Glad I could help, thanks for watching. Make sure to check out my website adampanagos.org for additional content (600+ videos) you might find helpful. Thanks, Adam
Thanks for the kind words, I’m glad you enjoyed the video! Make sure to check out my website adampanagos.org for additional content (600+ videos) you might find helpful. Thanks much, Adam
I have an exam tomorrow, I actually had this last but we might to use it tomorrow. I study in french but your basic english and clear explanations made it easy for me to connect the dots. Keep up the good work.
I guess Im asking randomly but does someone know a way to log back into an instagram account?? I stupidly forgot my login password. I would love any tips you can offer me.
Great ! english is not my 1st language. Nevertheles, I realy grasped your explanations while writing the sketches on a piece of paper . Thanks a lot Sir ! What you are doing is so helpful.
Thanks for the kind words, I’m glad you enjoyed the video! Make sure to check out my website adampanagos.org for additional content (600+ videos) you might find helpful. Thanks much, Adam
Glad I could help, thanks for watching. Always makes me happy to know that people throughout the world can see/access these random videos I make. Make sure to check out my website adampanagos.org for additional content (450+ videos) you might find helpful. Thanks, Adam
+Mete Yildirim Glad you liked the video. I'm still regularly posting videos to the channel, just the exact topics vary from video-to-video. Thanks for watching. Adam
This is great :) really helped me starting studying signals and systems ahaha Im studying Eletrical and Computer Engineering in Portugal this really helped me a lot thanks hahaha
Comments like these make me quite happy, many thanks. Make sure to check out my website adampanagos.org where I have additional resources you might find useful, and consider supporting development of new videos through www.patreon.com/agpanagos. Good luck wrapping up that degree! Adam
Thank you for the kind words, I appreciate you watching. Make sure to check out my website adampanagos.org for additional content (435+ videos) you might find helpful. Thanks, Adam
Thanks for the kind words, I’m glad you enjoyed the video! Make sure to check out my website adampanagos.org for additional content (600+ videos) you might find helpful. Thanks much, Adam
You're welcome, thanks for watching. Make sure to check out my website adampanagos.org where I have a lot of other material you might find helpful. Best, Adam
I know this is a convolution video and not an integration video but if you would have show the process of integration at 7:20, people would learn about integration too. Anyway the video is very nice!
Thank you for the kind words, I appreciate you watching. Make sure to check out my website adampanagos.org for additional content (600+ videos) you might find helpful. Thanks, Adam
Thank you very much. Mr. Panagos. More than helpful and really well explained. Just have one doubt: What happens when the two triangles overlap completely? Should we calculate them as well for the complete solution?
As the shapes slide by each other, anytime a new boundary is encountered the product of the equations changes. So, you have to change cases every time a new product is encountered. Definitely takes some practice!
After you've sketched the time-reversed and shifted signal, you "slide" that signal until it collides with the original signal. The front edge of the time-reversed and shifted signal is always at t+1. The back edge of the original signal is at -1. So, the first case occurs for all values of t such that t+1 < -1. It's all about sketching those pictures and keeping track of when the signals "collide" with each other. Hope that helps, Adam
isnt there a mistake at 2:23 if we take ' 1+ t ' and substitute 't' by (-tau + t) we get '' 1- tau + t '' as the new equation, and the opposite for other side ?????????????????????????????
At 2:23 we had the line 1+tau. The substitution we performed was replacing -tau with t-tau. So, 1+tau = 1-(-tau), and we replace -tau with t-tau to yield 1-(t-tau) = 1-t+tau = 1+tau-t as we had in the video. Same thing on the other line. We had 1-tau and we replace -tau with t-tau, so we have 1+(t-tau) = 1-tau + t. Hope that helps. Adam
@@AdamPanagos I really apreciate your care to answer , your answer makes sense now , so i presume that what i did is wrong ( i took the original equation of that ramp where the varibale was just " t " and since what we did was fliping and shifting so, t => t - tau , and the equation was 1+t from the left ) i watched another video just because of that part where finding the new equations and a guy just substitued in the original equation "t" by "t - tau" , i got your answer, but it's still not clear if i try some other examples , thank you .
