Number Theory | Strategies for Solving Linear Congruence

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  • Опубликовано: 21 дек 2024

Комментарии • 24

  • @kevinzurita9907
    @kevinzurita9907 4 года назад +6

    THis man is the GOAT

  • @PunmasterSTP
    @PunmasterSTP 3 года назад +3

    Congruent? More like con-great! Thanks again for making all of these wonderful videos and uploading them to enlighten us.

  • @georgesadler7830
    @georgesadler7830 3 года назад +2

    Professor Penn, thank you for showing the Strategies for Solving Linear Congruence.

  • @MarcusSt0ne
    @MarcusSt0ne 2 года назад +2

    This finally makes sense now after watching this. Thank you!

  • @muneerahammed4114
    @muneerahammed4114 4 года назад +2

    How can we say that result in 3:22

  • @IODell
    @IODell 3 года назад

    Always interesting. Thanks for posting.

  • @yongnianguan4273
    @yongnianguan4273 3 года назад +2

    Hello your video is very easy to understand. I am confusing about what is the symbol you write after write “sol”?

    • @paulconnor1040
      @paulconnor1040 3 года назад

      The letter 'n', underlined and written as a superscript. It's a way of shortening words on paper. Can't reproduce here, but Solution becomes Soln, Definition can be written Defn, Abbreviation as Abbrevn.

  • @MetalNeo91
    @MetalNeo91 5 лет назад +3

    nice, what a good video.

    • @MetalNeo91
      @MetalNeo91 5 лет назад +1

      Hello, i dont know if you have the time but i've a question about Euler theorem.
      Let say you want to find phi(26), how do you do that ? without calculator.
      I dont understand how most teacher calculate phi so fast. (2-1)(13-1) = 12 We says that 2 divide 13 integers between 1 and 26, where does 13 come from ?
      I understand fermat little theorem but euler theorem..

    • @MetalNeo91
      @MetalNeo91 5 лет назад +1

      I've find the answer somewhere, you have to divide 26 by 2 and once the rest is equal to 0 we divide the quotient by 2 redo til the rest is equal to 1.
      26 = 2x13 + 0

    • @MetalNeo91
      @MetalNeo91 5 лет назад +1

      I still dont get it i can't calculate phi(72) !!!

    • @MetalNeo91
      @MetalNeo91 5 лет назад +2

      Alright i found the solution, we have to split 72 in primes 72 = 2^3*3^2 then phi(72)=72(1-1/2)(1-1/3)=24 easy clap ^^

  • @vika0u0
    @vika0u0 Год назад

    why are the solutions mod 32 instead of mod 8 like the previous step?

    • @TheOiseau
      @TheOiseau Год назад

      The solution is 4 (mod 8), so anything of the form 4 + 8k will work.
      We originally wanted to solve in mod 32, so any value of k is fine as long as it yields a number between 0 and 31, so that's the final list of solutions: 4, 12, 20, 28.

  • @snipergranola6359
    @snipergranola6359 4 года назад +1

    Amazing

  • @dwightd3659
    @dwightd3659 5 лет назад +1

    Why did you got back to mod(32)?

    • @MichaelPennMath
      @MichaelPennMath  5 лет назад +4

      Because our original goal was to solve a congruence modulo 32. I guess this isn't strictly necessary, but it is customary to exhibit your solution in terms of the original congruence.

  • @anantshelgaonkar3950
    @anantshelgaonkar3950 Год назад

    Sorry sir,but i understood partially.actually i got stuck at how you take 12 mod 8 and then divide it to 4 mod 8.please guide us.

    • @MichaelPennMath
      @MichaelPennMath  Год назад

      12 is 4 larger than 8 so the remainder after dividing is 4, therefore 4 mod 8.
      -Stephanie
      MP Editor

    • @anantshelgaonkar3950
      @anantshelgaonkar3950 Год назад

      @@MichaelPennMath thanks for replying me very fastly sir.I am from India and after going through lots of videos now i am able to understand the concept by you.may i know from which country and region you belong to?

  • @hazzard77
    @hazzard77 4 года назад

    i hate when they do a trial-and-error guess for the multiplicate inverse. i see it in every modulo video and it's stupid.

    • @MichaelPennMath
      @MichaelPennMath  4 года назад +8

      I hated this as a student as well! It is so much more efficient to guess and check modular inverse for "small" n rather than go through the trouble of doing the Extended Euclidean Algorithm. Here is a video where I highlight the guess and check method along with the long method: ruclips.net/video/uPFh9_nLw1c/видео.html.
      Also, lots of research level mathematics is done via guess and check. The checking just involving writing a careful proof.

  • @evanthechong2167
    @evanthechong2167 Год назад +1

    Bro this is one of THE WORST math tutorials ever, going over concepts too fast, bare explanation, it's like a recap video rather than a tutorial.