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सर अपने इतना हम लोगों के लिए किए और हमे अच्छे से समझ भी आ गया इसके।लिए बहुत बहुत धन्यवाद
All explanation is great But the last ans GM IS 3.5964
thankyou sir your way of teaching is awSm
Excellent explanation sir, thanks for performing this experiment
ruclips.net/video/zTmjJD36byA/видео.html
Sir after calculating 0.6*13/(0.6+11.7)tan10=0.978076273Kindly Justify your calculation .that the height is 3.78
Thank You Sir, what you explained was very well understood in your video.
Will the metacentric height remain same or change if the 600 -gram load was placed at a distance of 6 cm from the center?
Sir weight of fluid displaced = buoyant force. Fir aap ne weight of body immersed in water se equate kiya hai kya?
Thank you so much sir 😇 this video helps me very in a short time period before 1 day from practical
ruclips.net/video/zTmjJD36byA/видео.html..
Nice sir...Keep teaching...Thanks sir
Well explained sir thank you
Sir ye sb toh thik h, but me iska real life kya application krne wala hu, isse mile data se kya krunga....ye kyu important h????pls sir acknowledge me
Sir aapke channel ka naam aisa kyu hai? Thank u for the well explained video sir, hope to see some more of these type of videos.
yeah..his channels name is pretty unique.. though thanks to sir for explaining so well
Please make more videos as per certain books like reeds naval arch so students can follow with you
Thank you sir! It helped a lot!
New volume me 1m3 is equal 1000lit. Hota he not a 1 cm3
Thanks for taking efforts
Nice video
Thank you v. much Sir!
How u calculate the angle of 10degree?
Actually there is a protacter inside which is used to measure angle as the pointer tilts and makes an angle.
best explanation👌
ans 3.59
great teacher...
Easily understand the concept......
great explanation
Very nice Sir ji
Very nice sir
Sir pls upload v notch experiment
nice description
Plz correction this
Great
Thankyou so much sir
tysm sir g ❤️❤️
shukriya sir
Thaks sir
👌👌👌
You helped me so much
CHAN sir👌
best
Bekar hai.....
सर अपने इतना हम लोगों के लिए किए और हमे अच्छे से समझ भी आ गया इसके।लिए बहुत बहुत धन्यवाद
All explanation is great
But the last ans GM IS 3.5964
thankyou sir your way of teaching is awSm
Excellent explanation sir, thanks for performing this experiment
ruclips.net/video/zTmjJD36byA/видео.html
Sir after calculating 0.6*13/(0.6+11.7)tan10=0.978076273
Kindly Justify your calculation .that the height is 3.78
Thank You Sir, what you explained was very well understood in your video.
Will the metacentric height remain same or change if the 600 -gram load was placed at a distance of 6 cm from the center?
Sir weight of fluid displaced = buoyant force. Fir aap ne weight of body immersed in water se equate kiya hai kya?
Thank you so much sir 😇 this video helps me very in a short time period before 1 day from practical
ruclips.net/video/zTmjJD36byA/видео.html
..
Nice sir...Keep teaching...Thanks sir
Well explained sir thank you
Sir ye sb toh thik h, but me iska real life kya application krne wala hu, isse mile data se kya krunga....ye kyu important h????pls sir acknowledge me
Sir aapke channel ka naam aisa kyu hai? Thank u for the well explained video sir, hope to see some more of these type of videos.
yeah..his channels name is pretty unique.. though thanks to sir for explaining so well
Please make more videos as per certain books like reeds naval arch so students can follow with you
Thank you sir! It helped a lot!
New volume me 1m3 is equal 1000lit. Hota he not a 1 cm3
Thanks for taking efforts
Nice video
Thank you v. much Sir!
How u calculate the angle of 10degree?
Actually there is a protacter inside which is used to measure angle as the pointer tilts and makes an angle.
best explanation👌
ans 3.59
great teacher...
ruclips.net/video/zTmjJD36byA/видео.html
.
.
Easily understand the concept......
great explanation
Very nice Sir ji
Very nice sir
Sir pls upload v notch experiment
nice description
Plz correction this
Great
Thankyou so much sir
tysm sir g ❤️❤️
ruclips.net/video/zTmjJD36byA/видео.html
..
shukriya sir
ruclips.net/video/zTmjJD36byA/видео.html
Thaks sir
👌👌👌
You helped me so much
CHAN sir👌
best
Bekar hai.....