Sir aap jese teacher sare subjects k mil jaye RUclips PE to selection pka ho skta h....❤️❤️ Sir gs k liye koi aap jesa teacher leke aaoo plzz RUclips PE..
I'm watching this channel in 2024 for ssc cgl. after searching so much for a perfect maths class i was recommended sir's channel and from that day on i never looked back.
1:44 intro ( number system ) 8:54 face/place value of number 14:00 classification of numbers 1:07:50 even- odd 1:29:19 prime no. 2:40:00 perfect no. 2:42:50 digital sum 3:38:41 perfect square 4:08:38 DIVISIBLILITY rule 5:55:05 combined divisiblity 7:17:15 recuring decimal ( bar ) 8:27:48 bar bracket 8:43:50 unit digit
5:15:20 Respected sir, If we could take 6 and 7 as C & E's place respectively, then the no will be 43657 (a,b,c,d,e), here, a=4, which also satisfy the Que. According to que., all arrangements are 76453, 73654, 37654 & 43657. Hence, the value of a is 7, 3 and 4.
Important points. 2:43:00 Digital Sum 3:10:10 Baby digital sum(not that important) 3:23:23 dark/deep comment of Abhishek Kumar 😂 3:39:30 perfect square 4:09:00 divisibility 5:12:10 important questions 5:55:00 Combined Divisibility 6:54:00 making of divisibility rule 7:15:00 recurring decimal & bar 8:44:00 unit digits
5:28 hrs ans is wrong 54k31m82=1 k-3 1-m 6=5+k-m (from left to right) possible value for k-m 6 and 17...17 not possible if we take k-m=6 then k=9 m=3 so maximum possible value of k+m=9+3=12
Today I completed my chapter.. Pehle numbers system se bht dar laga karta tha. Lekin ab khud me cofidence aa gaya hai.. I hope kabhi sir se milne ka mauka mile. Thanks Sir
Job lagne ke baad sir sabse pahle mai aapse miloonga ❤️❤️❤️❤️❤️❤️❤️❤️ You are my heart 💓 beat ashirwaad dijiye sir ki jald मिलूं बहुत खुशनसीब हूं की आपका क्लास देखने का मौका मिला ।
5:29:10 Vala swal ekdum shi h or isme k=4 and m=9 h... So option d is correct... Ap check kr skte h... Value put krke jo number aayega vo 11 se divide hoga...
5:25:00 If a number 54k31m82 is divisible by 11, what will be the maximum value of (m-k)? In this question solution, sum= m-k-11.But I think it will be m-k-5 Can anyone explain this question???
2:14:03 day one 3:38:59 day two 5:39:49 day three 7:45:36 day four 10:03:48 day five 11:04:02 day six completed But remainder theroem to hai hi nhi isme 😢
@@JatinSharma-xw6se of course, but you need to cover more topics which are not included in this video,, such as remainder theorem, factors, successive division.
either b or c must be positive means one of them is positive and rest 2 are negative so I think answer should be option A. Please clear the doubt.57:00
Abhinay Sir' means: Baadshaah of mathematics Hats off to you and your dedication towards our career You are very great and can not be compared with anybody
5:15:38 sir 4 bhi ho sakta hai answer because a b c d e 6 5 7 6+7+5=18 hai 3 se divide hoga Fir agar b ko 3 lenge to 36 hoga 4 se bhi divide hoga Ab bacha number 4 to answer 4 bhi ho sakta hai
5:25:00 Question wouldn't be corrected. It's (m+k) ✓ Number = 54k31m82 Calculation: ⇒ (5 + k + 1 + 8) - (4 + 3 + m + 2) = (14 + k - 9 - m) = k - m + 5 ⇒ k - m = -5 take maximum value of m = 9 ⇒ k = -5 + 9 = 4 ∴ m + k = 4 + 9 = 13
1:59:00 wronggggg,,statement 1 wrong h cause when we take 6 it has two factors 2 and 3 and same with no like 12,18 and for 5,7 it is 35 and 70 like no when we subtract factors of 2,3,5,7 we eventually subtract 1 no twice which leads to wrong no of prime Hope u understand
My dear respected sir I STARTED WITH A2Z bach left in between because i can't manage my both Graduation and Math Simultaneously Getting depressed that i can't manage both together
5:28:57 Question sahi hai , Sir aapne wrong add kiya hai jo diffrence aaya hai. m-k-5 aayega . Tab iske hisab se , ya to 0 ya to 11 ka multiple aana chahiye. So possible values, (6,1), (7,2), (8,3),( 9,4) hoga. K+ m chahiye, 1 + 6= 7 2 + 7 = 9 3 + 8 =11 4 + 9 = 13 Answer (B) and (D) sahi hai.
