Dualsky v2 Linear Brake Mode Setup

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  • Опубликовано: 11 дек 2024

Комментарии • 3

  • @msun12000
    @msun12000 8 месяцев назад

    Surely s stationary prop would create MORE drag than a free-wheeling rotating prop for a plane.
    Also, having no proportional throttle action with the stick from zero to approx half way (in free-wheeling mode) doesn't sound so great. 🛩

    • @RCJim
      @RCJim  8 месяцев назад

      Have a look at the discussion thread that my link in the description goes to. Two very practical arguements: A helicopter descending with an auto-rotating rotor following engine failure is going to descend slower than one where the rotor has quit spinning. Secondly, an auto-gyro aircraft uses a free rotating rotor to provide lift. In both cases the auto-rotating blades are producing greater "drag" than ones that are stationary.

    • @msun12000
      @msun12000 8 месяцев назад

      @@RCJim I looked at that discussion thread thanks. There seems to be some confusion over the meaning of "drag" versus "lift" for an aerofoil be it a wing (rotary or fixed) or a propeller. A stalled surface surface will present far more drag than a flying one with laminar flow.
      So a stationary prop in flight is effectively in a stalled condition whereas the auto-rotating examples for the helicopter or autogyro present a flying surface producing "lift". I hope that sounds logical🙂