Resolvendo livro de matemática (Intermediate Algebra) - Parte 45
HTML-код
- Опубликовано: 7 фев 2025
- 1
2
a)
2xy + 27x - z + 12
2xy, 27x, - z, 12
b)
2x², x, -wz
c)
11, -2, 7
d)
2xuv
2, x, u, v
e)
2xy: 2
-x: -1
8: 8
f)
2x, -7x
22ab²c³, -9ab²c³
3
-4
a)
inteiro, racional, real
b)
-1/4
c)
4
d)
|-4| = 4
4
0
a)
C#, inteiro, racional, real
b)
a, 1/a
Não está definido
c)
0
d)
|0| = 0
5
{x | x |-3|} = (3, ∞)
{x | x 3}
6
{x | x ≤ |-4/3|} = (-∞, 4/3]
{x | x ≤ 4/3}
7
{w | -5/2 w ≤ √9} = (-5/2, 3]
{w | -5/2 w ≤ 3}
8
{z | 2 ≤ z 11/3} = [2, 11/3)
9
2x³ - 5xy + 6
a)
2x³,- 5xy, 6
nt = 3
b)
6
c)
2x³: 2
5xy: -5
6: 6
2, -5, 6
10
a² - 4ab - b² + 8
a)
4 termos
b)
8
c)
1, -4, -1, 8
11
pq - 7 + q² - 4q + p
a)
5 termos
b)
-7
c)
1, -7, 1, -4, 1
12
7x - 1 + 3xy
a)
3 termos
b)
-1
c)
7, -1, 3
13
3 + 1/2 = 1/2 + 3 [a]
14
7,2(4 + 1) = 7,2(4) + 7,2(1) [c]
15
10 + 0 = 10 [f]
16
7 * 1 = 7 [g]
17
(6 + 8) + 2 = 6 + (8 + 2) [e]
18
(4 + 19) + 7 = (19 + 4) + 7 [a]
19
6 * 1/6 = 1 [i]
20
2 + (- 2) = 0 [h]
21
9(4 * 12) = (9 * 4)12 [b]
22
(1/4 + 2)20 = 5 + 40 [c]
23
42 * 1 = 42 [g]
24
4 * 1/4 = 1 [i]
25
(13 * 41)6 = (41 * 13)6 [d]
26
6(x + 3) = 6x + 18 [c]
27
8 + (- 8) = 0 [h]
28
21 + 0 = 21 [f]
29
3(y + 10) = 3(10 + y) [a]
30
5(3 * 7) = (5 * 3)7 [b]