Random number list to run experiment | Probability | AP Statistics | Khan Academy

[@TraceguyRune]

I solved this with math. Look
Her 1st box has a 1/1 (100%) chance of being a prize she doesn't have.
So theres 1 box.
The next few boxes have a 5/6 (83%) chance of being a prize she doesn't have..
So She should buy atleast 1 box.
Now her next few boxes have a 2/3 66% chance of being a prize she doesn't have.
So should buy atleast 1 box.
Her next few bozes now have a 1/2 (50%) chance of being a prize she doesn't have..
So should buy atleast 2 boxes.
Her next few boxes have a 1/3 (33%) chance of being a prize she doesn't have..
So should buy 3 boxes.
Her next few boxes have a 1/6 (16% chance) of being a prize she doesn't have.
So she should buy atleast 6 boxes.
Total: 14

[@nightRanger0077]

Smart dude

[@j2zel]

How would we calculate the theoretical number of boxes needed (without using experimentation)?

[@editsblazing]

Thank you Mr. Khan

[@pinruihuang8463]

Last time I was this early, Khan Academy had the star map.

[@BiswadebM]

It takes 6-9 boxes iykwim.

[@whozz]

It is exactly 14,7

[@melissalopez8362]

Tell me why at the beginning of the video I heard "so we are told that a man that yawns"?

[@jaydenlewis1134]

First