@@nathanc6516 Yeah, I should have expressed 'a' as 5b/7b-6. Because the solutions are positive integers we know that 5b/7b-6 is at least 1. So set >/= to one and multiply bs by 7b-6 to obtain the inequality . . . 5b >/= 7b-6 . . . then putting the b's on one side . . . 6 >/= 2b . . . 3 >/= b . . . same as b
Isolate a so that a = -5b/(6 - 7b)
Since a, b, are + integers, a = -5b/(6 - 7b) >/= 1
Then -5b 2b = 6 . . . => b
That doesn't make sense to me. I isolated a as 5b/7b-6. Not sure where you got those negative signs, also hard to follow what you did there.
@@nathanc6516 Yeah, I should have expressed 'a' as 5b/7b-6. Because the solutions are positive integers we know that 5b/7b-6 is at least 1. So set >/= to one and multiply bs by 7b-6 to obtain the inequality . . . 5b >/= 7b-6 . . . then putting the b's on one side . . . 6 >/= 2b . . . 3 >/= b . . . same as b
Very nice! ❤
Please watch first 2 minutes carefully and pause the video when needed, I hope you understand ❤
@@SALogics Noted, thanks