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Thanks, great explanation. Keep it up the good work
This is one of the best logic. Have never seen in any site.
Thanks Its very nice logic to find out duplicate cout
Thanks a lot sir, and wish you all the very best.
So nice of you
well explained bro.. Great
you can also use trim() method instead of replace
if(count>1) { map.put(arr[i], count); }If you apply this logic then we will get only duplicate characters count.
Thank You sir great explaination
The best Explanation I've ever seen..Thanks alot..❤❤
Sir you are the best teacher in my life i never see this type of explanation in coding ❤️ thankew so much sir 🙏🙏
❤
Best implementation,thanks a lot
you can solve with string not required to convert into array
Super explanation sir do more videos on java developer
Thank you so much sir
and please make videos on collection interfaces and classes
thanks alot..
Hi Sir Very informative session , in above how it is printing the unique character because it may print like a=4 a=4 a=4 a=4 because arr[i] is traversing from 0 index to length
Find recurrence of text ab means how to find s = " abababaabababaaa"
can you explain the same question without having 2 for loop so that time complexity will reduce .
Getting error in Map map = new TreeMap() Error: Character cannot resolved to a type
import java.util.*;class TestMap { public static void main(String[] args) { Map map = new TreeMap(); map.put('c',10); System.out.println(map.get('c')); }}please write proper way. import
Sir why your use for loop inside another for loop ,or anyone can explain this pls if possible....?
what
why treemap is used?
So that order is maintained
Array index outof bound exception it's showing
Please write code probably. It's will not give exception or error
Very easy to understand. Thanks much
Thanks, great explanation. Keep it up the good work
This is one of the best logic. Have never seen in any site.
Thanks Its very nice logic to find out duplicate cout
Thanks a lot sir, and wish you all the very best.
So nice of you
well explained bro.. Great
you can also use trim() method instead of replace
if(count>1) {
map.put(arr[i], count);
}
If you apply this logic then we will get only duplicate characters count.
Thank You sir great explaination
The best Explanation I've ever seen..Thanks alot..❤❤
Sir you are the best teacher in my life i never see this type of explanation in coding ❤️ thankew so much sir 🙏🙏
❤
Best implementation,thanks a lot
you can solve with string not required to convert into array
Super explanation sir do more videos on java developer
Thank you so much sir
and please make videos on collection interfaces and classes
thanks alot..
Hi Sir Very informative session , in above how it is printing the unique character because it may print like a=4 a=4 a=4 a=4 because arr[i] is traversing from 0 index to length
Find recurrence of text ab means how to find s = " abababaabababaaa"
can you explain the same question without having 2 for loop so that time complexity will reduce .
Getting error in
Map map = new TreeMap()
Error: Character cannot resolved to a type
import java.util.*;
class TestMap
{
public static void main(String[] args)
{
Map map = new TreeMap();
map.put('c',10);
System.out.println(map.get('c'));
}
}
please write proper way. import
Sir why your use for loop inside another for loop ,or anyone can explain this pls if possible....?
what
why treemap is used?
So that order is maintained
Array index outof bound exception it's showing
Please write code probably. It's will not give exception or error
Very easy to understand. Thanks much