Basic Maths for DSA | Euclidean Algorithm | Strivers A2Z DSA Course
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- Опубликовано: 3 авг 2024
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There is a slight mistake on the logic of Armstrong, it will be 1634 = (1^4 + 6^4 + 3^4 + 4^4), basically digits raised to the power count of digits, so sum = sum + pow(ld, cntDigits) will be the change, where the cntDigits is the number of digits.
Notes:
Count Digits: takeuforward.org/data-structu...
Reverse a Number: takeuforward.org/c-programs/r...
Check Palindrome: takeuforward.org/data-structu...
Gcd or HCF: takeuforward.org/data-structu...
Armstrong Number: takeuforward.org/maths/check-...
Print all Divisors: takeuforward.org/data-structu...
Check for prime: takeuforward.org/data-structu...
Submit the problems here:
Count Digits: bit.ly/3X17nIr
Reverse Number: bit.ly/3vCeBXS
Palindrome: bit.ly/3vylgCi
Armstrong: bit.ly/3vBfkbD
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HCF/GCD: bit.ly/3GB4Mj8
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There is a slight mistake on the logic of Armstrong, it will be 1634 = (1^4 + 6^4 + 3^4 + 4^4), basically digits raised to the power count of digits, so sum = sum + pow(ld, cntDigits) will be the change, where the cntDigits is the number of digits.
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Bhaiya i have good foundation in java can I do these sheet in java lang
@@himanshusharma3382 Han bhai mil ke try karte hai main bhi java Bala hi hun par bhaiya ne bola concept toh same hai par kahi kahi toda muskil hota hai cause c++ ke kuch function java mai nahi hai par toda manage karna padega
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The though topics are fully covered, so stop crying, I will upload at my speed, because I have a full time job, its not easy to work 9 hours and then create content.
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Are you from ap ?
Yee college meru
Iam also from Andhra Pradesh
From Vijayawada, VR Siddhartha Engineering College ❤
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For all those that couldnt get the 1634 test case right in the armstrong questoin, the power of each digit is equal to the no. of digits in the number
for example :
if it is a 4 digit number (1634) , then (1^4)+(6^4)+(3^4)+(4^4)=1634
if it is 3 digit then instead of 4 power will be 3
heres the code:
#include
bool checkArmstrong( int n)
{ string digits=to_string(n);
int digitcount=digits.size();
int num=n;
int r=0;
int pal=0;
while(n>0)
{
r=n%10;
pal=pow(r,digitcount)+pal;
n=n/10;
}
if(pal==num)
{
return true;
}
else
return false;
}
might not be optimal but it is how i tried and it works
yeah u r right even i got this mistake in most of the google search results but chatgpt and gfg gave me the right answer
is this correct as well ?? what about time complexity???
{ int i=0;
int N = 371;
int duplicateOfN1 = N;
int d2 = N;
while(N>0)
{
N=N/10;
i++;
}
int sum = 0;
int digitcount=i;
while(duplicateOfN1>0)
{
int lastdigit = duplicateOfN1%10;
duplicateOfN1 = duplicateOfN1/10;
sum = sum+((int)Math.pow(lastdigit, digitcount));
}
if(sum==d2)
System.out.println("it is an armstrong number");
else
System.out.println("it is not an armstrong number");
}
Actually power =number of digits in the number so try with power 4 it will work .
Thanks it helped
thanks bro!
Thanks a lot Striver for this amazing content. Honestly, the simplicity and the way of enplaning algorithm by breaking them down does help a lot of Beginner Folks to grasp DSA concepts.
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I started preparing DSA and Take you forward is a life saviour! Lots of love Striver.
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tier*
He meant tear only 🥲@@a_maxed_out_handle_of_30_chars
which college ?
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Thanks striver..
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23:55
One correction !!
Armstrong number is the number in any given number base, which forms the total of the same number, when each of its digits is raised to the power of the number of digits in the number.
1634 is not equal to 1^3 + 6^3 + 3^3 + 4^3
it is equal to 1^4 + 6^4 + 3^4 + 4^4
Can u provide the code for it am doing cmath and using pow function to use the number of powers equal to total no. Of digits but in 1634 its giving false
Sir upload videos as much as possible, as our placement season starts from June .Hope I will learn maximum till June 💝💝💝💝💝💝💝💝💝💝😭😭😭😭
Bro did you get placed?
ya bro in toshiba software @@Tihorcreation
@@Tihorcreation💀
#Free Education For All... # Bhishma Pitamah of DSA...You could have earned in lacs by putting it as paid couses on udamey or any other elaerning portals, but you decided to make it free...it requires a greate sacrifice and a feeling of giving back to community, there might be very few peope in world who does this..."विद्या का दान ही सर्वोत्तम दान होता है" Hats Off to you man, Salute from 10+ yrs exp guy from BLR, India...
understood, this guy is an absolute champion!
What a content man! Thank you!
Thanks a lot Striver!! you make very stuff so easy to understand in simple terms..
Sir, you are helping me in doing hard work and making me experience the relief after doing the hard work we get
Thanks for all your support
Only have one request. I know you have been trying to make videos as fast as you can, but actually the placement is in the next 6-7 months, so if you can try to upload the beginner part as soon as possible, it would be beneficial to move for the other playlist of you which you have been uploaded in the past about different topics.