1:25:14 The solution is wrong. Correct Solution: For (n + 1)(n + 30) to be always even, at l east one factor must be even. *Positive n:* If n is even: n + 30 is even. If n is odd: n + 1 is even. *Negative n:* If n is even: n + 30 is even. If n is odd: n + 1 is even. Therefore, (n + 1)(n + 30) is always even for any integer n. Answer: (iv) NOT
Sir aap students hit me hmesha aage rhte h Sir aapko ek bdi prblm ki or dhyan dilana chahta hu ki aajkal phone screen ke karan eyes prblm bahut hone lgi h to apnn sbko ek compaign chlana hoga sir kyuki ye private company h to ek bar me hi bat man lege plzz ek bar aap is important matter ki taraf dhyan dijiye Plzz sir 🙏🙏🙏 Thnxx sir❤️
किसी संख्या को 11 से विभाजित करने के लिए, 11 के विभाज्यता नियम का उपयोग करते हुए, उस संख्या के अंकों के स्थानों पर वैकल्पिक जोड़ (alternate sum) की गणना की जाती है। हमारी संख्या है: 54k31m82 विषम और सम स्थानों पर स्थित अंकों का योग निकालते हैं: विषम स्थान (1st, 3rd, 5th, 7th, 9th स्थान): \( 5 + k + 3 + m + 2 \) सम स्थान (2nd, 4th, 6th, 8th स्थान): \( 4 + 3 + 1 + 8 \) विषम स्थान का योग: \[ 5 + k + 3 + m + 2 = 10 + k + m \] सम स्थान का योग: \[ 4 + 3 + 1 + 8 = 16 \] अंतर निकालते हैं: \[ (10 + k + m) - 16 = k + m - 6 \] संख्या 11 से विभाज्य होने के लिए यह अंतर 11 का गुणज होना चाहिए। अर्थात, \( k + m - 6 \) 11 का गुणज (multiple) होना चाहिए। हम इसे 11 के सबसे छोटे गुणज (0, 11, -11, ...) के रूप में लिख सकते हैं: \[ k + m - 6 = 0 \] \[ k + m - 6 = 11 \] \[ k + m - 6 = -11 \] ... दिए गए विकल्पों को देखते हैं: A) 10 B) 11 C) 12 D) 13 हम विकल्पों को इस प्रकार समझते हैं: \[ k + m - 6 = 11 \] \[ k + m = 17 \] इसी तरह, \( k + m - 6 \) का मान 11 है, तो: \[ k + m = 17 \] दिए गए विकल्पों में से 17 किसी भी विकल्प में नहीं है, इसलिए यहाँ कोई स्पष्ट त्रुटि हो सकती है। यदि ऐसा हो तो परीक्षा या प्रतियोगिता में हमें परीक्षक या संबंधित अधिकारी से संपर्क करना चाहिए। किसी भी विकल्प का सही उत्तर नहीं होना चाहिए, क्योंकि \( k + m = 6 \) सही उत्तर है, जो विकल्पों में मौजूद नहीं है।
The question in the image is: "If \( a + b + c \) is even and \( a \), \( b \), and \( c \) are integers, then which of the following statements is true? (a) Either \( a \) or \( b \) must be even number. (b) At most one of them is even number. (c) At least one of them is even number. (d) At most one of them is odd number." The correct answer is: (c) At least one of them is even number. ### Explanation: For the sum \( a + b + c \) to be even, the sum of the parities (odd/even nature) of \( a \), \( b \), and \( c \) must result in an even number. The possible combinations for \( a \), \( b \), and \( c \) are: - \( a \), \( b \), and \( c \) are all even. - Two are even, and one is odd. - One is even, and two are odd. If all three were odd, the sum would be odd, which contradicts the given condition that \( a + b + c \) is even. Therefore, at least one of \( a \), \( b \), and \( c \) must be even.