In the video titled " convolution example 02" at 2:05 you have substituted "t" by " t - tau" in the original equation , to get the new equation of the " flipshifted " signal , which is confusing me a lot .
@@ghilashamaili2733 No, the video is correct. When doing convolution, we replace "t" with "tau-t". When doing this, I feel it is helpful it draw each step of this transformation so one can keep track of where the bounds of the final integral will be. That's why I first sketch x(tau), then x(-tau), then x(t-tau). Sketching x(-tau) is just the time-reversed signal on the tau axis. Sketching x(t-tau) next just takes our time-reversed signal x(-tau) and shifts it by an amount t. So, in this case, I just keep track of where the time-origin tau = 0 gets shifted to. It will always get shifted to t. The thing to be careful with is that since we've already done a time reversal, shifting by "t" moves the signal in the opposite direction "from normal". For example, if we have the signal x(t), and then plot x(t-4), this shifts us 4 units to the right on the t axis. The signals x(t+5) shifts us 5 units to the left. However, if we're working with x(-t), shifting 4 units to the right means replace t with t-4, which would be x(-(t-4)) = x(-t+4). So, when comparing x(-t) to the signal x(-t+4), the signal x(-t+4) has actually been shifted 4 units to the right. The plus sign "+" on the 4 might make you think it's been to the left, but there is a minus sign on the t. You just have to be careful to keep track of whether we're dealing with a "normal" signal, or a "time-reversed" signal. If we've time-reversed already, that reverses the direction that we shift for some given + or - value of the shift. Hope that helps, Adam
So in essence The equation for a given case is given by: [x(t)*x(t)]*(T2-T1), lets call (T2-T1)=ΔT, so x(t)*ΔT + y(t)*ΔT. Is that correct? So the two areas multiplied with each other within each region?
Sure thing, that would be totally fine. I was mainly focusing on the convolution steps in this video, and not so much on how to simplify the resulting terms. Thanks for watching!
For (1+ t) consider x(t) = t : it's a straight line, we time shift this to the left by 1 to get the line x(t) = t + 1, or = 1 + t. Similarly for the 1 - t line; x(t) = -t, but time shifted to the right: x(t) = -(t - 1) = 1 - t. When we convolve the triangles together we replace t with T (can't write tau here so I'll use capital T), giving 1 + T, 1 - T. The other triangle we are time shifting about it's centre t: consider x(T) = 1 + T: here t is 0 because it's simply where it started on the origin. If we change this t to 'slide' them together we also change the equations in time. So we end up with x(t - T) = 1 + T - t and x(t - T) = 1 - T + t. I hope I've managed to explain that in a way you can follow.
right at 2:34, were the intercept is a function of t. Let's draw pictures, triangle with t to left of zero, let's say 1/2, so the peak is at 1, the slope is -1 and the intercept is 1/2. I can't see this analytically but as he says, when t is - 1/2, the intercept will be 1/2, which is 1 PLUS (-1/2). So the downward side is - tau + 1 PLUS t. On the upward side: at t=0, it's tau +1. Let's shift is right, make the peak t=1/2. Now the peak is 1 and the intercept is 1/2. We moved it right, from t=0 to t=1/2 and the intercept went down. So the left side is tau + 1 MINUS t. This has been driving me nuts.
Hi, firstly; thanks for these videos, they are very succesfull for us :) I need to learn " the convolution of u[n] and one signal " , what means this conv ?
when u flip and sketch x(-t) doesnot the value of left side and right side of triangle reverses? i mean at left side it,s t+1 it should be t-1 after the shift
Mainly just the name; great-grandfather came to the US from Greece so 1/8th Greek here. Thanks for watching and good luck with your studies! Best, Adam
Thanks a lot sir, your videos are extremely helpful, but I have a question. How can I know the number of cases and cases needed to do a convolution? is difficult to me know that.
