Timestamps for the different topics covered in the video: 0:00 Introduction 0:30 Types of Communication: Baseband and Carrier Communication 3:23 Introduction to Double Sideband Suppressed Carrier (DSB-SC) 7:40 Generation of DSB-SC Modulated Signal and Tone Modulation 10:22 Demodulation of DSB-SC
I\'m not sure but ,if anyone else wants to uncover introduction to electronics try Elumpa Circuits Expert Alchemist (Have a quick look on google cant remember the place now ) ? Ive heard some incredible things about it and my neighbor got great success with it.
Thank you for the nice and crisp explanation with optimum time utilisation. Your voice and ascent is clear, no need of caption, actually the caption is a disturbance as it masks vital area of the screen and the diagram/ equations behind. Thank you 🙏
Not sure I will remember all that math, but you certainly made me have a few aha! moments with this. It makes me admire the people that invented this even more.
hey ,if anyone else wants to discover how to make electronic circuits try Bablim Electronics Booster (just google it ) ? Ive heard some awesome things about it and my buddy got excellent results with it.
Awesome video @:146 you said using modulation the frequency spectra of the BBU signal is shifted to non-overlapping band at the higher frequency is this using FM you mean? or the modulation in general regardless of the type it will do the shifting?
Thanks for the great explaination but i have two questions 1- Why we need to multiply the modulated signal with the carrier again at the receiver before the LPF? 2- If the frequency or the phase of the carrier at the receiver is not the same at the transmitter what will happen the the demodulated signal?
Sir , if am being confused. Please help me. Sir , if in AM only the amplitude of the carrier wave is modulated according to the message signal , then what does the upper and lower side bands represent? Is this means that the frequency of carrier also changes or what?
In time domain, yes only amplitude of carrier wave is modulated but the same thing in frequency domain corresponds to two side bands around carrier frequency. (Of course, in DSB-SC, we will not have carrier frequency ). The carrier signal frequency is not changing but the message signal band gets shifted by fc in frequency domain. I hope, it will clear your doubt.
Thanks for the great video,sir. But I have a doubt in demodulation where you've used LPF. So, it will allow 1/4(M(f-2f0).but, we dont need that signal right,sir. Are we suppose to use BPF instead of LPF, sir?
The LPF will in fact reject 1/4 M (f - 2fo) and will pass only the message signal spectrum. Please check at 12:22. Because after the demodulation, we want to recover the original message signal. I hope, it will clear your doubt.
Hi, kindly thank you very much for your lectures. You were saying there is no discrete component at the centred frequencies (-fo and fo). However, what if we have DC component in our signal that appears at 0 Hz. Then, would not we have a component at centres?
You said at 07:30 : now, one thing if you notice over here, then at every zéro crossings of this message signal, there will be a phase reversal in the modulated signal. And that is wrong and big mistake for ‘phase-reversal’, to occur, both the message and the carrier should have their zero-crossings at the same instant of time. In the event of the zero-crossing of the message not being accompanied by the zero-crossing of the carrier, there is a change in polarity of the modulated waveform without the usual ‘phase-reversal’
Please clarify my doubt. The message signal during transmission is m(t). But in 12.25 you mentioned that the msg signal is 1/2(m(t)).why ? Dividing it by 2, won't it get disturbed ?
When the message signal m(t) is divided by 2, only its amplitude will become half. In every other aspect the signal is same. After recovering the message signal, using simple amplifier its amplitude can be doubled or scaled as per the requirement. I hope it will clear your doubt.
I don't understand the forier transform of Cos in Tone Modulation part... how there is term 1/2 ? I saw in books Fourier transform of coswot = F{Coswot} = π[d(w+wo) +d(w-wo)} ? which one is correct?
The formula which you have written is in w (angular frequency). If you see the formula of Fourier transform in terms of the angular frequency, then in the frequency shifting property there is 2*pi additional term. Therefore the overall expression will get multiplied with 2*Pi. The expression written in the video is in frequency. e.g (f- fo) Both are correct representations. I hope it will clear your doubt.
Why is it that when I come looking for electronics information, it's almost always by an Indian?? Your English isn't very good Turd? You mean third. Stop pausing in the middle of a sentence. When you do that, it makes the sentence confusing.
Timestamps for the different topics covered in the video:
0:00 Introduction
0:30 Types of Communication: Baseband and Carrier Communication
3:23 Introduction to Double Sideband Suppressed Carrier (DSB-SC)
7:40 Generation of DSB-SC Modulated Signal and Tone Modulation
10:22 Demodulation of DSB-SC
I\'m not sure but ,if anyone else wants to uncover introduction to electronics try Elumpa Circuits Expert Alchemist (Have a quick look on google cant remember the place now ) ? Ive heard some incredible things about it and my neighbor got great success with it.
this is my whole class in 15 minutes!!
This is my whole semester
You explain the most difficult topic in easy way and in less time Best teacher on RUclips for electronic.
Thank you for the nice and crisp explanation with optimum time utilisation. Your voice and ascent is clear, no need of caption, actually the caption is a disturbance as it masks vital area of the screen and the diagram/ equations behind. Thank you 🙏
My teacher even dont let us understand in 1 hours which you just do in 15minutes .thanku sir ❣️❣️
Really that's so true👍🏻
Don't compare your teacher to this teacher bro ....
You are amazing job.. keep it up.. Love from Pakistan
Not sure I will remember all that math, but you certainly made me have a few aha! moments with this. It makes me admire the people that invented this even more.
hey ,if anyone else wants to discover how to make electronic circuits try Bablim Electronics Booster (just google it ) ? Ive heard some awesome things about it and my buddy got excellent results with it.
