Dislocation interaction leading to strain hardening I

Поделиться
HTML-код
  • Опубликовано: 2 авг 2024
  • Dislocation interaction leading to strain hardening I
  • НаукаНаука

Комментарии • 51

  • @MrVat7
    @MrVat7 5 лет назад +82

    Somebody give this professor a Nobel Prize

    • @mistervoldemort7540
      @mistervoldemort7540 5 лет назад +3

      agreed

    • @sanathkavatooru
      @sanathkavatooru 4 года назад +6

      Really!! He's explaining wonderful

    • @vaibhavvibhor8482
      @vaibhavvibhor8482 4 года назад +8

      I have attended his classes and he is one of the coolest professor ever! trust me, his class is a whole performance in itself

    • @garimaverma8345
      @garimaverma8345 4 года назад +3

      I was about to say that.!!! Great explanation

    • @simonblue56
      @simonblue56 4 года назад +1

      Totally agreed!

  • @pouraliakbar
    @pouraliakbar 2 года назад +4

    You deserve a prize for your teaching! Thanks for making the course so interesting.

  • @SandeepKumar-qv2fd
    @SandeepKumar-qv2fd 2 года назад +3

    Thank you so much sir 🙏🙏.
    You are God of material science for me. 🙏🙏

  • @shahidnabi010
    @shahidnabi010 Год назад

    I was always confused about this topic but this video cleared all my doubts

  • @KrishnaSridharan
    @KrishnaSridharan 2 года назад +1

    Very nicely explained. This is what we call teaching 🙂

  • @spyfromsparta
    @spyfromsparta 4 года назад +7

    Other Sleep inducing lullaby NPTEL Professors should learn from him, on how to make a course more interesting.

  • @worldrecordloading4362
    @worldrecordloading4362 3 года назад +2

    Awesome 🤩... You are genius... Make things very simple.... Thank you for helping students 🤗

  • @AbuDujana692
    @AbuDujana692 8 месяцев назад

    Sir, thanking you for awosome lectures....the content, logical sequence and precise presentation❤❤❤

  • @krishnakanttiwari2775
    @krishnakanttiwari2775 3 года назад

    Clear like anything 🥰🥰🥰🥰

  • @Jehosafath
    @Jehosafath 2 года назад

    Could you please recommend any literature for bcc materials?

  • @saurav1916
    @saurav1916 2 года назад

    sir, are we talking about mixed dislocations here because burgers vectors b1 and b2 are not perpendicular to the respective dislocation line in respective planes?

    • @introductiontomaterialsscience
      @introductiontomaterialsscience  2 года назад

      Yes, before interaction the two dislocations are mixed but glissile (able to move on their slip plane). After combination, the resulting dislocation is edge but sessile (unable to move on its slip plane, because the plane is not a favourable slip plane, which in turn is because the CRSS on this plane is very high.)

  • @knvcsg1839
    @knvcsg1839 2 года назад

    Why the hell didn't I start watching them at the starting itself?

  • @Shreejigovindhari
    @Shreejigovindhari 4 года назад

    In figure at 6:50 min, can we choose origin twice in drawing the Miller planes ???

    • @introductiontomaterialsscience
      @introductiontomaterialsscience  4 года назад +3

      Yes, you are permitted to shift the origin at any convenient location. However, the orientation of the axes should remain the same.

    • @Shreejigovindhari
      @Shreejigovindhari 4 года назад

      @@introductiontomaterialsscience thank you sir

  • @siddharthjena2189
    @siddharthjena2189 2 года назад +1

    17:28 Sir how the slip plane of resulting dislocation is (001)?

    • @rajeshprasad101
      @rajeshprasad101 2 года назад

      As suggested, you can apply the Weiss Zone law to get this: ruclips.net/video/gq6piKyyAQo/видео.html.

    • @ramvilashsingh1446
      @ramvilashsingh1446 2 года назад

      ruclips.net/video/gq6piKyyAQo/видео.html
      Go through this video

  • @vishalmishra9138
    @vishalmishra9138 2 года назад

    17:27 ,how the resulting plane is (001)?

