Resolvendo livro de matemática (Intermediate Algebra) - Parte 45

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  • Опубликовано: 7 фев 2025
  • 1
    2
    a)
    2xy + 27x - z + 12
    2xy, 27x, - z, 12
    b)
    2x², x, -wz
    c)
    11, -2, 7
    d)
    2xuv
    2, x, u, v
    e)
    2xy: 2
    -x: -1
    8: 8
    f)
    2x, -7x
    22ab²c³, -9ab²c³
    3
    -4
    a)
    inteiro, racional, real
    b)
    -1/4
    c)
    4
    d)
    |-4| = 4
    4
    0
    a)
    C#, inteiro, racional, real
    b)
    a, 1/a
    Não está definido
    c)
    0
    d)
    |0| = 0
    5
    {x | x |-3|} = (3, ∞)
    {x | x 3}
    6
    {x | x ≤ |-4/3|} = (-∞, 4/3]
    {x | x ≤ 4/3}
    7
    {w | -5/2 w ≤ √9} = (-5/2, 3]
    {w | -5/2 w ≤ 3}
    8
    {z | 2 ≤ z 11/3} = [2, 11/3)
    9
    2x³ - 5xy + 6
    a)
    2x³,- 5xy, 6
    nt = 3
    b)
    6
    c)
    2x³: 2
    5xy: -5
    6: 6
    2, -5, 6
    10
    a² - 4ab - b² + 8
    a)
    4 termos
    b)
    8
    c)
    1, -4, -1, 8
    11
    pq - 7 + q² - 4q + p
    a)
    5 termos
    b)
    -7
    c)
    1, -7, 1, -4, 1
    12
    7x - 1 + 3xy
    a)
    3 termos
    b)
    -1
    c)
    7, -1, 3
    13
    3 + 1/2 = 1/2 + 3 [a]
    14
    7,2(4 + 1) = 7,2(4) + 7,2(1) [c]
    15
    10 + 0 = 10 [f]
    16
    7 * 1 = 7 [g]
    17
    (6 + 8) + 2 = 6 + (8 + 2) [e]
    18
    (4 + 19) + 7 = (19 + 4) + 7 [a]
    19
    6 * 1/6 = 1 [i]
    20
    2 + (- 2) = 0 [h]
    21
    9(4 * 12) = (9 * 4)12 [b]
    22
    (1/4 + 2)20 = 5 + 40 [c]
    23
    42 * 1 = 42 [g]
    24
    4 * 1/4 = 1 [i]
    25
    (13 * 41)6 = (41 * 13)6 [d]
    26
    6(x + 3) = 6x + 18 [c]
    27
    8 + (- 8) = 0 [h]
    28
    21 + 0 = 21 [f]
    29
    3(y + 10) = 3(10 + y) [a]
    30
    5(3 * 7) = (5 * 3)7 [b]

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