Initial Value and Final Value Theorems

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  • Опубликовано: 10 фев 2025
  • Control Systems: Initial Value and Final Value Theorems
    Topics discussed:
    1. Initial and final values of a signal (function).
    2. Significance of Initial and Final Value Theorems.
    3. Initial Value Theorem.
    4. Example based on the Initial Value Theorem.
    5. Conditions of Initial Value Theorem.
    6. Final Value Theorem.
    7. Example based on the Final Value Theorem.
    8. Conditions of Final Value Theorem.
    9. Examples of Unbounded and Oscillatory Functions where the Final Value Theorem is not applicable.
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    Music:
    Axol x Alex Skrindo - You [NCS Release]
    #ControlSystemByNeso #ControlSystems #InitalValueTheorem #FinalValueTheorem

Комментарии • 53

  • @aaronfritz6892
    @aaronfritz6892 2 года назад +43

    Seriously, its so weird having a college professor jump straight into how to derive these concepts without explaining the concept in terms of what its used for or how it relates to other things. These videos are what fills the gap for me, thanks for making this intuitive for a beginner!

  • @sanjayprabhu6909
    @sanjayprabhu6909 4 года назад +15

    hello neso i am really happy you are uploading vedios continously thankyou very much

  • @PunmasterSTP
    @PunmasterSTP 3 года назад +6

    Initial value? More like "Incredible; thank you!" These videos really are quite splendid.

  • @maharjaveed8289
    @maharjaveed8289 3 года назад +2

    Good method and easy to understand
    Again your's work is very Good

  • @balasubramaniyans1426
    @balasubramaniyans1426 3 года назад +3

    Excellent explanations sir

  • @mohammeduzair1276
    @mohammeduzair1276 3 года назад +8

    I can't believe the fact that such amazing videos have such few likes!

  • @rahulguptha3131
    @rahulguptha3131 4 года назад +3

    Nice video thank you we need more videos like this

  • @ippalavalasaanusha3672
    @ippalavalasaanusha3672 3 месяца назад

    Thanks a lot neso academy for the great explanation

  • @gowriv944
    @gowriv944 4 года назад +2

    Nice sir.upload more and more vedios about control system.

  • @sohelansari-dq5kv
    @sohelansari-dq5kv 4 года назад +2

    great teacher

  • @NitinSharma-so9hg
    @NitinSharma-so9hg Год назад

    Good Lecture . THANKYOU

  • @patriciaa4260
    @patriciaa4260 2 года назад

    Thank you so much! You have helped me!

  • @hikmathasanov
    @hikmathasanov 3 года назад +1

    For the first condition, I think it is supposed to be s.F(s). That is how it was explained before at Signals and Systems Lecture Series.

  • @sarojinivaradharajan5598
    @sarojinivaradharajan5598 3 года назад +1

    Great! Thank you very much

  • @s.m.senses7199
    @s.m.senses7199 3 года назад +1

    thanks Sir🙏❤

  • @kaverik.thekodda
    @kaverik.thekodda 2 года назад +1

    Is the value of u(0) & u(inf.) just equal to "1"?
    See 01:50
    I ask because, we determine the value of the function using only the term with the exponent.
    (or that's how it seems)

    • @kaverik.thekodda
      @kaverik.thekodda 2 года назад

      does the question makes sense?

    • @comment8767
      @comment8767 Год назад

      u(t) looks like it might be a step function .... is is not just anything. So is does equal 1 at times later than zero.

  • @Happiestsoul31
    @Happiestsoul31 4 года назад +1

    Thank you

  • @aaqibrashidle6655
    @aaqibrashidle6655 3 года назад +2

    Uh r great sir

  • @triposat
    @triposat 4 года назад +8

    Please upload the lectures of Data Structure as soon as possible. please sir 🙏🙏

  • @vectorrehan9340
    @vectorrehan9340 3 года назад

    thanks a lot

  • @vinayaaaaaaa
    @vinayaaaaaaa 3 года назад +2

    Sir please upload transient analysis🙏😭

  • @harshitpandey8696
    @harshitpandey8696 3 месяца назад

    ❤️❤️❤️😭😭😭tysm

  • @pawandabad5263
    @pawandabad5263 4 года назад +1

    Nice sir

  • @sudeepshetty4530
    @sudeepshetty4530 3 года назад +2

    In final value theorem 2nd example, how do you say F(s)=1/(s-2) pole value is 2? No clarity given about direct conclusion of RHS value?? Can you explain more..other than that quality of explanation is super.

