Hello dear, Here is your answer. We take x0 =4, not x0=5 because we have got the -ve and and + ve value between 4 and 5 which mean our root will lie between 4 and 5. And its up to us either we proceed by taking x0=4 or x0=5. There is no any hard and fast rule for this. So go for it it's totally your choice and i am sorry that i am replying you late. Have a nice day.
Transform equation to the form x = f(x) and there we have two options Solve x = f(x) or solve x = f^{-1}(x) How to choose correct one ? In this example f(x) = 100/x^2 - 1 If we try to solve x=f(x) we will get divergent sequence but if we solve x = f^{-1}(x) sequence will converge
Why is the second form for the second example not valid?? Since the root lie between 0 and 1 and once we plug it to to the derivative we get less than 1 for both, why is it not still valid?
Hello dear, Thanks for your comment. The thing is you cannot apply f(0) and f(1) in the beginning because in iteration method one must satisfy what the theorem says i.e. modules of fi(x) must be less than one. You can apply f(0) and f (1) if the theorem has satisfied. In to this video i have added an extra Example at the end to enhance your understanding so do watch the video till end. And i am sure that you arr going to find it very helpful. Thank you. Have a nice day
13:11 should the 2nd equation be x = (-x+1)^1/3 with negative x in argument as oppose to positive x? or am i wrong?
@Ciaran K Campbell I think you are right...
In this case |g'(x)| is not less than one on [0,1]@@swapnab8221
Nice explanation brother
Tq♥️
Well Explained Sir, Keep on doing more vedios
Very good explanation esp at the end
Very helpful
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Nice explanation bro Tq
Welcome
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Why we take x0=4 ? If we take x0=5 means
Hello dear,
Here is your answer.
We take x0 =4, not x0=5 because we have got the -ve and and + ve value between 4 and 5 which mean our root will lie between 4 and 5.
And its up to us either we proceed by taking x0=4 or x0=5. There is no any hard and fast rule for this. So go for it it's totally your choice and i am sorry that i am replying you late.
Have a nice day.
Thank you 😭
Super excellent
Transform equation to the form
x = f(x)
and there we have two options
Solve x = f(x) or solve x = f^{-1}(x)
How to choose correct one ?
In this example
f(x) = 100/x^2 - 1
If we try to solve x=f(x) we will get divergent sequence but if we solve x = f^{-1}(x) sequence will converge
Is fixed point iteration still the same as method of successive approximation
Nice one
Why is the second form for the second example not valid??
Since the root lie between 0 and 1 and once we plug it to to the derivative we get less than 1 for both, why is it not still valid?
You're right have seen this as well
Thankss broo
Thanks 🙏🙏🙏🙏
How to take xnot value
sir can we put f(0) and f(1) in the beginning equation itself means in the question
Hello dear,
Thanks for your comment.
The thing is you cannot apply f(0) and f(1) in the beginning because in iteration method one must satisfy what the theorem says i.e. modules of fi(x) must be less than one. You can apply f(0) and f (1) if the theorem has satisfied.
In to this video i have added an extra Example at the end to enhance your understanding so do watch the video till end.
And i am sure that you arr going to find it very helpful.
Thank you.
Have a nice day
Galerkin method.
Hope you like it.
ruclips.net/video/dBoVeyes4YQ/видео.html
❤️
ily
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Voice is very low
Sorry for inconvenience.
At first find the interval
Yes
Yes
Very helpful