Some other nice identities from this type of triangle, if you want them: a = c/2 = (b sqrt(3) )/ 3 b = c/2 sqrt(3) = a sqrt(3) c = 2a = ( 2b sqrt(3) / 3) Not too sure how to fit them in here and write them, but this should be understandable. If you're learning for school learn at least one row, or one column from each row and you can work out the rest, so you're ready for any 30 60 90 triangle. I remember the easiest ones: a = c/2 and b = a sqrt(3) from these you can work out the rest!
if the side opposite the 30 degree angel is always equal to sqrt 3 less then the side opposite the 60 degree angel then how come 5 - sqrt 3 doesn't equal the same as 5 times sqrt 3 over 3? Thanks in advance :)
Some other nice identities from this type of triangle, if you want them:
a = c/2 = (b sqrt(3) )/ 3
b = c/2 sqrt(3) = a sqrt(3)
c = 2a = ( 2b sqrt(3) / 3)
Not too sure how to fit them in here and write them, but this should be understandable. If you're learning for school learn at least one row, or one column from each row and you can work out the rest, so you're ready for any 30 60 90 triangle.
I remember the easiest ones:
a = c/2 and b = a sqrt(3)
from these you can work out the rest!
Sir, looking at all of your videos, you may be my saving grace in my PAP Geometry class this year
Khan rocks !!
Plz do more tuts on Geometry ... we need more !
I love u
Daddy
Can't believe how far Khan Academy has gone from watching this video 13 years later.
You sir....are a GOD send......
question: if you have a square root of 3 over 3 could it be simplifed to the square root of 1? plz reply
Thank you man
if the side opposite the 30 degree angel is always equal to sqrt 3 less then the side opposite the 60 degree angel then how come 5 - sqrt 3 doesn't equal the same as 5 times sqrt 3 over 3? Thanks in advance :)
Short leg = x
long leg = x rad3
hyp = 2x
easier formula -.-
thank you soooo much :D
Thank you! :D
its easier for me to remember :)
The link on the description is broken.
The writing's a little cramped on this one, Sal!
he sounds kinda like brian from family guy ;)
yes, because short leg and long leg are definatley mathematically correct terms -.-
what if i have the base ??????? waaaaaaaaaahahahaaaa