EXAMPLE Calculating Influence Lines: Part 1 - General Method

An example of how to calculate influence lines for the shear and moment at a point in a beam with an internal hinge. Uses the general method to first find the influence lines for the reactions and then to find the moment and shear influence lines at a given point.
Like my explanations? Check out my full free online textbook at learnaboutstruc...

[@theonlynever61]

Really informative and helpful video! I loved it. I wish my engineering professors explained how to to this as well as you did. Thanks for the help.

[@pedrodylan7289]

I realize I am kinda randomly asking but does anyone know a good place to stream new tv shows online?

[@chinhaowlim]

Thank you very much for the video!

[@fatimamancuso]

This is a great example, only problem it doesn't address is what if the point of interest for internal moment or shear is before your hinge, between A and B. This works if your point of interest is after B.

[@reginalddmuchunga727]

at last i got it at least i can manage to tackle my assignment

[@ngjingying647]

So helpful. Thank you.

[@Michael0918ify]

really helpful for the exam... much better than our lecturer :D

[@xiaobanzi]

Good luck in the exam!

[@Michael0918ify]

xiaobanzi thx. it s really helpful vedio aye

[@tommykirilyo215]

Thanks much for this video.

[@naishethelovebirds5145]

Love the video but can i ask is it possible to be asked to find the shear influence line at B ( considering we know the reaction influence line of B )

[@ejazshaikh3005]

Which textbook are you using for the problem?

[@lisro21]

Thank you for the video

[@yamikawaii321]

I don't understand how to get (x-10)
reference: 22.40.

[@lisro21]

@28:32 isn't it supposed to be Sum(M@G)=0

[@jodeneclarke3201]

what text are you using?

[@TheCivilProfessor]

My own, now online: www.learnaboutstructures.com

[@engrjace]

where did you get the rxn @ by 6-X/4 ?

[@MrMe-kj1up]

6-X/4 is equal to 1.5 - X/4. just divide 6 into 4 and x/4, you get 1.5 - x/4.

[@ll-tr7hh]

legend