Block over Block Friction Cases for JEE(Adv) | Class 11 Physics in Minutes |
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- Опубликовано: 7 сен 2020
- Block over block problems in friction is the foundation of understanding dynamics of friction. Ashish Arora sir has explained the fundamental concepts related to application of friction when a block over another block is placed and lower block is pulled by an external force. On all these concepts frequently questions are asked in JEE Mains, JEE Advanced, NEET, NSEP and National/International Physics Olympiads.
Detailed understanding of the concept can be covered through the Physics Galaxy Concept videos available through our channel playlist or our website.
www.physicsgalaxy.com
Students can follow our channel updates on our facebook page.
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Based on above video some questions are given below in comment section which students can solve and check if they are able to solve these questions using the concept explained in above video. Out of 3 questions given below for third question answers are not given. Students are advised to post the answer of this question in comments to discuss and verify if their answer is correct.
Practice Quiz Que -
Q1. A 4kg block is placed over 8kg block on a rough ground. Friction coefficient between 8kg and ground is 0.5 and that between the two blocks is 0.2. A force F is applied horizontallay on 8kg block. Find at what value of F sliding will start between 8kg and ground then at which value sliding will start between the two blocks ?
Ans [60N, 84N]
Q2. A 7kg block is placed over 5kg block on a rough ground. Friction coefficient between 5kg and ground is 0.3 and that between the two blocks is 0.5. A force F is applied horizontallay on 5kg block. Find at what value of F sliding will start between 5kg and ground then at which value sliding will start between the two blocks ?
Ans [36N, 96N]
Q3. A 10kg block is placed over 20kg block on a rough ground. Friction coefficient between 20kg and ground is 0.1 and that between the two blocks is 0.2. A force F is applied horizontallay on 20kg block. Find at what value of F sliding will start between 20kg and ground then at which value sliding will start between the two blocks ?
Ans [Post Your Answer of Q3 in comment section to verify]
#physicsinminutes #physicsgalaxy #ashisharora #physicsgalaxypim
Practice Questions for students on concept of above video. Students are required to solve these questions and verify the answers given and for Q3. Solve the question and post your answer in comment section for discussion and verifying your answers. In all below questions take g = 10m/s².
Q1. A 4kg block is placed over 8kg block on a rough ground. Friction coefficient between 8kg and ground is 0.5 and that between the two blocks is 0.2. A force F is applied horizontallay on 8kg block. Find at what value of F sliding will start between 8kg and ground then at which value sliding will start between the two blocks ?
Ans [60N, 84N]
Q2. A 7kg block is placed over 5kg block on a rough ground. Friction coefficient between 5kg and ground is 0.3 and that between the two blocks is 0.5. A force F is applied horizontallay on 5kg block. Find at what value of F sliding will start between 5kg and ground then at which value sliding will start between the two blocks ?
Ans [36N, 96N]
Q3. A 10kg block is placed over 20kg block on a rough ground. Friction coefficient between 20kg and ground is 0.1 and that between the two blocks is 0.2. A force F is applied horizontallay on 20kg block. Find at what value of F sliding will start between 20kg and ground then at which value sliding will start between the two blocks ?
Ans [Post Your Answer of Q3 in comment section to verify]
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Sir, plz post such questions after every video based on the content of the video
30N and 60N
30 and 90 N
30N and 90 N respectively
Sir you are literally the best teacher who makes concepts too easy to understand. You make all of us love Physics.
Sir please start something live for class 11 JEE also if possible !!!
Yes sir please try to do that
Thanks sir, friction is clear now.
Sir only because of you i got confidence to attempt physics Examwell thanks a lot for your affords i used to feel physics tough before watching your videos after watching your videos i improved a lot
30 N and 90 N.
thank you soooooo much sir for these valuable videos. these are very very helpful for all of us.
Great, You got it right Ankush!
Sir I have watched hundreds of your videos but still im trying to understand how you edit your videos ......THANK YOU FOR TAKING SUCH GOOD EFFORTS for students and using THESE PLATFORMS WISELY ❤️❤️❤️❤️👍👍👍👍👍
thank u sir , I have massive doubts in this beat, but all is crystal clear now
Answers of Question-3 is (a) 30 N and (b) 90 N respectively
I can't tell u sir how much u are helping me sir I almost lost this concept but u made this very easy for me ❣️❣️❣️🥺🥺🥺🥺 love u sir 🙏🏻🙏🏻🙏🏻🙏🏻❣️love u infinity🙏🏻🙏🏻
30N & 90N
Answer for the 3rd question is 30N and 90N...am I correct?