Thank you for all the resources bhaiya(sir).
Did you complete all topics?
Amazing. I loved the GCD part, understood very well. Thank you so much
Striver your video is superb.. and in each video you taught in a very energetic way which makes your video very interesting. All the part in the video is amazing but the last.. i.e. Euclidean’s theorem and reducing loop by half by sqrt.. method is wonderfull.. Now, I try to build-up this type of logic in every Q. to reduce time & space complexity. Thankyou Striver ❤
Hi @Raj sir. Thanks for the video also Congratulations for your 300k subscribers. Looking forward for your more wonderful videos. Truly enjoying. ❤
I really like the explanation, specially the pattern in which you have explained starting from count digits till gcd.
Thank you striver for explaining all the basic math stuff mostly in other courses the instructor assume that we already know they simply explain the code.
started dsa with your this course,thank you!
Congrats Striver for 300K Sub. Let's hope striver see's this comment.
Aniket er bari giye
Aniket er barite code chapo
Thanks alot! Please complete this DSA series for beginners asap. It helps alot for beginners in dsa like us 🙏. The only complain I have from your other DSA playlist is it's not begginer friendly and needs abit dsa knowledge
This year I got Civil branch in my state NIT. Can I understand this course as a begineer and also as a non-cs student?
Also is this playlist is enough for placement or from any other playlist I have to study ?
Yes
Try to complete the strivers a2z DSA course sheet
Your video is very informative. I can learn new things from every video. I knew all of this topic. but your video taught me new things, and how to think clearly. Thank you, sir.
Your amazing playlists specially graph and dp helped me to improve a lot. Can you please create a playlist for CP as well.
very well explained sir i have just started the series and I am getting each and every thing . Your teaching methodology is just insanely superb.
Please asap bring a linked list series as well sir
🙏 🙏 🙏 🙏 🙏 hats off to you, preparing this videos require a lot of time and from your busy schedule you are preparing for us Thank you, Dada.
Great teaching, understood all the concepts effortlessly
I can't believe he is doing this for free, amazing sir. Love from Bangladesh.
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..
im from chennai and love to watch ur lectures and learning through ur dsa sheet bro ..
Congrats striver bhai for 300K subscribers.
Hope it cross million soon.
best one till now!!! 🙏🙏🙏
UNDERSTOOD.......Thank You So Much for this wonderful video........🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻
What a brilliant way of teaching hats off to you and thank you so much for the content ;)
much more needed these topics
1.3 - C++ STL and Java Collection should be a single topic like C++ STL / Java Collection. Not separate topic. So one can move forward with everything checked.
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Perfect and simplest explanation found ever
understood the assignment :) thanks striver
very clear and crisp explanation.
Excellent Sir,My honorable thanks for making these videos with excellent explanation❤.
It's great to learn from this channel ❤️Thank you:-)
no one teaches maths in theire dsa course...this is indeed an AtoZ dsa course.. blessed to have it❤
Great content for any professional or an engineering student❤💯. Thank you sir for taking this much of efforts 💯
Hey Striver, I am a 5th semester student of a tier-3 college, first of all thankyou for all your videos, I have completed your graph series, almost completed your SDE sheet. I needed your help so I joined your channel. I see that your last members only post was a year ago, I understand that u have a full time job and therefore you are busy. I just wanted to know if you will continue making meeting sessions, because I need your guidance. Thanks again for your hard work.
Thank you Striver!
thank you so much for creating this playlist
Understood, thanks for your hard work.
thank u so much for a wonderful video !
great content!
I was waiting from last 5 days. Finally come 😌😌
Amazing. I understood very well
so far, this is better than the paid courses 🔥🔥🔥.
Thank you striver. Basic maths completed. Coded along with you. Made the notes for the lecture .
Can you send me notes pdf??
Raj, Thanks a lot for This Amazing Video about C++ Basic Maths
Lecture - 7 Completed ✅
@Striver
Great Way! Understood completely
I never though i will be able to solve these so easily, thanks a lot striver for make it very very simple and easy to understand.
Euclidean algo is so easy this way...
@@mizzzile yes 🥹
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your teaching skills are awesome bro
Striver is an inspiration ❤️
amazing way of explaining stuff
Understood, Thank you so much!!!
very nicely explained!!
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u r god !!
beast!!
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Very nice explanation...God Bless You
understood, and it is time to practice by myself!!
Understood well!
Understand, superb video, keep up ♥
Great way of teaching
Unstoppable striver for a reason 🙌❤
God bless you brother, i am in better place all thanks to you!!!
Understood, Thanks for this amazing content
understood everthing great video sir
understood striver :) thank u for this wonderful lectures
started working on this a-z dsa course.. Have a job but want to start over these topics .. To switch to a better one!!!
Amazing Video!!
Waiting for this one from morning 🙂
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Bhaiya maza aa gya
Fully understood 😃😃
Congrats For 300K Subscribers Bhaiya
Beautiful algorithm
In the eucledian algo why we are taking min(a,b) in time complexity like the time complexity should be logphi(max(a,b))
Because we take max of a, b and divide that.
Like in count digit we write log10(N) where N is the number divided by 10, so here max(a,b) is the dividend in eucledian algo
Mind blowing content❤❤
great content! understood.