SSC JE CBT 2 Paper Solution Civil Engineering | SSC JE 2024 CBT 2 Civil Engineering | by Shubham Sir

[@ghevrajbose2634]

Solution :-
Center line length 10.6*2 + 6.3*3 = 40.1m
Total length = {( Center line length - width of item /2 ) * No.of T-junction }
Total length = 40.1 - 1.1 = 39m
Volume = L*B*H { given question B=1.1 H = 0.3
Volume = 39*1.1*0.3 = 12.87m³

[@Dheeraj_Kaiwartya]

By Long Wall Short Wall Method
L=2(c/c Length of Long Wall+2x Width of Foundation/2)+3(C/c Length of Short Wall-2x Width of Foundation/2)
L=2(0.3/2+4+0.3+6+0.3/2+2*1.1/2}+3(0.3/2+6+0.3/2-2*1.1/2)= 39m
By Centre Line Method
L=2(C/c Length of Long Wall)+(c/c Length of Short Wall)-No.of T-Junction(Width of Foundation/2)
L=2(0.3/2+4+0.3+6+0.3/2)+3(0.3/2+6+0.3/2)-2*1.1/2=39m
Given (B=1.1m & H=0.3m) in the figure
So, The Quantity Of Lime Concrete Foundation=
LxBxH= 39x1.1x0.3= 12.87m³

[@Singhrajesh794]

Simple h sir...
Total c/c distances=(2*long wall c/c distance + 3*short wall c/c distance -deductions for T-junction (2Nos.))
(2*10.60+3*6.3-2*1.1/2)=39m
So volume of PCC=LBH
V=39*1.1*.30=12.87m✅✅

[@ashishgupta116]

Thanks sir🙏🏻

[@b.dibyaranipatro3473]

Sir interior ke kiye (2n-4)*90 hoga na

[@navinkeshri1335]

सर... Ist question me... Jb.. C ad D free from local attraction.. Dikh rha h.... To D SE BEARING TO सही ही होंगी न... C ANSWER HO JANA CHAHIYE

[@prajwalkumar4366]

12.87m3 (isme 1.1 se minus karna hai na ki 0.3 se)

[@mahdeviswami8852]

Sir download ka option available karwa do please

[@enggmbd6941]

Ek question ko solve karne me 31 minutes lag gay chacha

[@GSCB66]

Screen bale calculator se ye 20 minute me bhi nhi hoga😂😂😂

[@Minote7-b4u]

Ye to bat h bro tbhi to cpwd milega