1:20:00 either a or b must be even which means that we have 1 even no. and 2 are odd no. So sum of two odd no. are even and sum of two even are even. Option a is correct. if a is even no. even + odd + odd = even + even = even [Sum of two odd no. are even]. Is I am right?
at 00:57:00 at most two negative means we can also consider the case where we are taking only one negative in that condition option B is also not satisfying.
@brijendrarajawat bhai maine school me kabhi maths nahi padhi dhang se class 10 th me fail bhi hua maths me par best of five ki wajah se pass hua 11th me commerce le li aur 87%se pass kari aisa nhi ki maths se dar lagta hai bas jab padhna chahiye tha tab man nhi hua padhne ka, par bhai ab bahot dikkatein aa gyi hain achanak se ab mai college me hu second year ssc clear krna chahta hu par sach batau toh 8th class ki maths karne me bhi atak jaunga toh bhai yea poochna tha ki pahle basics clear karu 8-12th class tk ke ya direct ssc ka syllabus padhne lagu chapter wise
Thanks so......much sir for your such unique hard work for us. Mai kanhaji se yahi magungi ki vo aapko hmsha khush rakhe aur aapki saari wishes poori kare...😊
YES....Precious years of many aspirants have been wasted due to 2 years of corona and 5 years of lack of vacancies....for CGL 2023 age limit should be counted from 01/01/2022. Also Email this issue to your respective MPs to raise this issue in parliament....Write public grievances. Young People have next 5 golden years....but old candidates need to fight back hard. ALSO AGE LIMIT FOR PA SA SHOULD BE 30 YEARS AND NOT 27 YEARS...as 30000 posts are under 27 years. Modi Sarkar listens when u write emails in good number 👍
![BLACK BAG - Official Trailer [HD] - Only in Theaters March 14](http://i.ytimg.com/vi/Du0Xp8WX_7I/mqdefault.jpg)
Pdf & doubts - u can whatsap - 9971512230 & Join Telegram channel - t.me/abhinaymaths &
Pdf Telegram channel - t.me/abhinaymathspdfs
Sir aap jese teacher sare subjects k mil jaye RUclips PE to selection pka ho skta h....❤️❤️
Sir gs k liye koi aap jesa teacher leke aaoo plzz RUclips PE..
a fractional number is always a rational number, but a rational number may or may not be a fractional number🙏
U
Yes
Good video
Suggest any changes in comment
2:42:50 2nd lecture
4:8:40 3rd divisibility rule
5:45:30 new lecture combined divisibility
7:14:50 Simplification Pdf(part 3) Q.n. 34
8:42:10 unit digit Pdf (Part 3)
9:6:21 unit digit PDF(Part4)
Ye jo 2.0 ki individual class h unhe hi merge ki h kya
@@manjusoni3355 ha
@@astube2021 ok
Bhai isme remainder theorm ni krayi ky sir ne ?
@@vaibhavhasija485 uska mene main lecture se kr liya tha to wo whi mil jayega......playlist me dekh lo.....wase aage wo bhi hoga hi isi video me
I'm watching this channel in 2024 for ssc cgl. after searching so much for a perfect maths class i was recommended sir's channel and from that day on i never looked back.
Is it enough for number system ? It cover all types and topic in this chapter ?
