Lecture 06 : Making Phosphate Buffer (100mM)

[@bartley7231]

This man don't drop no catch. He is so thorough. Thank you for an excellent video.

[@Dr.AsadAliPhD]

Amazing methodology. great work

[@jungbhadursingh9450]

Sir best teaching methodology

[@jungbhadursingh9450]

Sir u r having good art of teaching so plz explain or made videos on 50mM phosphate buffer nd also make videos on hw to prepare diffrent buffers

[@ArslanAli-jn4hd]

Thank you so much Sir!!
Much appreciated effort ✨

[@etherealgoddess3736]

How much amount should we take for the second component

[@radheyradhey5434]

Best explain about the buffer making

[@rudranimukherjee7958]

Really helpful,thanks a lot

[@Imranmwt666]

thank you so much, Nicely Explain. Best wishes

[@haimiviews4784]

Well explained, thank you

[@Manmata_Dhara]

I have a question. If this is the case, the final conc of individual ingredients will never be 0.1 M. For preparation of a buffer the final concentration of acid and base should be equimolar right?

[@monicam.1799]

Manmatha Dhara I have the same doubt, does the concentration of the final solution will remain as we are adding the same molarity of both solutions??

[@neeteshkumar2137]

dissolving time of sodium phosphate monobasic?

[@sabrinasin123]

Thanks for your sharing sir, it is really an informative video. By the way, in my case, I have to prepare 0.1M sodium phosphate buffer (pH 6.8). I straight forward mix the both 10ml of 0.1M dibasic and 10ml 0.1M mono basic, and it came out pH 5 something, and then I gently added the solution with dibasic until it reached my target pH. Is it practical? Thanks for your comment.

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[@daltondominic2377]

@Bruce Armani instablaster =)

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[@daltondominic2377]

@Bruce Armani glad I could help xD

[@PrinciThapak_scienceelite]

How you calculated the gm of solute

[@ShubhamRawat-x3s]

By this formula- required vol.×required concentration ×molecular weight ÷1000×1000
Formula for determine milimolar solution

[@shreyadas6453]

Very helpful vedio!!

[@ko-fanta]

Thank you Prof

[@kishanshaw8577]

well explained

[@salmamansour4418]

What is the amount of the NaPO4 dibasic powder???

[@milindgajbhiye4303]

Calculate from its mol wt

[@maywong6568]

@@milindgajbhiye4303 is this means we add 3.549g of Na2HPO4 powder into DI water?

[@Manmata_Dhara]

The second ingredient u r adding will have a very low concentration. How will and how long it will act as buffer?

[@talatz8227]

Since they have prepared equimolar solution i.e. 100mM so the concentration doesn't change. It's the volume that's different not the concentration.

[@markog5925]

You should have used volumetric flask

[@sabrinasin123]

If you are professional not to split out the buffer during mixing, it is okey ^_^

[@davidorsa4406]

Do the calculations!!! It does not make sense just talking!!!

[@mahparakhanam5093]

Sir u didn't mention the quantity of dibasic to be taken....please tell me that.

[@user-fs2hy8im8m]

You only have to calculate it according to the concentration you need

[@gurralamohankumar5838]

Thank u so muchhh

[@hakimabanoo1882]

Thank sir

[@padmamanandhar7438]

So long video and elaborative. So much could have been eliminated

[@dr.durgeshkumarghata1837]

Sir ji calculation

[@jairajput3841]

sir plz teach us by hindi language then better result you will find

[@sreyankosadhukhan6776]

Repetitive.

[@mdmafujur8347]

well explained