Thank you for the very clear video and illustrations!!
Great Explanation
very clear video and with good detail!!
best video bro👍👍👍👍👍👍👍
This is my whole 1 lecture (3 hours) in 15 mint😅
Awesome video @:146 you said using modulation the frequency spectra of the BBU signal is shifted to non-overlapping band at the higher frequency is this using FM you mean? or the modulation in general regardless of the type it will do the shifting?
thank you for this video. this is very helpful
Please make more videos on this playlist
Thanks for the great explaination but i have two questions
1- Why we need to multiply the modulated signal with the carrier again at the receiver before the LPF?
2- If the frequency or the phase of the carrier at the receiver is not the same at the transmitter what will happen the the demodulated signal?
Excellent refresher. Thanks!!
great sir ji
Nice explanation, Thank you :)
Sir , if am being confused. Please help me.
Sir , if in AM only the amplitude of the carrier wave is modulated according to the message signal , then what does the upper and lower side bands represent? Is this means that the frequency of carrier also changes or what?
In time domain, yes only amplitude of carrier wave is modulated but the same thing in frequency domain corresponds to two side bands around carrier frequency. (Of course, in DSB-SC, we will not have carrier frequency ). The carrier signal frequency is not changing but the message signal band gets shifted by fc in frequency domain. I hope, it will clear your doubt.
pls make video on other modulations, too.
What is the plan ? Are you shifting gears towards communications?
Any way it's good to know also all about communication 🙂
He shifted ?
OP Video♥
Thanks for the great video,sir. But I have a doubt in demodulation where you've used LPF. So, it will allow 1/4(M(f-2f0).but, we dont need that signal right,sir. Are we suppose to use BPF instead of LPF, sir?
The LPF will in fact reject 1/4 M (f - 2fo) and will pass only the message signal spectrum. Please check at 12:22. Because after the demodulation, we want to recover the original message signal. I hope, it will clear your doubt.
Hi, kindly thank you very much for your lectures. You were saying there is no discrete component at the centred frequencies (-fo and fo). However, what if we have DC component in our signal that appears at 0 Hz. Then, would not we have a component at centres?
Nice class😇
You said at 07:30 : now, one thing if you notice over here, then at every zéro crossings of this message signal, there will be a phase reversal in the modulated signal.
And that is wrong and big mistake
for ‘phase-reversal’, to occur, both the message and the carrier should have their zero-crossings at the same instant of time. In the event of the zero-crossing of the message not being accompanied by the zero-crossing of the carrier, there is a change in polarity of the modulated waveform without the usual ‘phase-reversal’
Excellent 👌👍
very understanding
Sir when are you going to upload Techniques for generation of Modulated signal??
Sir please respond sir!!
Very soon.
@@ALLABOUTELECTRONICS Thank you sir 😇
The reason for asking u sir that is you can explain the content very clearly sir!!
Hi hello
Please clarify my doubt. The message signal during transmission is m(t). But in 12.25 you mentioned that the msg signal is 1/2(m(t)).why ? Dividing it by 2, won't it get disturbed ?
When the message signal m(t) is divided by 2, only its amplitude will become half. In every other aspect the signal is same. After recovering the message signal, using simple amplifier its amplitude can be doubled or scaled as per the requirement. I hope it will clear your doubt.
@@ALLABOUTELECTRONICS but why is the amplitude becoming half ?
Also thanku so much for answering :))
@@anirudhracs4537 It's because of the Fourier transform
Which software use for lecture vedio
What will be the value of modulation index for DSBSC??
Distinguishe between DSBSC and SSBSC and give time domain &frequency domain descriptions ? Plz sir can say in this topic
what is the meaning of this negative frequency
I don't understand the forier transform of Cos in Tone Modulation part... how there is term 1/2 ?
I saw in books Fourier transform of coswot =
F{Coswot} = π[d(w+wo) +d(w-wo)} ?
which one is correct?
The formula which you have written is in w (angular frequency). If you see the formula of Fourier transform in terms of the angular frequency, then in the frequency shifting property there is 2*pi additional term. Therefore the overall expression will get multiplied with 2*Pi. The expression written in the video is in frequency. e.g (f- fo)
Both are correct representations.
I hope it will clear your doubt.
Thank u so much sir for a quick response and clearing my doubt....🙂😀
Good sir
❤❤❤❤
Good
I wish I didn't have trouble understanding the Indian accent. Thanks a lot for the explanation though.
How about sir for QAM modulation
thanks sir
👍👌👌🏻
ECE 485 UofA
Well but sir very fast is not good we are facing problem
You may watch it at 0.75 X speed. It will help you.
done
7:31******
154
1223
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why dont you explain in hindi?....please explain in hindi ...everyone dont understand english so good...please explain in hindi
All books are written in English
as far as I know in India not everybody understand Hindi
there are Punjabi people also
What other language students have to do
I know I feels different but we need to learn studying in English...all engineering education occurs in english language only
Universal English he Hindi nhi bro ....
South walo ko hard ho jayega Aisa to ...
Tho I'm South, i know Hindi
He is explaining in Hindi
Why is it that when I come looking for electronics information, it's almost always by an Indian?? Your English isn't very good Turd? You mean third. Stop pausing in the middle of a sentence. When you do that, it makes the sentence confusing.
and how is your Indian speaking doing? Come on man, he is doing the best he can, slow to .75 speed is a good solution.