Thank you so much Sir..for these amazing sessions..🙏🏼
Sejal Sangole yes 30 N and 90 N
You got it right Sejal!
Yes
@@AbhinavSingh-qk4so sir had pinned the comment of Q, see it
Yes
thank you sir
you are the best physics teacher i have ever seen
most hardworking person
with no glimpse of the slightest arrogance
🙏🙏🙏🙏
thanks a lot and all the best
My concept is crystal clear now.THANK YOU SIR.😊
I can't tell you how much these videos are helping me.
Why
@@babayoga8206 are भाई these are helping me in my jee preparation 2022 aspirant
@@INSPIRING_ROHIT Bhai joke tha ki why u can't tell 😂😅😅
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@@babayoga8206 🤣🤣🤣kya joke tha!
Sir I admire you and Respect you with the depth of my heart. You are the best Physics teacher I've ever seen in my life. You are the God Of JEE Physics 💯
Ashish sir please,make video on how we plan for every physics lecture after this
Thank u sir,it was extremely needed
can't thank you enough sir :)))
Thanks sir for your all effort your revision checlist videos really boost my prepration to next level
Sir you are really an excellent teacher your concept clearing power is awesome you are great
30N ,90N is the answer. Very easy question, I m thinking. But reality is that Ashish sir has made us so prone to solve this types of problems. Thankyou Sir
Seedhi baat no bakwas....hats off sir...cause you didnt tell lot of stories in between and wasting time of students.....true content...
You and prashant sir are a boon to all of us. Aapne milkar cut off ko badha diya hai 🔥🙏🙏
Ese videos dete rahiyega sir much much support and respect from a 11 th grader 😊😊
Very easy shortcut nice.
Sir I salute you...💕 And also request you to please make more videos on such important concepts ..which help us🤘
Can't thank you enough sir !
1) limiting friction of ground touching block is 30 N
2) the maximum force by which both boxes can move, while staying at rest with respect to each other (F max) is 90 N.
Thank you sir. Hindi videos are very helpful sir. I am following your guidance for my Medical entrance this year.
Thanks for the video..i m weak in mechanics ...your videos have made mechanics simplified and interesting for me..Dear sir ..kindly make some videos on solving circuits of current electricity, Capacitance , Inductor , LR, RC...it will be very helpful ...please sir
Thx sir for clearing my doubt 😀😍
Thank you for this video sir🙏🙏🙏🙏🙏
Sir ji.., love you and your teaching
answer is 30N to start the sliding between the block and ground, and 90N for sliding between blocks, as 60 will be required for upper block to slide and 30 for the lower and ground = 90N.
Thanks a lot sir.🙏
I am not getting when the two blocks will have common acceleration and when would they have different accelerations....can someone plzzz help🙏
Thanks for your class 😊
Sir, after limiting friction on upper block is achieved will
a) acceleration of upper block = acceleration of lower block
b) acceleration of both blocks are different
c) whats the direction of acceleration of upper block
Sir kindly solve few questions on block over block in which force is applied to each block .
best teacher 🙇🙇♂️ thanks sir
Love you sir
May god bless you
U can't imagine how much ur videos are helping us
Thank you so much sir❤️❤️❤️
Thank sir
The only satisfactory Physics teacher in internet is "Physics Galaxy "... 👏👏
Thank you respected sir for so much
Above or equal to 90 N requied for sliding between two blocks and min force requied to move is 30 N
Thank you sir:)
Thank You so much sir... Whenever you appear on the screen, a new hope rises in me and being a neet aspirant these videos are really helpful...
Thanks a lot once again sir... 🙏🙏🙏
Hi Men Where Are You Now;?
@@mochi_minutes8758 I am in a Medical College, a 3rd year student...
@@patitapabanpattanayak5147 ooooooo all the best for future men you did great 👑
i thjink sir is GOD.............he knows what i want i was struggling with this type of ques and he uploaded just what i wanted
sir 30 and 90 thank you for your extraordinary support
Sir plz make a video on jee advanced 2020..🙏🙏
Thank you sir!!