+Gustavo Alejandro Malvaez Olguin Unfortunately, that's just one of those things that takes practice to figure out. In general, anytime the part of the signal you're dealing with changes equation (e.g. positive slope line to negative slope line for example) or the signal you're multiplying against changes equation then you'll need a new case.
Ehm, in my case I was going to give the TDFT of a triangle y(t)=1-abs(t). Anyway I went and tried to solve it the usual way, but the solution in our book said that y(t)=z(t)*z(t) where z(t) is a rec function with height one and left side on -0.5 and right side +0.5. Dose this make any sense to you? Anyway they later on said that Y(f)=(Z(f))^2 and we know from the mathematical handbook that Z(f)=sin(pi*f)/(pi*f) so naturally we know that Y(f)=sin^2(pi*f)/(pi*f)^2 thus solving the TDFT for y(t) I know that the books method for finding TDFT is much faster but i dont understand the part where they say y(t)=z(t)*z(t) and is the * in this statment the convulution or just a regular multiplication symbol?
Convolution in time domain, and normal multiplication in Frequency domain for your question. And it is also reciprocal, suppose you have to convolve between two functions in frequency domain, then it is multiplication in time domain.
+Mete Yildirim I use an iPad app called Doceri (www.doceri.com) for most of my videos. This app lets you record all your handwriting ahead of time and use "breakpoints" to pause as needed. Once all the writing is down you can "play" the handwriting back while recording audio over it. I find this works much better than trying to write and talk at the same time. I'd definitely recommend checking out the app, I've found it very useful. Hope that helps!
+Mohammad Nadeem That's definitely a completely valid way to approach the problem. I was just trying to work through each part of the computation to demonstrate how to explicitly evaluate (and understand) the convolution integral. Hopefully I ended up with the correct final answer! Adam
I use an iPad app called Doceri (www.doceri.com) for most of my videos. This app lets you record all your handwriting ahead of time and use "breakpoints" to pause as needed. Once all the writing is down you can "play" the handwriting back while recording audio over it. I find this works much better than trying to write and talk at the same time. I'd definitely recommend checking out the app, I've found it very useful. Hope that helps!
first tell us why we need to perform convolution. Everyone is explaining how it works but why it exists, tell us why convolution comes into existence and how.
Convolution is the fundamental relationship between the input signal and output signal of a linear time-invariant system. It describes how to compute the output of a system, given the input signal and the impulse response of the system. It's used everywhere. Watch the other videos on my channel to see more details.
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took you 10 mins to explain something my university lecturer couldn't!
Glad I could help, thanks for watching. Make sure to checkout www.adampanagos.org/ for additional resources you might find helpful.
tomorrow i have a signal modulation exam and although my english is not that good yet your explanation was super smooth ... Thank you so much!!!
Glad I could help, thanks for watching. Make sure to check out my website adampanagos.org for additional content (600+ videos) you might find helpful. Thanks, Adam
Sometimes it takes a different person to explain it in a different way for it to make sense. You're a hero!
Glad I could help, thanks for watching!
Thank you very very much! Couldn't understand anything about convolution till this video. U are great
Thanks for the kind words, I’m glad you enjoyed the video! Make sure to check out my website adampanagos.org for additional content (600+ videos) you might find helpful. Thanks much, Adam
I used this video to learn convolution two years ago, now I searched this video so hard to help me revise it for a job interview. God bless you!
Glad to hear that. Hope the job interview went well! Best,
Adam
Another thanks to add to the pile. It's been over three years since I've gone through and done a convolution, this was a great refresher.
Great, glad I could help! Thanks,
Adam
I have an exam tomorrow, I actually had this last but we might to use it tomorrow.
I study in french but your basic english and clear explanations made it easy for me to connect the dots.
Keep up the good work.
