seen confused in Question c to find the height we =x2-x1/ordinate
Replying me how did your get height