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Nice explanation.😀
I appreciate you watching! 🙏🥰💕✅Thanks for the feedback! 💯💕🥰✅
Nice ! You have published this type of exercise several times on your channel but there is a programmable algorithm that solves them all! You implement this algorithm yourself during your correction!
I will check it out
(a - b)^2 - ( b +1/2)^2 = 31/4(2 a - 2 b)^2 - (2 b+1)^2 = 31(2 a+1) (2 a-4 b-1) = 312 a+1 can be 1,-1,31,-31a = 0 , - 1 , 15 , - 16b = (a^2 - 8)/(2 a+1)b = - 8 , 7 , 7 , - 8Hence solutions are (0,-8) (-1,7) (15,7) (-16,-8)
Awesome 😎💯😎 approach
Where is it said that the solutions should be from Z?
Nice explanation.😀
I appreciate you watching! 🙏🥰💕✅Thanks for the feedback! 💯💕🥰✅
Nice ! You have published this type of exercise several times on your channel but there is a programmable algorithm that solves them all! You implement this algorithm yourself during your correction!
I will check it out
(a - b)^2 - ( b +1/2)^2 = 31/4
(2 a - 2 b)^2 - (2 b+1)^2 = 31
(2 a+1) (2 a-4 b-1) = 31
2 a+1 can be 1,-1,31,-31
a = 0 , - 1 , 15 , - 16
b = (a^2 - 8)/(2 a+1)
b = - 8 , 7 , 7 , - 8
Hence solutions are
(0,-8) (-1,7) (15,7) (-16,-8)
Awesome 😎💯😎 approach
Where is it said that the solutions should be from Z?