This guy is going straight to heaven
:D
Where multiple wives await him
72 virgins for this guy
I guess Im asking randomly but does someone know a way to log back into an instagram account??
I stupidly forgot my login password. I would love any tips you can offer me.
I was so sure that I was dropping this class until I came across your videos. thanks a million.
Professor you are a genius in explaining this. Finally I understand how to visualise the mathematics.
Awesome; glad to hear that. Thanks!
you teach better than my prof in school. good work!! Great work!
Your videos on convolution are the best presentation I've seen, University included. Thanks
Thanks for the kind words, glad I could help! Best,
Adam
Great ! english is not my 1st language. Nevertheles, I realy grasped your explanations while writing the sketches on a piece of paper . Thanks a lot Sir ! What you are doing is so helpful.
Thank you very much! You taught me more in 13 min video than my university professor in one and a half hour long lecture.
+Filip Stokic Thanks for the nice feedback, glad you liked it!
great video, I have been searching for few hours and finally got a video that is easy to understand
Great, glad this video was helpful for you. Thanks for watching.
Extremely helpful. You sir, are a saint.
+Poofer Glad to help, thanks for watching and for the nice feedback!
Thank you SO much, Adam! You're a brilliant teacher .
You're welcome. Thanks for the nice comment and thanks for watching.
Very simply and very good explanation. 👍👍👍👍👍👍👍
Thanks for the kind words, I’m glad you enjoyed the video! Make sure to check out my website adampanagos.org for additional content (600+ videos) you might find helpful. Thanks much, Adam
I can't thank you enough! Thanks to you I completely understood the general steps for the convolution between two functions.
Awesome, glad to hear that. Thanks for watching!
Bro you are great teacher!!! Thanks to teach the topic in which i was very confused ❤❤❤
By far the best explanation I've seen for this this. Thank you!!
Glad to hear that, thanks much!
Thanks sir from India....may God bless you....
Glad I could help, thanks for watching. Always makes me happy to know that people throughout the world can see/access these random videos I make. Make sure to check out my website adampanagos.org for additional content (450+ videos) you might find helpful. Thanks, Adam
tomorrow I have a biomedical signals midterm and am using this to understand more complicated convolutions. thanks!
Thank you Prof. I also like to thanks for all these excellent videos. Hope you do more and publish here.
+Mete Yildirim Glad you liked the video. I'm still regularly posting videos to the channel, just the exact topics vary from video-to-video. Thanks for watching.
Adam
Saving Lives !
Thanks!
keep it on.. You r a glory for us.
+1
This is great :) really helped me starting studying signals and systems ahaha Im studying Eletrical and Computer Engineering in Portugal this really helped me a lot thanks hahaha
I study the same thing, good luck bro x) #EngineeringPower
Glad to help, thanks for watching!
dude.. final year engineering and its the 1st time i understand this shit... thank you
Comments like these make me quite happy, many thanks. Make sure to check out my website adampanagos.org where I have additional resources you might find useful, and consider supporting development of new videos through www.patreon.com/agpanagos. Good luck wrapping up that degree!
Adam
+Adam Panagos gonna check it thanks...
you are truly limitless sir respect from moroccoo i love uuu
Thanks for the kind words! Best,
Adam
Thanks, your content is very helpful.
Thank you for the kind words, I appreciate you watching. Make sure to check out my website adampanagos.org for additional content (435+ videos) you might find helpful. Thanks, Adam
nice explanation...very useful lecture adam, and focus on convolution of exp(at) u(-t) * exp(-bt) u(t)
Excellent video! You have really help me understand Convolutions.
+Titurel Glad to hear that, thanks for the nice feedback!
Good video but I wish you showed the plot of y to visualize
a very nice illustration of convolution
Thanks much.
Adam
Excellent!!!! Excellent explaination!!!
