EXAMPLE - Portal Method for Approximate Building Frame Analysis

Full Portal Method frame analysis example, including assumptions and approximations, determination of assumed column shears, full solution for all frame member forces and the construction of axial, shear and moment diagrams.
Like my explanations? Check out my full free online textbook at learnaboutstruc...

[@youenglooi9733]

you r better than professor in my school ! thx , i love u !

[@jawadmahmud2552]

Excellently done, professor. Thank you very much.

[@michaeljofreddoria8139]

Im confused about the moment at the left side(moment diagram). . It shows that it is not in equilibrium. 81+111.375 is not equal to 30.375. Which means that the direction is wrong.

[@engchristianoakuku5741]

great work proffesor...now i can get the strain energy stored in the frame by Maxwell-Bett theorem.thanks

[@michaelanthonyabenales]

is this the analysis that is applicable to ultimate strength design? also, where could i apply moment distribution, is it in ultimate design or working stress design.

[@alialhameedi990]

Thanks so much. But I wonder if you can use UDL instead of lateral loads please

[@abdullahalmahruqi1976]

Thanks man!
We really appreciate your work

[@gabrielcentino4001]

You made me love my course again. Our instructor suck

[@SamarKenkre]

Very clearly explained ! Good stuff :)

[@nishattasnimpriyanka6665]

Very helpful video. Keep up the good work. Love from Bangladesh :)

[@MIMRAN65]

Prof Correct me if I am wrong, based on the assumed direction the axial force in beams are tensile forces instead Compression

[@caseypoi1]

thank so much for your video. i had some questions if you had a minute.
1) i saw another example where 2 bays of the same width/stance produced zero axial force in the interior column. would this be true of any number of equal stance bays (say 4 bays), where all interior columns (say 3 column, with the 4 bays) would have zero axial force? is this true regardless of the story heights?
2) i noticed that n this example and others that the moment of the interior column is twice that of the moments in the exterior columns. how does this hold when there are multiple bays? with 4 bays, would the 3 interior columns each be twice as much as either exterior column?
thanks again!

[@dhananjayareddychinnagadi8196]

if u don't mind please upload the same example with substitute frame method also sir..

[@tadthurston3192]

Could you show this method for the situation where you had uniform and uniformly decreasing loads instead of point loads on the frame members?

[@TheCivilProfessor]

I'd love to make more like this one, but it'll have to wait until next semester unfortunately.

[@benardmbeda5262]

Perfectly presented

[@jan-ainsleylopez-mills6552]

Hi: Did you upload the solution for the Cantilever Method? I would like to view if you would share?

[@MinanZamia]

When you upload cantilever method

[@BenjaminNPham]

This is brilliant. Thank you so much

[@TheCivilProfessor]

Thanks!

[@dvdortiz9031]

Excellent

[@jezoo5187]

i always get confused with the arrows and it makes my algebraic signs wrong :(

[@proshantatalukder3654]

brilliant work :*

[@theAnntman]

How'd you get 13.5 @7:35? Thanks.

[@franklinfitzgerald2666]

Hello, at hinge between H and I, take moments : 1.8x16.88 - 2.25x IF=0 then
IF= 16.88x1.8/ 2.25 =13.5 ,

[@diaboloj]

Please, at 8:11, how did you get 13.5kN? I can't see any other vertical force given. Thanks

[@ronafebiglesias5724]

16.88(1.8)/2.55=13.504

[@JJNg-sy5kc]

Hi, I think you did a mistake at 32:05 where the directions of both beams should be clockwise and direction of column should be counter-clockwise. Correct me if I am wrong. Thanks.

[@anietieokon6894]

Jie Ng nope. it is very correct and excellent. check the moment diagrams carefully

[@mikaelaabrihan1236]

at 16:15 how did you get the 28.6... when i calculate it shows 28.2

[@mohd7lo428]

amazing work, thank you soo much :)

[@TheCivilProfessor]

Thanks!

[@Manga_audrey]

please how did you get 50.6

[@dhananjayareddychinnagadi8196]

very useful sir.thank u

[@taongamaiwanga9890]

Great stuff

[@huzaifadaya4939]

How is the distance between H and I, 3 and 2.25 from H to hinge and hinge to I?

[@Alex-xq7ft]

Huzaifa Daya if you look on the first figure, span HI is 4.5. H to hinge should be 2.25. He must have been wrong where you saw 3.

[@mycuisine-andhrastyle5319]

At 15:04 how did u get 84.4,49.5 @4,3

[@triciamaribontigao7340]

@16:05 ... is it 28.6 or 28.2?

[@shierrajoygabon9262]

good morning sir, is there an instances that the exterior columns will have a value of a twice shear?

[@SuperLetsPlay2010]

if exterior colum is twice as thick as interior column

[@anubhavitiwari135]

hey can you please specify how you achieved the veertical force when there was none in the first place?

[@DeanS753]

***** thankyou for posting this link, helped me out, cheers.

[@AyeshaMunira]

Thanks Professor :) :)

[@douglassmith12345678]

at 15:00 how did he get 63KN?

[@omersaleemYT]

Well.. Helping Students in 2017 :D

[@PinceLordBaay07]

THNKS FROF...:)

[@Fawazz19]

63 is not correct I thinkit is 22.49Thank you

[@oralsquare]

awesome

[@audikarl5150]

at least explain how u got the horizontal forces, how u got it

[@dyarabubakr3373]

thank u :)

[@pranaybora5015]

can i get ur mail...???

[@johnnywayne46]

10:43 LAWL

[@kanyewest8844]

ILU

[@jasoncothran9759]

WRONG

[@ryoma13abby]

14:49. How did you get the 63?

[@qaisalsabahi191]

Risa Harada i got 49, maybe he's wrong!

[@Alex-xq7ft]

Risa Harada if you take moments about the beam hinge, you get 78.755 in tension.

[@sharifapalmer3321]

(16.88x1.8+13.5x2.25+45x1.8)/2.25

[@tristanjeromevillota6965]

The 1.1 should be 1.8, he just wrote it wrong but the answer is correct with the right dimension