Pls reply
हर टीचर ऐसी होनी चाहिए,,,, बच्चो का भविष्य बेहतर होगा,,,,AS
1:44 intro ( number system )
8:54 face/place value of number
14:00 classification of numbers
1:07:50 even- odd
1:29:19 prime no.
2:40:00 perfect no.
2:42:50 digital sum
3:38:41 perfect square
4:08:38 DIVISIBLILITY rule
5:55:05 combined divisiblity
7:17:15 recuring decimal ( bar )
8:27:48 bar bracket
8:43:50 unit digit
Is it complete number system
@@aamirdar4657did you get the answer ? Is it complete ?
5:15:20
Respected sir,
If we could take 6 and 7 as C & E's place respectively, then the no will be 43657 (a,b,c,d,e), here, a=4, which also satisfy the Que.
According to que., all arrangements are 76453, 73654, 37654 & 43657.
Hence, the value of a is 7, 3 and 4.
Yes bro
starting:1 august 2024
DECIMAL SYSTEM 4:26
FACE VALUE 7:59
PLACE VALUE 10:05
COMPLEX NUMBER 13:58
IMAGINARY NUMBER 16:48
Q1 ka c hoga 500 only
many clips are missing of perfect square (1:50:00), but teaching methodology is very good easy to understand for a begineer like me
Mtlb
Should I complete the number system from this video?
Ply reply
@@nousername1587 yes you can but basics of calculations is required
@@keshav3105 where is missing videos...
Bhai sara yahi pda denge to offline kon pdega bhai g
03:39:28 Perfect Square Number
04:08:39 Divisibility Rule(0-11)
05:54:43 Combined Divisibility Rule
सर क्यूब रूट का चिन्ह न दे कर स्क्वायर रूट का चिन्ह दिया और हल क्यूब रूट में करके दिखाया इस भूल।को।सुधार कर लें
3:39:24 = perfect square
4:08:56= divisibility
at 5:27:29 correct ans will be d K+M = 13 k=9, m=4
Important points.
2:43:00 Digital Sum
3:10:10 Baby digital sum(not that important)
3:23:23 dark/deep comment of Abhishek Kumar 😂
3:39:30 perfect square
4:09:00 divisibility
5:12:10 important questions
5:55:00 Combined Divisibility
6:54:00 making of divisibility rule
7:15:00 recurring decimal & bar
8:44:00 unit digits
Is it complete number system
@@aamirdar4657 no
Your A to z science batch is fruitful for me sir.. Thankyou sir..🙏
कामयाब होने के लिये करो मेहनत पर यकीन
क्यों किकिस्मत तो जुए में आजमाई जाती है।
0- 4:08:36 classification
4:08:38 - 7:14:52 divisibility
7:14:54 - 10:24:35 recurring decimals & unit digit questions
10:24:36 - 11:04:00 factorial
खड़े हो कड़ी मेहनत (Hard Work) करो संघर्ष (Struggle) करो लेकिन कभी हार मत मानो… (Never Give Up)☑️
वाह क्या बात बोली हमे तो पता ही नही था हमारे तो भाग्य ही जाग गए 🙏🏾🙏🏾🙏🏾🙏🏾🙏🏾
Excuse me Didi aap airforce ka notes banayi ho
Khada hua hai
2:43:00 Class 3) Digital Sum
4:09:00 Class 4) Divisibility
This teacher solves complex problems so easily that sometimes its a bounce ball for me. But still superb.
5:28 hrs ans is wrong
54k31m82=1 k-3 1-m 6=5+k-m (from left to right)
possible value for k-m 6 and 17...17 not possible
if we take k-m=6 then k=9 m=3 so maximum possible value of k+m=9+3=12
k-m = -5 then it is also divisible by 11, then the maximum value of K is 4 and m is 9 then K+m = 13
Sir your mother had the exact same case as mine. Got two surgeries two years ago. Hope she will be all good soon.
