Beers Law

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  • Опубликовано: 11 дек 2024

Комментарии • 60

  • @ashapasha4528
    @ashapasha4528 8 лет назад +54

    This video literally made me understand the lab I already performed.

    • @Shani249
      @Shani249 8 лет назад

      same

    • @terrykyng5771
      @terrykyng5771 3 года назад

      You probably dont give a damn but does someone know of a method to log back into an instagram account?
      I was stupid forgot my password. I would love any assistance you can give me!

  • @iCantMakeMovies
    @iCantMakeMovies 9 лет назад +17

    I love how clearly you present the information! Really great job.

  • @ethankizziar9545
    @ethankizziar9545 8 лет назад +18

    Best explanation of Beer's law I have ever seen...thanks man you saved me

  • @chantellehollingsworthplow4695
    @chantellehollingsworthplow4695 6 лет назад +4

    Your video and explanation along with writing/drawings is a huge help. Thank you so much.

  • @aryashrestha6828
    @aryashrestha6828 3 года назад

    thank you for making me understand my entire internal assessment

  • @wayne02058
    @wayne02058 4 года назад +2

    I think you have made understanding beers law so simple, :)
    but a quick gripe I have is the background noise, I found it hard to pay attention.

  • @ozgurderince8727
    @ozgurderince8727 8 лет назад +15

    the use of calculator is harder than understanding Beer's Law.

    • @blackhawkX02
      @blackhawkX02 6 лет назад +1

      He lost me at 16:54 just because of that thing, I couldn't follow...my calculator is not even like the one he uses.

  • @zharaibrahimi3467
    @zharaibrahimi3467 6 лет назад +2

    Amazing video, saved me stressing from a 3 day stress.
    Just the background noise is annoying.

  • @plutoniumiscool
    @plutoniumiscool 2 года назад

    Would it be possible to calculate the concentration of a compound if i dont have a standard to compare with?

  • @luisvalenciaherencia7418
    @luisvalenciaherencia7418 3 года назад

    if I have an unknown substance in which I did a spectrophotometric scan and I obtain a wavelength in which it has its highest absorbance. Is it possible to find the concentration based on these data?

  • @joeychai1037
    @joeychai1037 10 лет назад +4

    This is very specific!!!

  • @marianadiaz7456
    @marianadiaz7456 9 лет назад +2

    what about the wavelength?

  • @rebecab.737
    @rebecab.737 5 лет назад +1

    REALLY helpful. Thanks a lot.

  • @nkouprisca
    @nkouprisca 5 лет назад

    Sir hello
    I have some questions about the lab report on spectrophotometric analysis of the percentage of cranberry juice in cranberry apple juice
    1)Using the entire set of percentages of pures cranberry juice in cranberry apple juice ,what is the overall averages, standard deviation and ranges of percentages of pure cranberry juice?
    Given concentration(%) and absorbance(A)
    5%=0.04
    10%=0.22
    15%=0.40
    20%=0.55
    25%=0.68
    30%=0.90
    2)if apple juice has a non zero absorbance at the lamda max,how would this affect your calculations in calculating the percent cranberry in cranberry apple?would you calculations report a percent cranberry that is too high or too low?

  • @seppevancampe2921
    @seppevancampe2921 4 года назад +1

    Thank you so much , i finnaly understand it
    Legend

  • @ameliaamezquita9100
    @ameliaamezquita9100 2 года назад

    hello, i just found this, but why do you do 2-log(%T)?

    • @chempatenaude
      @chempatenaude  2 года назад

      A Beer’s law plot is linear when Absorbance is plotted against concentration. Most devices today will display the absorbance value for you. But if you have a device which displays percent transmittance instead, that formula will convert your transmittance values into absorbance values for graphing.