    • @PunmasterSTP
      @PunmasterSTP 3 года назад +2

      A pole is a value of the variable that makes the denominator of a function equal to zero. Because the factor (s - 2) is in the denominator of F(s), we can set s - 2 = 0 to see that s = 2 is a pole.

  • @shraddhajalwani5481
    @shraddhajalwani5481 4 года назад +1

    sir please upload the power system video 🙏🙏🙏🙏❤
    you have uploaded 26 videos only please complete it ,

  • @agjhv3835
    @agjhv3835 3 года назад +1

    5:38 but the example you took is discontinuous at t =0

    • @PunmasterSTP
      @PunmasterSTP 3 года назад +2

      Yeah I was a bit unsure of that part as well. I think the main idea is that the function can't be discontinuous immediately after t = 0, as in, f(0+) is finite and the limit of f as t approaches 0 from the right is f(0+).

  • @chidanandadatta4695
    @chidanandadatta4695 4 года назад +1

    Can we say, result from final value theorem as dc value of the system??

  • @comment8767
    @comment8767 Год назад

    The value of u(0) in Example 1 is unclear. If u(0) = infinity, then IV would be infinity, no?
    Maybe u(t) is a step function at 0? It is not a generalized function?

  • @serenasavage9842
    @serenasavage9842 3 месяца назад

    For final value theorem, how does 1/s+2 = 0 if s=0? I don’t understand what I’m missing

  • @akshaymatsagar1710
    @akshaymatsagar1710 4 года назад +1

    sir please complete the paylist .............we r waiting for further lectres

  • @shreyashagrawal2264
    @shreyashagrawal2264 3 года назад +1

    If we do Inverse Laplace Transform of F(s) = 1/(s+2) then it will give us f(t) = e^-2t and therefore f(t) violates the condition 1 i.e. f(t) = 0, t

    • @ahasnainkhan9622
      @ahasnainkhan9622 3 года назад

      f(t)=e^-2t.u(t) for F(s)=1/(s+1) not just e^-2t, hope answered your question.

  • @-DanishShafi
    @-DanishShafi 2 года назад

    There is a mistake in the initial value in the first example.
    It's answer is 0 not 1

  • @Muvva_raj
    @Muvva_raj 7 месяцев назад

    In first example e power zero is one ....but side of that we have u(0) whole will become zero no?

  • @sushrutmdhakate9874
    @sushrutmdhakate9874 2 года назад

    If final value theorem is not apllicable , then in all cases is that unbounded ?

  • @javaandroid6964
    @javaandroid6964 4 года назад +1

    Explain more

  • @albertdot5704
    @albertdot5704 Год назад

    If system is marginal stable, will final value theorem applicable,??

  • @talhafaraz6510
    @talhafaraz6510 3 года назад

    If any one have the lab report on this topic please share with me as soon as possible

  • @dungaajay6085
    @dungaajay6085 4 года назад +1

    u(t) is not defined at 0 right..then how e^0.u(0) = 1?please explain

    • @johnaime213
      @johnaime213 4 года назад +4

      that is why they use 0+, meaning slightly after 0.

  • @syedismail1849
    @syedismail1849 2 года назад

    🔥🔥🔥🔥🔥

  • @waytowardspeace-fv9mx
    @waytowardspeace-fv9mx 4 года назад +1

    Make video fast...

  • @GatreddiMohith
    @GatreddiMohith Год назад

    😂

  • @rahulguptha3131
    @rahulguptha3131 4 года назад +1

    Nice video thank you we need more videos like this