MySQL 2 Part

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  • Опубликовано: 31 янв 2025
  • select * from musa order by name asc;
    select * from musa order by name desc;
    select * from musa where name like "%a" "a%" "%a%";
    select * from musa where id between 1 and 2;
    select distinct name from musa;
    SELECT home_type FROM Rooms GROUP BY home_type
    SELECT home_type, AVG(price) as avg_price FROM Rooms
    GROUP BY home_type HAVING avg_price 50
    SELECT family_member, member_name FROM Payments
    INNER JOIN FamilyMembers
    ON Payments.family_member = FamilyMembers.member_id

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