  • @faizmohammad2417
    @faizmohammad2417 6 лет назад

    very nice lecture and illustrative explainations

  • @newyorker5010
    @newyorker5010 4 года назад

    Life savior 🙌🏻

  • @monaeldosoky4405
    @monaeldosoky4405 4 года назад

    Many thanks .very illustrative

  • @rodrigobaldeon8443
    @rodrigobaldeon8443 3 года назад

    Why is this here in my feed? Flashbacks of AP Chem 2021 FRQ #5 or 6

  • @SuperJhon360
    @SuperJhon360 2 года назад

    I have an unknown solution where my professor said the absorption is 0.85 and the path length is 1cm what is the consentration of the unknown solution?
    What you showed here on the calculator confused me because i only have 1 number how am i supposed to find the concentration?
    Also my professor doesnt use or allow the use of graphing calculators so i got confused as to find the slope so i can make my equation.
    I also need to use that equasion to find the extinction co efficient and the molar absorbtivity.
    So i cant figure out anything until i can understand how to find a
    I was given a graph and a bunch if questions and my professor didnt explain much he just gave me equasions with little explanation of how to do it im teaching myself. Its all due tomorrow so its not going to help me now but hopefully your explanations can help in my next lab.

    • @chempatenaude
      @chempatenaude  2 года назад

      Josh: Do you have a graph of absorbance versus concentration plotted? Or do you have a data table instead and have to make your own graph? Once you have the graph you just need to find the equation of the straight line. You can do this using technology like a graphing calculator. You can also enter the data on a spreadsheet program like Excel or Google Sheets and perform linear regression there. You can also find the equation of the line by hand. You would pick two points on your line and determine the slope of the line. Then using your slope and one of your two points that you picked, you can calculate the Y intercept of the line. Now you have the equation of your line. Plug-in the absorbance value into your equation and calculate the concentration.

  • @anjalisharma314
    @anjalisharma314 3 года назад

    I have put one solution and want to know his concentration .how can I know this by using raw data showing absorbance value and wavelength?

    • @chempatenaude
      @chempatenaude  3 года назад

      Anjala: do you have several solutions of known concentration and known absorbance at a certain wavelengths? If so, you make a Beer’s law graph of absorbance versus concentration and should find a straight line. Use the equation of that straight line, along with the absorbance value of your unknown solution, to calculate the concentration of the solution.

    • @anjalisharma314
      @anjalisharma314 3 года назад

      @@chempatenaude sir. I have five different solution having a particular organic compound in it. But I don't know the concentration of that compound in it. I want to know the concentration of that compound in these five samples. How can I know the concentration?
      Should I make a linear graph of these five compounds. , get equation, use the value of equation in
      A=ECl.,...............(1)
      C=A/El................(2)
      Take absorbance of first compound (from raw data from uv visy spectrophotometer) and put the value of equation and get conc.of one compound by putting value in eqn( 2)
      Take absorbance of second compound and put the value of same equation and get conc. of sec.compound
      Take absorbance of third compound and put the value of same equation and get conc. Of third compound. And so on
      Value of equation remain same for all five compounds. Am I right sir?

    • @chempatenaude
      @chempatenaude  3 года назад

      @@anjalisharma314 What is the name of the compound? Are you able to obtain a pure sample of the compound to make some standard solutions with concentrations you know? Is this a coloured solution? What solvent are you using?

    • @anjalisharma314
      @anjalisharma314 3 года назад

      @@chempatenaude sir it's an organic compound in solvent methanol. Actually the samples have been prepared by known conc five samples I have. I used these five known conc samples' And have added some thing into it so that that compound get absorbed by this thing. Now I want to know after putting a thing in these five samples of known conc. How much it get absorbed. For knowing how much it absorbed ,I mean ,I want to know the concentration of these compounds in each five samples I used the uv visible spectrophotometer for it.But in raw data there is absorbance value only. Now tell be how can I know the conc of that compound in each sample?

  • @airahmedija3661
    @airahmedija3661 5 лет назад

    sir where is the continuation of this video?

    • @chempatenaude
      @chempatenaude  5 лет назад +1

      Airah ... there is no continuation of the video.

