Relational Algebra (Division Operation)

[@BusuBong]

I am taking a $300 course in Korea, but your free lectures are always much better. I am always deeply grateful for them. Thank you very much.

[@fatimaali1125]

Homework Ans:
The division operation is not possible because the student relation is not a proper subset of the course relation as not all attributes (columns) in student are present in course

[@Ashahp11]

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[@DharmeshGuna]

Great explanation. Thank you!

[@mohanamisra]

Welp. Wish this playlist was completed for my exam tomorrow...

[@rakeshchanda-j7s]

which year?

[@muneebashraf8983]

Try to complete this within 2 to 3 months
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[@jorgesarmiento147]

thank you i was struggling to get this concept right and you made it so easy to understand

[@mohamadbader03]

Amazing Explanation! Thank you

[@yabon87]

no,because in the new expression course/student the numrator course isn't proper subset of the denominator one which is student 😊

[@hareshparab7808]

It is derieved operator right so internally we are using some sort of difference operator as well as cross product what about that ?

[@mohammad.businessmanagement]

❤❤❤

[@rikamoiisrael131]

it is not possible because every attribute in student is not present in the course relation.

[@SwathiR-di8ps]

Division condition : student is not a proper subset of course. Course has only one tuple whereas student has 2 tuples so this is not possible

[@lifeahead5208]

I actually don't know why
But may be because name attribute is not in the r2 table

[@sakthi______9321]

It is impossible. Because the course relation is not a proper subset of the relation student

[@sumitpal3723]

Not possible becouse course is not super set becouse id does not content name of student