Static equilibrium on an inclined plane (statics)
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- Опубликовано: 27 авг 2024
- This is a simple problem showing how to calculate the mass of an object that is suspended from a cord and is held in place (static equilibrium) by another object of known mass that rests on an inclined plane.
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I've been working on a similar problem. Not only are you the only person to explain how to work out the second weight but also ignore friction and keep it static. Thank you
I'm glad I could help.😊
Thank you oh my God ...been stuck on this question for hours, not knowing how to calculate mass. Thank you from South Africa 🇿🇦
You're very welcome. I'm glad it could help.
@@jlbenson in case where the other mass is not given. How do you calculate? what do multiply with? At the end.
@@leratoshasha1224 if you have been given that angle write down the value of the sin of that angle.
What does frictionless pulley mean
Great video. I've been searching how to solve this problem and this is the only video I can find on RUclips explaining how to solve for the mass of the second block. Very helpful video for a specific incline plane problem.
Thanks very much for the comment. I'm really glad I could help. I plan to post some more videos, but I have been dealing with some health problems that make it hard for me to write.
Treat the 3 blocks on the incline as one.
Hello, how about you have 4 blocks, 1st block is 3kg, 2nd block is 8kg and 3rd block is 5kg, what will be the mass of the fourth block hanging down?
Thank you really helpful
I'm glad I could help.🙂
hi, thanks for this video. I have a question that asks for the mass (m) that will begin to move the 100kg (M) up the slope, can you help?
with a 0.2 coefficient of friction between M and the slope
Any mass m greater than the equilibrium mass computed in this example will do it? Let me know if this helps.
Post the entire question and I will try to help you out.
Thanks a lot !
But why is the tension the same though? :(
We assume the string has no mass and does not stretch or rub against the pulley. This a common assumption for problems like this. If you assume friction between the string and pulley, then there is a different tension in the two parts on either side of the pulley.
@@jlbenson Alright thanks a lot
Because the pulley is assumed to have no mass so the tension remains constant throughout.
as easy as pie
yep
Looks like he can do math but can't write the letter m properly!!!
You're probably too young to remember it, but there used to be a type of writing called "cursive"; that's a cursive "m." It has always been easier to write for me and helps me distinguish between an "n" and an "r". I'm from the stone age.