    • @airahmedija3661
      @airahmedija3661 5 лет назад

      @@chempatenaude could you make a continuation sir about the task you left upon ending the video (mass of brass sorts) ? If it is okay?

  • @FreeSkillsStyle
    @FreeSkillsStyle 7 лет назад

    I have to get the concentration of an unknow solution using dilutions I have the wavelength, the absorbance.
    I made 5 dilution ex: 2ml water 3 ml unknow soln 0.746 absorbance 810 wavelength how do I get the concentration

    • @chempatenaude
      @chempatenaude  7 лет назад +2

      Ismael: You'll have to calculate the concentration (C2) in each of your 5 dilutions using C1V1 = C2V2. Then create a scatterplot on Excel or a graphing calculator ... Absorbance (y-axis) vs Concentration (x-axis). Find the equation of the line of best fit for your graph (linear regression ... trendline on Excel). Use that equation from your graph along with the absorbance of your unknown solution to calculate its concentration.

    • @jessiegustine1486
      @jessiegustine1486 4 года назад

      chempatenaude I still don’t understand hot you find the concentration. C1V1= C2V2 ??

  • @jsx0328
    @jsx0328 8 лет назад

    Great use of the graphing calculator, but unfortunately, not usable on a test. Sci-calcs only.

  • @Ebani
    @Ebani 7 лет назад

    Just what i was looking for.

  • @realkh5729
    @realkh5729 3 года назад +1

    You have explained it really well, i have a question about my prac, only if could reach to you via email or anything i would be great i'm happy to pay for your time :)

  • @shibamdas915
    @shibamdas915 4 года назад

    except that calculator part.. it's the best explanation

  • @mayreacts8030
    @mayreacts8030 4 года назад

    Thanks very much.

  • @adilali2399
    @adilali2399 8 лет назад

    cheers.....it was v. useful

  • @blizzrd6578
    @blizzrd6578 5 лет назад +1

    That solution is blue sir.

  • @rameshbishta2874
    @rameshbishta2874 7 лет назад +1

    Thanks a lot!

  • @TheRapThug
    @TheRapThug 8 лет назад

    Wonderful thanks

  • @jayaramsi
    @jayaramsi 8 лет назад

    very good video

  • @muhammadhakimin3153
    @muhammadhakimin3153 8 лет назад

    thank you

  • @PwnagePicturesInc
    @PwnagePicturesInc 9 лет назад

    Thanks a lot dude!!

  • @sarahhe562
    @sarahhe562 4 года назад

    thanks bro

  • @mohamedhashim3360
    @mohamedhashim3360 9 лет назад

    Thanks

  • @ricardorodriguez405
    @ricardorodriguez405 2 года назад

    great video, but i’m on spring break i don’t want this on my recommended 😅

    • @chempatenaude
      @chempatenaude  2 года назад

      Where do you have Spring Break at the start of March!? Jealous. :)

  • @الغيثالنافع-س7ع
    @الغيثالنافع-س7ع 4 года назад

    HILP .. HILLLLP😭 I lost after 16:00

    • @chempatenaude
      @chempatenaude  4 года назад +1

      I performed “linear regression” on the data in order to find the equation of the line of best fit. I used the graphing calculator to do this. You could also do it using a spreadsheet like Microsoft excel. You could also find the equation yourself by first drawing a line on your graph. Then pick two points on that line and find the slope and y-intercept. .الغيث النافع

    • @الغيثالنافع-س7ع
      @الغيثالنافع-س7ع 4 года назад

      @@chempatenaude Thank you for answering me🌺

  • @محمدفاضلمحمد-ج1ك
    @محمدفاضلمحمد-ج1ك 8 лет назад

    very good
    thanks

  • @harshasindhi7931
    @harshasindhi7931 7 лет назад

    thanks

  • @jamirahamed6023
    @jamirahamed6023 6 лет назад

    Thanks