Sir plz make videos for 2021 jee students
Ans.3 90N,30N sir acc. to previous questions I understood that 90 will be 1st ans.and 30 will be second ans.?
Hello sir 🙏🏻🙏🏻🙏🏻🙏🏻
Keep uploading these checklist for
Neet 2021 aspirants
These checklists are very much important
for our examination
So its a request
from my side that
to keep uploading these checklist
till the syllabus
gets complited
if F is less than the combined combined friction, then according to fbd, m2 moves while m1 is static? how is this possible
Ans for the 3rd Ques is [30 N ; 90 N ] . Also,waiting for also your incoming videos .
U r Just osm sir......
Thank you sir
Epic simply
Q. 3 F at which sliding begins between ground and blocks= 30N.
F at which sliding begins between blocks = 90N.
3:40 is it not possible that M2 slides over M1 before they move together with a common acceleration. Suppose if value of limiting friction for M2 is less than value of limiting friction for M1 , in that case is it not possible that M2 slides over M1 before they both(M1 and M2) start moving together?
Sir please resume physics in minutes series for other chapters also .🙏
sir how to select strip while integration... like dm ,dv etc... (2019 adv gravitation question) use this question as example.. sir plz
Q3....30 N and 90 N respectively
Thats right ! Good going !
Great sir
Sir plzz do analysis for jee advanced physics.
Great teacher ..u re
Sir could you please help in providing solutions for previous years NEST( national entrance screening test) papers?
3) 30N and 90N
i)30N, ii) 90N
Will you post the video for electrostats and magnetic?
Sir ... Please make a video on projectile on an inclined plane ...
cleared sir
Thanks a lot
thank you s😀😀😀😀 for this awesome session
For homework Q - [30N, 90N]
Thanks for the video and quiz 🙏🏻
Q3. Ans=30N & 90N
Thats right ! Good going !
Dear Ashish sir please start live class hurry ,we are waiting 👍👍🙏
It will be announced soon.
This question came in September attempt of JEE MAINS 2021
sir kya baat hai maja aagya
sir how to solve for 3 block ? please make a video on that. i am unable to solve such problem of hc verma
Please make a video on relative motion and cat chasing rat problems
Answer is 30N and 90N.
Thats right ! Good going !
[ 30N,90N ]
30N, 90N
sir answer for 3 rd question is 30N and 90N
Sir please make video on rotation of rod and it's analysis
keep watching, coming soon
You are a legend of physics sir.....thanks.plzz make a video on collision
coming up soon
Sir plz ammeter ar galvanometer k questions kra do short me plz
Sir ...when will booster series for advanced be started???
Sir please all. Concept before jee 2020
Please make a video regarding important topics for jee advanced chapter wise.
Coming up soon.
Answer for the first part is 30 N and for the second part is 90 N
Q.3 ans 30N and 90N
Answer for question number 3.
30N and 90N.
Thank u PG
sir please make vedio on CRTM
sir jee advanced me lens eqn aur ,modern physics ke kch topic s regularly puche ja rhe hai unke concepts pe differential eqn ke form me solve kane me prblm ho rha hai
Sir I had a doubt regarding a question of Work Energy
Sir in the following type of question
Q)
A small particle slides along a track with elevated ends and a flat Central Part. the flat part has a length 3M the curved portion of the track are frictionless but for the flat part the coefficient of kinetic friction is 0.2 the particle is released at point a which is at a height h is equal to 1.5 metre above the flat part of the track. where does the particle finally come to rest?
Why don't we measure the distance covered by the block in the curved portion. I am not getting full satisfactory answer to this question. Hope You will Answer Sir 🙏🙏🙏
Not sir to answer but if u find it convincing then fine...
Gravity force is conservative in nature.. path taken is not considered while calculating work done or energy BUT
SHORTEST PATH (Displacement) IS TAKEN TO CONSIDERATION..
For A F>30N and for B F=90N
Sir Plzz make PiM on acceleration of block after cutting string and spring.plzz🙏🙏🙏🙏
coming soon
Sir I am Aakashian !! And allen dlp student .. And I know it never matter ... What all matter is our hard work... And what pushes us .. Is teachers !! They act as feather over crown... Sir thank you !... Fir being here . thank you so much
Hut bc
2:23 🌟🌟