बहुत अच्छी क्लास रही गुरु जी सादर प्रणाम करता हूं 🙏🙏🙏🅿️✔️💯🌉🙏
Today I completed my chapter.. Pehle numbers system se bht dar laga karta tha. Lekin ab khud me cofidence aa gaya hai.. I hope kabhi sir se milne ka mauka mile. Thanks Sir
Bs ye ek video kaafi hai number system ke liye?
did u get to know?@@PoojaSharma-x1b
Job lagne ke baad sir sabse pahle mai aapse miloonga ❤️❤️❤️❤️❤️❤️❤️❤️
You are my heart 💓 beat
ashirwaad dijiye sir ki jald मिलूं
बहुत खुशनसीब हूं की आपका क्लास देखने का मौका मिला ।
Ho gaya apka selection
5:29:10 Vala swal ekdum shi h or isme k=4 and m=9 h... So option d is correct...
Ap check kr skte h... Value put krke jo number aayega vo 11 se divide hoga...
Is it all bro
11:04:02
Complete class done with 3 break ...(15×3=45mint.)
1.5x Speed with complete handwritten notes
💪💪
bro pse suggest that if it is sufficient about number system
@@SurajGns 70%complete
Because Kuch question nhi lagenge
Mene bhi questions laagae to thode questions fas rhe hai ab bhi
Konsa concept reh gaya hai
11:02:40 sir, yaha par 23 hoga,
So ans will be...29
Thank you so much sir for thus wonderful session 😊
5:25:00
If a number 54k31m82 is divisible by 11, what will be the maximum value of (m-k)?
In this question solution, sum= m-k-11.But I think it will be m-k-5
Can anyone explain this question???
Sir made a mistake there 5:25:00
Yes
K-m = -5
Take maximum value of m= 9
K-9=-5
K= -5+9 = 4
Maximum value of k+ m= 9+4=13
3:38:25
Not questions from here on
Divisibility rule 4:10:00
13 ka divisibility
Is it complete number system
2:14:03 day one
3:38:59 day two
5:39:49 day three
7:45:36 day four
10:03:48 day five
11:04:02 day six completed
But remainder theroem to hai hi nhi isme 😢
Is This Sufficient for CGl ??
@@JatinSharma-xw6se of course, but you need to cover more topics which are not included in this video,, such as remainder theorem, factors, successive division.
10:20:10 that motivates me
This shows that "Har kisi ka ek din aata h"❤❤❤😂😊😊🎉🎉
either b or c must be positive means one of them is positive and rest 2 are negative so I think answer should be option A.
Please clear the doubt.57:00
But there is no guarantee that a would be +ve so (a) is wrong
Abhinay Sir' means: Baadshaah of mathematics
Hats off to you and your dedication towards our career
You are very great and can not be compared with anybody
Aaditya Ranjan sir best 😂😂
Sab teachers best hi best hai
Thankyou sir a marvelous session.keeping the josh high sir
Divisibility rule 4:55:53
Thank you sir.. bhut kuch hai khna pr abhi padhne ki jrurt hai.... once again ty...
2:43:00 - Digital sum
4:08:40 - divisibility rule
Thank you for this initiative you have taken
5:15:38 sir 4 bhi ho sakta hai answer because
a b c d e
6 5 7
6+7+5=18 hai 3 se divide hoga
Fir agar b ko 3 lenge to 36 hoga 4 se bhi divide hoga
Ab bacha number 4 to answer 4 bhi ho sakta hai
Just amazing❤... Number system finished 😎
Is it complete number system
5:25:00
Question wouldn't be corrected. It's (m+k) ✓
Number = 54k31m82
Calculation:
⇒ (5 + k + 1 + 8) - (4 + 3 + m + 2) = (14 + k - 9 - m) = k - m + 5
⇒ k - m = -5
take maximum value of m = 9
⇒ k = -5 + 9 = 4
∴ m + k = 4 + 9 = 13
This class is amazing and i didn't felt boring even for a second.