Thanks for the kind words, I’m glad you enjoyed the video! Make sure to check out my website adampanagos.org for additional content (600+ videos) you might find helpful. Thanks much, Adam
Great explanation! Thank you so much
You're welcome, thanks for watching. Make sure to check out my website adampanagos.org where I have a lot of other material you might find helpful. Best,
Adam
well explaimned thank you! now i got it. will try some examples on my own! :)
Thx so much from korea
u just saved my life:)
Glad I could help. Thanks for watching!
Adam
I know this is a convolution video and not an integration video but if you would have show the process of integration at 7:20,
people would learn about integration too. Anyway the video is very nice!
yes please, if you solved can you show it
You should definitely know how to integrate if you are doing convolutions though
So good professor.
Great video!
Thank you for the kind words, I appreciate you watching. Make sure to check out my website adampanagos.org for additional content (600+ videos) you might find helpful. Thanks, Adam
how you got the slopes
How did you find the line equations in the beginning?
You saved my ass, friend.
Glad I could help. Make sure to check out my website adampanagos.org for additional content that you might find helpful. Thanks, Adam
Case 3 and case 4 i don't understand but your explanation is very nice
When we sketch the flipped graph, we replace the “tau” with “tau - t” right ?
Thank you very much Adam
I love how im able to get videos like this on the math im studying!
Glad I could help, thanks for watching!
Awesome explanation!
+dekyed Thanks, glad you liked it!
This is so godly
Thank you very much. Mr. Panagos. More than helpful and really well explained. Just have one doubt: What happens when the two triangles overlap completely? Should we calculate them as well for the complete solution?
thank you sir. u are my hero
Thanks!
How do you generally decide what the cases are?
As the shapes slide by each other, anytime a new boundary is encountered the product of the equations changes. So, you have to change cases every time a new product is encountered. Definitely takes some practice!
Adam Panagos But how do you decide t+1
After you've sketched the time-reversed and shifted signal, you "slide" that signal until it collides with the original signal. The front edge of the time-reversed and shifted signal is always at t+1. The back edge of the original signal is at -1. So, the first case occurs for all values of t such that t+1 < -1. It's all about sketching those pictures and keeping track of when the signals "collide" with each other. Hope that helps,
Adam
Adam Panagos Ok I understand thank you so much!
you are a Legend
Thanks!
isnt there a mistake at 2:23 if we take ' 1+ t ' and substitute 't' by (-tau + t) we get '' 1- tau + t '' as the new equation, and the opposite for other side ?????????????????????????????
At 2:23 we had the line 1+tau. The substitution we performed was replacing -tau with t-tau. So, 1+tau = 1-(-tau), and we replace -tau with t-tau to yield 1-(t-tau) = 1-t+tau = 1+tau-t as we had in the video.
Same thing on the other line. We had 1-tau and we replace -tau with t-tau, so we have 1+(t-tau) = 1-tau + t.
Hope that helps.
Adam
@@AdamPanagos I really apreciate your care to answer , your answer makes sense now , so i presume that what i did is wrong ( i took the original equation of that ramp where the varibale was just " t " and since what we did was fliping and shifting so, t => t - tau , and the equation was 1+t from the left ) i watched another video just because of that part where finding the new equations and a guy just substitued in the original equation "t" by "t - tau" , i got your answer, but it's still not clear if i try some other examples , thank you .
In the video titled " convolution example 02" at 2:05 you have substituted "t" by " t - tau" in the original equation , to get the new equation of the " flipshifted " signal , which is confusing me a lot .
@@ghilashamaili2733 No, the video is correct. When doing convolution, we replace "t" with "tau-t". When doing this, I feel it is helpful it draw each step of this transformation so one can keep track of where the bounds of the final integral will be. That's why I first sketch x(tau), then x(-tau), then x(t-tau). Sketching x(-tau) is just the time-reversed signal on the tau axis. Sketching x(t-tau) next just takes our time-reversed signal x(-tau) and shifts it by an amount t. So, in this case, I just keep track of where the time-origin tau = 0 gets shifted to. It will always get shifted to t.