    • @ramvilashsingh1446
      @ramvilashsingh1446 2 года назад

      ruclips.net/video/gq6piKyyAQo/видео.html
      Go through this video

  • @vishnusuresh168
    @vishnusuresh168 4 года назад

    Sir, small doubt. The family of 111 plane is in the shape of a triangle, then how to do we image it as two rectangular planes in at 8:31

    • @naturespeaks2023
      @naturespeaks2023 4 года назад +1

      Plane is infinite in all directions. It looks like a rectangle when we draw it within unit cell.

    • @introductiontomaterialsscience
      @introductiontomaterialsscience  4 года назад +1

      Vishnu Shukla has explained it correctly.

    • @vishnusuresh168
      @vishnusuresh168 4 года назад

      @@naturespeaks2023 Thank you so much for the replay. So do we have discontinuity from one unit cell to the another as we move along the crystal

    • @vishnusuresh168
      @vishnusuresh168 4 года назад

      @@introductiontomaterialsscience sir thank you so much for the replay, So do we have discontinuity from one unit cell to the another as we move along the crystal.

    • @introductiontomaterialsscience
      @introductiontomaterialsscience  4 года назад +1

      @@vishnusuresh168 No discontinuity. The planes are continuous across the unit cell. Having said that, really there are only discrete atoms. But we are assuming a plane to pass through the centres of these atoms. This assumed plane is continuous across the unit cells.

  • @sandeshrisal4719
    @sandeshrisal4719 4 года назад

    How are two vectors [110] and [1 0 -1] parallel???

    • @rajeshprasad101
      @rajeshprasad101 4 года назад +4

      [110] and [10-1] are not parallel. Did i say so?

    • @jvikash88
      @jvikash88 3 года назад

      @@rajeshprasad101 sir, the two burger vectors in (-1 1 1) plane and (1 -1 1) plane are 1/2[0 -1 1] and 1/2[1 0 -1] which have been assumed to be parallel to the intersection line of the two planes [1 1 0]. So [0 -1 1] , [1 0 -1] and [110] should be parallel but they are not. Could you explain this, sir?

    • @younesmoustiri9168
      @younesmoustiri9168 3 года назад +2

      @@jvikash88 I'm pretty sure he said that the dislocation line is parallel to the [110] plane and not the burgers vectors that he drew

    • @jvikash88
      @jvikash88 3 года назад +1

      @@younesmoustiri9168 Yes Younes, it’s the dislocation line not the burger’s vector. Thanks for pointing that out.

  • @priyanshusinha1209
    @priyanshusinha1209 4 года назад +1

    Sir, I am unable to understand the figure which you have drawn after cubic figure?? Can u please help sir...

    • @rajeshprasadlectures
      @rajeshprasadlectures 4 года назад

      I have drawn two planes in the cubic unit cell. Then in the next drawing, I am showing the same two planes without the unit cell.

  • @mrKumar-mo5ch
    @mrKumar-mo5ch 5 лет назад +2

    17:34 how (001) plane come I found u=v=w=0

    • @ravitejavelpula1305
      @ravitejavelpula1305 Год назад

      BRO,DID U GET THE ANSWER ,I AM ALSO GETTING (000) PLANE ONLY???PLS HELP ME I WAS STUCK IN IT
      IF WE THINK THEORETICALLY THEN IT IS CORRECT,BUT HOW CAN WE PROVE MATHEMATICALLY??

  • @adityapratapsingh7382
    @adityapratapsingh7382 3 года назад +1

    Thank you Sir, I have studied material science seriously for the first time after my graduation. In this video I am unable to understand how to decide what should be the Burgers vector, please help! or anyone else if willing to help. ( I have revised previous videos already)

    • @adityapratapsingh7382
      @adityapratapsingh7382 3 года назад

      Also, what would happen if we take b1= 1/2[0 -1 1] and b2=1/2[ 1 -1 0] in the very first step prior to forming of sessile dislocation? Please reply so that I can move forward in this course.

    • @jayakrishnaadapa8842
      @jayakrishnaadapa8842 2 года назад +1

      Please refer to weiss zone law video

  • @mohammedsofian5927
    @mohammedsofian5927 4 года назад +1

    jero