Kudos to you and your way of teaching sir🙏🙏🙏🙏🙏🙏🙏🙏🙏
Is entire number system completed in this video . Is is enough for CGL ? Please reply
You are doing a great job sir by providing such valuable content for free. You are helping in laying the foundation of new educated India.
Divisiblity Rule Q : 4:55:53
1:59:00 wronggggg,,statement 1 wrong h cause when we take 6 it has two factors 2 and 3 and same with no like 12,18 and for 5,7 it is 35 and 70 like no when we subtract factors of 2,3,5,7 we eventually subtract 1 no twice which leads to wrong no of prime
Hope u understand
Old abhinay sir is Back now.
Ye ssc CGL ya ssc hai bhai
@@rauwwwwgyh ssc cgl
Students jutane ke liye bhaiya ....Nahi toh nahi aate...
@@biki1135 Abee gadhe vo padha rhe h vo tujhe ni dikh rha h.. Bs subscriber k chkkr me sab ni rehte h... Vo unki job h...
@@Explain247 Is it complete number system or not ?
5:29:20 difference will be m-k-5 ...option d ie 13 is correct
Very thankful for this wonderful class
11:04:02 please check again sir 89 is wrong, 29 is right 🙄
My dear respected sir
I STARTED WITH A2Z bach left in between because i can't manage my both Graduation and Math Simultaneously
Getting depressed that i can't manage both together
At 5:29:10 question is correct and the answer will be D -13 (9+4)
5:28:57 Question sahi hai ,
Sir aapne wrong add kiya hai jo diffrence aaya hai.
m-k-5 aayega .
Tab iske hisab se , ya to 0 ya to 11 ka multiple aana chahiye.
So possible values, (6,1), (7,2), (8,3),( 9,4) hoga.
K+ m chahiye,
1 + 6= 7
2 + 7 = 9
3 + 8 =11
4 + 9 = 13
Answer (B) and (D) sahi hai.
Correct answer is 12
@@RK-kk6nq how?
Anyone june 2024 wala😅
Present sir
😅😅
G
Yes
Yes
Most useful session for beginners 😊
Kuch aata bhi h 😮
Pro level class hai Didi
Sir ji 👏👏👏👏👏aj tak apka jaisa math 📐📊📚📐📊📚📐📊📚teacher nhi mile sir ap kash school🎒📚🎒📚🎒📚 me mile ho to mujhe
East or west abhinay sir is the best 🥰🥰🥰🥰🥰
sir ye vali video jo aap dal re hai .... bahut hi badiya bahut sahi hai ...
Namaskar 🙏 sir ji 🙏 nice class 👍👍👍👍👍👍👍👍
5:25:23 sum m-k-5 hoga
Then answer will be 11
Abhinay sir is rare teacher of maths its provide rate content
5:29:29 - option (d)13 will be correct 💯.
Thanks sir you are great 🙏.
Please upload algebra compiled video also 🙏
1:25:14 The solution is wrong.
Correct Solution:
For (n + 1)(n + 30) to be always even, at l east one factor must be even.
*Positive n:*
If n is even: n + 30 is even.
If n is odd: n + 1 is even.
*Negative n:*
If n is even: n + 30 is even.
If n is odd: n + 1 is even.
Therefore, (n + 1)(n + 30) is always even for any integer n.
Answer: (iv) NOT
Very good information delivered by you thank you very much
5:25 pe.... questions shii h......aapne glt kiya......
m-k + 5 hoga.....
m -k = -5
Tbb k = 9
m = 4
K+m = 13
yes
Kon kon March me Dek rha h 2024 😅
Hmm
Hmm
Aap kis standard me ho
😄
Yo
Sir aap students hit me hmesha aage rhte h
Sir aapko ek bdi prblm ki or dhyan dilana chahta hu ki aajkal phone screen ke karan eyes prblm bahut hone lgi h to apnn sbko ek compaign chlana hoga sir kyuki ye private company h to ek bar me hi bat man lege plzz ek bar aap is important matter ki taraf dhyan dijiye
Plzz sir 🙏🙏🙏
Thnxx sir❤️
love u sir , u r great person... come on earth no one knows ur value...