The thing to be careful with is that since we've already done a time reversal, shifting by "t" moves the signal in the opposite direction "from normal".
For example, if we have the signal x(t), and then plot x(t-4), this shifts us 4 units to the right on the t axis. The signals x(t+5) shifts us 5 units to the left.
However, if we're working with x(-t), shifting 4 units to the right means replace t with t-4, which would be x(-(t-4)) = x(-t+4). So, when comparing x(-t) to the signal x(-t+4), the signal x(-t+4) has actually been shifted 4 units to the right. The plus sign "+" on the 4 might make you think it's been to the left, but there is a minus sign on the t.
You just have to be careful to keep track of whether we're dealing with a "normal" signal, or a "time-reversed" signal. If we've time-reversed already, that reverses the direction that we shift for some given + or - value of the shift.
Hope that helps,
Adam
@@AdamPanagos thanks a lot , shifting a reversed signal was the issue , thanks again.
Good video! I'm a little confused as to how many units to move the lower limit when the upper limit is moved
So in essence The equation for a given case is given by: [x(t)*x(t)]*(T2-T1), lets call (T2-T1)=ΔT, so x(t)*ΔT + y(t)*ΔT. Is that correct? So the two areas multiplied with each other within each region?
thanks ,,good job keep it up..
+Arun Kaparwan Glad you liked the video, thanks for the nice feedback!
great explanation! Thanks
+allan rocha Thank you! I appreciate the nice feedback.
Broooo i love you
Glad I could help, thanks for watching. Make sure to check out my website adampanagos.org for additional content you might find helpful. Thanks, Adam
Thank you for a nice video :) I would have simplified the expressions by collecting like terms in the results in case 6
Sure thing, that would be totally fine. I was mainly focusing on the convolution steps in this video, and not so much on how to simplify the resulting terms. Thanks for watching!
I still don't get how you come up with the equations.
For (1+ t) consider x(t) = t : it's a straight line, we time shift this to the left by 1 to get the line x(t) = t + 1, or = 1 + t.
Similarly for the 1 - t line; x(t) = -t, but time shifted to the right: x(t) = -(t - 1) = 1 - t.
When we convolve the triangles together we replace t with T (can't write tau here so I'll use capital T), giving 1 + T, 1 - T.
The other triangle we are time shifting about it's centre t: consider x(T) = 1 + T: here t is 0 because it's simply where it started on the origin. If we change this t to 'slide' them together we also change the equations in time.
So we end up with x(t - T) = 1 + T - t and x(t - T) = 1 - T + t.
I hope I've managed to explain that in a way you can follow.
right at 2:34, were the intercept is a function of t. Let's draw pictures, triangle with t to left of zero, let's say 1/2, so the peak is at 1, the slope is -1 and the intercept is 1/2. I can't see this analytically but as he says, when t is - 1/2, the intercept will be 1/2, which is 1 PLUS (-1/2). So the downward side is - tau + 1 PLUS t.
On the upward side: at t=0, it's tau +1. Let's shift is right, make the peak t=1/2. Now the peak is 1 and the intercept is 1/2. We moved it right, from t=0 to t=1/2 and the intercept went down. So the left side is tau + 1 MINUS t.
This has been driving me nuts.
What would be the convolution of triangle and the square pulse?
Hi, firstly; thanks for these videos, they are very succesfull for us :)
I need to learn " the convolution of u[n] and one signal " , what means this conv ?
sir if you wouldn't mind...how did u do the case 2 integration?my result does not match yours..
when u flip and sketch x(-t) doesnot the value of left side and right side of triangle reverses? i mean at left side it,s t+1 it should be t-1 after the shift
No, the equation of the line on the left side of the triangle is still a line with a positive slope, the labels are correct.
Great video!! By the way are you Greek? your name sounds Greek
Mainly just the name; great-grandfather came to the US from Greece so 1/8th Greek here. Thanks for watching and good luck with your studies! Best,
Adam
when you integrate from t to 1 (third integral), it looks like there should be overlap from both functions? Or not?
