Digital Butterworth and CHEBYSHEV filter

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  • Опубликовано: 9 ноя 2024

Комментарии • 29

  • @karimullanoorbasha7181
    @karimullanoorbasha7181 5 месяцев назад +1

    Good explained chesaru

  • @pabbathiaashrithashetti7892
    @pabbathiaashrithashetti7892 2 года назад +1

    Will you please explain how ur using the calcy for partial fractions and how are you applying it ?

  • @Sizzling_sahasra
    @Sizzling_sahasra 4 года назад

    Very nice Saleem, good presentation

  • @dilsecelebrities86
    @dilsecelebrities86 Год назад +1

    Hello i had a in 3rd butterworth u had used short foe partial fraction right i couldn't understand there y we got 0.5

  • @dilsecelebrities86
    @dilsecelebrities86 Год назад

    Bro starting lo ey topic ..aslu topic kuda kanipinchatla

  • @MBA93949
    @MBA93949 2 года назад

    Outstanding

  • @mekavijaybhaskar5897
    @mekavijaybhaskar5897 4 года назад +2

    Bro... I want design of iir filters from analog filters and analog and digital frequency transformation

  • @MBA93949
    @MBA93949 2 года назад

    ❤️❤️❤️❤️

  • @chandanat9970
    @chandanat9970 4 года назад

    Very good explanation

  • @rohitsoni8686
    @rohitsoni8686 3 года назад +1

    explanation "GOD" ho kya??? 😍

  • @tadepu-raghavendra
    @tadepu-raghavendra 4 года назад

    Can you explain A how came plsd

  • @saikiran3663
    @saikiran3663 3 года назад

    Can you explain the steps in 15:44 ...

  • @prabhutejavallepu5039
    @prabhutejavallepu5039 4 года назад +2

    A&B values u have taken wrong, i.e..,1/3=0.33 but u have taken 3.33

  • @swathiposani240
    @swathiposani240 4 года назад

    Dsp class cheppadi sir

  • @kaveri3463
    @kaveri3463 4 года назад

    So in impulse invariant technique there is no prewarping right!!

  • @sanskarvidyarthi9895
    @sanskarvidyarthi9895 3 года назад

    How are you getting the roots in the denominator at 13:20 and 17:40 ???

    • @syedsaleemfeedtheneedy9563
      @syedsaleemfeedtheneedy9563  3 года назад

      by using casio ---- ax2+bx+c=0

    • @pro1world573
      @pro1world573 3 года назад +1

      Click-> Mode->eqn 1-> degree 2->after entering values, you will get x1 and x2 then in x1(press shift and equal to=) to find imaginary part of x1 and repeat it for x2 you will get imaginary part.

  • @srksharma8199
    @srksharma8199 3 года назад

    22:03 how is that true?shouldn't we use the formula to calculate omega p?

    • @syedsaleemfeedtheneedy9563
      @syedsaleemfeedtheneedy9563  3 года назад

      Divide both numerator and denominator with 17265.4 to get H(Z) at 22:03

    • @srksharma8199
      @srksharma8199 3 года назад

      @@syedsaleemfeedtheneedy9563 I mean sir how is omega c = omega p?Is that a relation between omega c and omega p for high pass ?

    • @syedsaleemfeedtheneedy9563
      @syedsaleemfeedtheneedy9563  3 года назад

      @@srksharma8199 I did not get you will you please tell me about what you are asking Butterworth or Chebhyshev ?

    • @thelyricsguy3094
      @thelyricsguy3094 2 года назад

      same question sir?

  • @kaveri3463
    @kaveri3463 4 года назад

    👏