Every student knows the value of sir sir is great ☺️👍
@@pinspiresindia aa gyi life barbad krne ko reply krne ek ldki 😄😄😄🤣 swaha 🔥🔥🔥🔥
Kamal ka teacher hai app sir....❤️
Thank you sir .... 🙂 Hats off
1:51:06 sir 43+5+2=50 is correct but 41+7+2=50 is also correct then the question have 2 answer right 👍🏼
I'm from your foundation 6.0 batch
Nice session well done sir 👍👍👍
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किसी संख्या को 11 से विभाजित करने के लिए, 11 के विभाज्यता नियम का उपयोग करते हुए, उस संख्या के अंकों के स्थानों पर वैकल्पिक जोड़ (alternate sum) की गणना की जाती है।
हमारी संख्या है: 54k31m82
विषम और सम स्थानों पर स्थित अंकों का योग निकालते हैं:
विषम स्थान (1st, 3rd, 5th, 7th, 9th स्थान): \( 5 + k + 3 + m + 2 \)
सम स्थान (2nd, 4th, 6th, 8th स्थान): \( 4 + 3 + 1 + 8 \)
विषम स्थान का योग:
\[ 5 + k + 3 + m + 2 = 10 + k + m \]
सम स्थान का योग:
\[ 4 + 3 + 1 + 8 = 16 \]
अंतर निकालते हैं:
\[ (10 + k + m) - 16 = k + m - 6 \]
संख्या 11 से विभाज्य होने के लिए यह अंतर 11 का गुणज होना चाहिए।
अर्थात, \( k + m - 6 \) 11 का गुणज (multiple) होना चाहिए।
हम इसे 11 के सबसे छोटे गुणज (0, 11, -11, ...) के रूप में लिख सकते हैं:
\[ k + m - 6 = 0 \]
\[ k + m - 6 = 11 \]
\[ k + m - 6 = -11 \]
...
दिए गए विकल्पों को देखते हैं:
A) 10
B) 11
C) 12
D) 13
हम विकल्पों को इस प्रकार समझते हैं:
\[ k + m - 6 = 11 \]
\[ k + m = 17 \]
इसी तरह, \( k + m - 6 \) का मान 11 है, तो:
\[ k + m = 17 \]
दिए गए विकल्पों में से 17 किसी भी विकल्प में नहीं है, इसलिए यहाँ कोई स्पष्ट त्रुटि हो सकती है। यदि ऐसा हो तो परीक्षा या प्रतियोगिता में हमें परीक्षक या संबंधित अधिकारी से संपर्क करना चाहिए।
किसी भी विकल्प का सही उत्तर नहीं होना चाहिए, क्योंकि \( k + m = 6 \) सही उत्तर है, जो विकल्पों में मौजूद नहीं है।
Thankyou so much for this amazing fruitful session, we are lucky to have teacher like you jo itni easily maths smjhate hai 🙏
Same view on this video as you khushbu Singh
The question in the image is:
"If \( a + b + c \) is even and \( a \), \( b \), and \( c \) are integers, then which of the following statements is true?
(a) Either \( a \) or \( b \) must be even number.
(b) At most one of them is even number.
(c) At least one of them is even number.
(d) At most one of them is odd number."
The correct answer is:
(c) At least one of them is even number.
### Explanation:
For the sum \( a + b + c \) to be even, the sum of the parities (odd/even nature) of \( a \), \( b \), and \( c \) must result in an even number.
The possible combinations for \( a \), \( b \), and \( c \) are:
- \( a \), \( b \), and \( c \) are all even.
- Two are even, and one is odd.
- One is even, and two are odd.
If all three were odd, the sum would be odd, which contradicts the given condition that \( a + b + c \) is even.