For writing and recording, what electronic equipment's used and software. Will you please tell me .
there should be a case where they overlap, right?
Yes, that's handled in case 4 when t = 0. At this point, they completely overlap.
Thanks a lot sir, your videos are extremely helpful, but I have a question. How can I know the number of cases and cases needed to do a convolution? is difficult to me know that.
+Gustavo Alejandro Malvaez Olguin Unfortunately, that's just one of those things that takes practice to figure out. In general, anytime the part of the signal you're dealing with changes equation (e.g. positive slope line to negative slope line for example) or the signal you're multiplying against changes equation then you'll need a new case.
+Adam Panagos Thanks a lot! then, I need more practice! :D
+Gustavo Alejandro Malvaez Olguin Yup, that's just the way it goes sometimes. Definitely some tricky stuff. Hang in there!
Can you recommend some books or articles that will help me to practice convolution? :)
Thank you so much!!
You're welcome; thanks for watching!
you are a god
Thanks for the kind words, glad I could help.
Ehm, in my case I was going to give the TDFT of a triangle y(t)=1-abs(t). Anyway I went and tried to solve it the usual way, but the solution in our book said that y(t)=z(t)*z(t) where z(t) is a rec function with height one and left side on -0.5 and right side +0.5. Dose this make any sense to you? Anyway they later on said that Y(f)=(Z(f))^2 and we know from the mathematical handbook that Z(f)=sin(pi*f)/(pi*f) so naturally we know that Y(f)=sin^2(pi*f)/(pi*f)^2 thus solving the TDFT for y(t)
I know that the books method for finding TDFT is much faster but i dont understand the part where they say y(t)=z(t)*z(t) and is the * in this statment the convulution or just a regular multiplication symbol?
Convolution in time domain, and normal multiplication in Frequency domain for your question. And it is also reciprocal, suppose you have to convolve between two functions in frequency domain, then it is multiplication in time domain.
Aha okay well that's understandable thanx, well now I remember that the handbook also has that principle written down
Thank god, for Laplace...
Dear Prof, May i know what tools you use for screen writing or creating this video...Thanks
+Mete Yildirim I use an iPad app called Doceri (www.doceri.com) for most of my videos. This app lets you record all your handwriting ahead of time and use "breakpoints" to pause as needed. Once all the writing is down you can "play" the handwriting back while recording audio over it. I find this works much better than trying to write and talk at the same time. I'd definitely recommend checking out the app, I've found it very useful. Hope that helps!
why did this take 6 cases and not 5?
brilliant!!!!
Thanks for the kind words. Best,
Adam
oh wow just went to wolfram alpha ...it did the integration in seconds!
+Mohammad Nadeem That's definitely a completely valid way to approach the problem. I was just trying to work through each part of the computation to demonstrate how to explicitly evaluate (and understand) the convolution integral. Hopefully I ended up with the correct final answer!
Adam
Thanks a lot
+Kai Sheng Wang You're welcome, glad to help.
How did you record this movie?
I use an iPad app called Doceri (www.doceri.com) for most of my videos. This app lets you record all your handwriting ahead of time and use "breakpoints" to pause as needed. Once all the writing is down you can "play" the handwriting back while recording audio over it. I find this works much better than trying to write and talk at the same time. I'd definitely recommend checking out the app, I've found it very useful. Hope that helps!
est ce que je peux avoir votre email
Keşke altyazi olsaydi
Samo ga jos zadnji grafik nema ali dobro.
What a fucking god
first tell us why we need to perform convolution. Everyone is explaining how it works but why it exists, tell us why convolution comes into existence and how.
Convolution is the fundamental relationship between the input signal and output signal of a linear time-invariant system. It describes how to compute the output of a system, given the input signal and the impulse response of the system. It's used everywhere. Watch the other videos on my channel to see more details.
@@AdamPanagos Thanks a lot.
lant olsn admım bk gbi vidyo
Thank you very much