RACH Procedure in LTE | RACH failure reason | Contention and Non-Contention Based RACH क्या होता है

[@er.jeetookuthar9462]

jabrdast shandar

[@WirelessSchool]

Thank you

[@pratikkumar1568]

one of the best explanation of RACH procedure.Thank you sir.

[@WirelessSchool]

At your service guys.keep watching our videos 🤞🏻

[@mdabdulaziz5476]

Great effort and very nice explanation

[@WirelessSchool]

Thank you !! Keep watching

[@girajashankar1932]

Good learning

[@WirelessSchool]

Thanks for visiting

[@shaikyaseen3210]

Great efforts sirji, very much thankful

[@WirelessSchool]

Thanks Yaseen❤❤

[@pradipdalai02]

well explanation...👍

[@WirelessSchool]

Thank you 😃

[@manugautam8648]

Excellent explaination

[@WirelessSchool]

Glad it was helpful!

[@SuperAkshaymalik]

Best explanation bhai , mast hai bhai

[@WirelessSchool]

Thank you😍

[@kundansingh-gq4vh]

very good video.nice explaination sir..

[@WirelessSchool]

Thanks Kundan , Keep watching 💕

[@surajpratapsaroj1690]

Salute to u sir

[@surajpratapsaroj1690]

Nice Sir

[@shyamsinghpal3755]

Well explained 👏

[@WirelessSchool]

Thanks Shyam

[@sonalikitchenentertainment3940]

Nice video

[@WirelessSchool]

Thanks sonali

[@simranjitsingh4935]

8:13 Sir, 8 bytes ko agar bits mein kare ge toh 8x8 =64 bits ho gye .

[@WirelessSchool]

Hi Simranjit
My bad.. If MSG3 Size is greater than 6bytes=48bit then GrpB will be selected.
Thanks !!

[@mohdshahnawazakhtar1025]

😊

[@balkrishna769]

Very nice I know video was lengthy but pls can you pls provide more info about other prach parameters.

[@SaeedRahman786]

Really useful ...Can you please make a video on CRC?

[@Rahul-li9xb]

Sir on what bases or parameters endb select any 1 UE out of 3?

[@WirelessSchool]

Hi Rahul
Generally eNB follows FCFS(first come first serve )

[@manugautam8648]

Please increase the text font size

[@NitinKumar-wi2px]

8:17 time stamp.. wrong information 1 byte in 8 bit not 6 bit.. Please rectify in video

[@WirelessSchool]

Corrected- Thanks for pointing

[@VipinKumar-dv7hy]

It should be 8*8=64 bits to convert bytes..also you said preamble format depends on msg3 but we use preamble in msg1 then how we can know msg3 before msg1?

[@WirelessSchool]

Hi Vipin
Yess Correct .8byte=64bits..I tried to explain 48bits out of 64.
Before sending MSG1, UE has some data in its buffer to be sent out.Based on data size in buffer it will decide.
I hope this answers your question.

[@RajKumar-wr5ud]

@@WirelessSchool BECAUSE MSG1 IS INITIATED TO GET ULGRANT FOR MSG3 WHICH STORED IN BUFFER .TECHNICALLY MSG3 WAS MSG1@TIME OF DOWNLINK SYNCHRONIZATION COMPLETE

[@indramani8888]

bro it should be 8*8=64 bits not 48. and how msg3 size is a concern for RA Pramble , coz msg 3 comes after msg 1 and prambles going to be used in msg1 only.

[@WirelessSchool]

UE checks buffer size before sending RACH request

[@WirelessSchool]

Thanks for pointing out mistake-Corrected same in video

[@girajashankar1932]

Excellent explaination

[@WirelessSchool]

Glad it was helpful!