Therefore, at least one of \( a \), \( b \), and \( c \) must be even.
Sir they way u have uploaded this marathon of this topic.. we request u to upload for every topic a mega marathon session
Is it complete number system
You are the best ❤️ , keep going sir we need more videos.
Thank you, I will share soon.
1:20:00 either a or b must be even which means that we have 1 even no. and 2 are odd no. So sum of two odd no. are even and sum of two even are even. Option a is correct.
if a is even no.
even + odd + odd = even + even = even [Sum of two odd no. are even].
Is I am right?
हौंसले के तरकश में कोशिश का वो तीर ज़िंदा रखो।
हार जाओ चाहे ज़िंदगी में सब कुछ
मगर फिर से जीतने की उम्मीद ज़िंदा रखो।
This video is a masterpiece.. Sir ji 🙏
Jalwa hai sir kaa 😂 😅 .What a wonderful Class in my Life . One of the best educator in India for math ......
Maths 🤚
The best class on number system ❤
U are Superman sir ❤️❤️ tremendous way you explained
5:28:30 m-k-5 hoga aur answer 13 hoga
Sir I m in class 7 and I learnt so much from this class ❤
9:24:00 Sir Unit digit of the product of all even number is 0 !
Exactly. ×10
Thanks so...much sir. i have no words for you🙏🙏🙏
at 00:57:00 at most two negative means we can also consider the case where we are taking only one negative in that condition option B is also not satisfying.
@brijendrarajawat bhai maine school me kabhi maths nahi padhi dhang se class 10 th me fail bhi hua maths me par best of five ki wajah se pass hua 11th me commerce le li aur 87%se pass kari aisa nhi ki maths se dar lagta hai bas jab padhna chahiye tha tab man nhi hua padhne ka, par bhai ab bahot dikkatein aa gyi hain achanak se ab mai college me hu second year ssc clear krna chahta hu par sach batau toh 8th class ki maths karne me bhi atak jaunga toh bhai yea poochna tha ki pahle basics clear karu 8-12th class tk ke ya direct ssc ka syllabus padhne lagu chapter wise
Amazing contant sir jiiii❤️❤️❤️❤️❤️❤️💯💯💯💯💯
Question at 5:15:00 has 3 options correct 7,3,and 4 with 4
43657
Pranam Gurudev🙏🙏🙏
Excellent sir...At last I have completely understod this topic
Thanks for uploading math lacture
Love from Rajasthan
One More rajasthan
Thanks so......much sir for your such unique hard work for us.
Mai kanhaji se yahi magungi ki vo aapko hmsha khush rakhe aur aapki saari wishes poori kare...😊
Sir i have a request.
Please give solved slides pdf of all these questions 🙏
Sir ye bahut acha h baaki ke topic bhi ese kr dijiyega ❤️❤️🤟
किसी की यादों में घुट-घुट कर मरने से अच्छा है, की आप अपनी ताकत को अपने लक्ष्य पर लगाओ और इतने सफल बन जाओ की एक दिन आपको छोड़ने वाले रोये👍👍❤️❤️🥰🥰🙏🙏🙏
YES....Precious years of many aspirants have been wasted due to 2 years of corona and 5 years of lack of vacancies....for CGL 2023 age limit should be counted from 01/01/2022.
Also Email this issue to your respective MPs to raise this issue in parliament....Write public grievances.
Young People have next 5 golden years....but old candidates need to fight back hard.
ALSO AGE LIMIT FOR PA SA SHOULD BE 30 YEARS AND NOT 27 YEARS...as 30000 posts are under 27 years.
Modi Sarkar listens when u write emails in good number 👍
Completed sir ✅ please upload part 2🙏
Iska part 2 nhi mila
@@thecompanion2961abhi bhi number system complete nhi hoe ha?
9:24:13 ka Ans 0 hoga .. 10 se multiply karte hi unit digit 0 aa jayega
Sir puri class ki pdf bhi dal Dana sir ... please 💝💝💝👉
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