Transitive relations | Relations and Functions | Class XII | Mathematics | Khan Academy
HTML-код
- Опубликовано: 6 сен 2024
- In this video, we will learn what transitive functions are.
Practice this concept - www.khanacadem...
Check out more videos and exercises on Relations and Functions - www.khanacadem...
To get you fully ready for your exam and help you fall in love with Math, find the complete bank of exercises and videos for Class XII Maths here - www.khanacadem...
Khan Academy is a free learning platform for Class 1-12 students with videos, exercises, and tests for maths, science, and more subjects. Our content is aligned to CBSE syllabus and available in Hindi, English, and many more regional languages.
Experience the joy of easy, seamless, accessible learning anywhere, anytime with Khan Academy.
Subscribe to our RUclips channel - / khanacademy
As a 501(c)(3) nonprofit organization, we would love your help!
Donate here: www.khanacadem...
Created by
Aakash Singh Bagga
6:11 why is it not transitive when 2,3 already exist
You are right! There is a mistake in the video, (2,3) is in the set. But still the relation is NOT transitive because if you take (3,2) and (2,3) then (3,3) should also exist in the relation for it to be transitive and (3,3) is absent. Thanks for pointing out the error though!
But why it is wrong? (3,3) is not required, (2,2)is the required one for second checking which is already present in the relation, therefore it is transitive.
Yes@@venkatesh2k5
@@venkatesh2k5 wait wait wait if u take (3,2) as ab then bc will be (2,3) and (2,2) and in the first case ((2,3) one) ac should be (3,3) and to be transitive it should have (3,3) and for the second case ((2,2) one) ca should be (3,2) which exist
so therefore it should have (3,3) as well to be transitive
sir in the practice test there was question, if A={6,7,8} R={(6,6),(6,8),(8,6)} check if it is transitive
according to the answer given it is transitive but according to me on checking the last pair (8,6) i.e a,b then b,c is (6,8) but then a,c is (8,8) which does not exist in relation so it is not transitive. pls help me if there is a mistake
Must be a mistake. Order of elements is irrelevant in sets, so in this case there should be both (6,6) and (8,8) as elements to make the relation transitive. At 3:58 and 13:04 the guy in the video talks about relations similar to yours which he, unfortunately, didn't explore as much as you did. Great observation btw
sir question 5 mein Transitive na hone ka karan (2,2),(2,3) => (2,3) nhi balki (3,2),(2,3) => (3,3) hai as (3,3) is not in the given relation.
Thk sir 🎉🎉🎉🎉
Honestly the best video on transitive relation ❤
Yes
Thank you so much sir
❤
Thank you 🙏🙏🙏🎉
Thanks a lot sir 🤍
❤❤❤❤
What if R={(1,1) (2,2) (3,3) (4,4)} is this a transitive relation ?
Yes bro this is the transitive relation bcz of a property that says that if there is no b,c of that element they by default called transitive exactly like symmetric relation.
@@unidentified2810 what if R={(1,6),(2,7)(3,8)}. How is it transitive??
@@Phoenixrangers kuch bhi🤧🤧
Watching this 1day Before exam