Great video as always! Although the intermediate with taking the 1/2 out to make the 1/20 coefficient wasn't necessary. I guess this was just to get us familiar with more complex solutions?
At 4:16, why did he multiply the numerator by 1/2 but then didn't do the same outside the integral? Instead of doing "1/20 x 1/2" outside, he did "1/20 x 2". Im confused....
if you substitute dx = 2du, you get 2/(u^2+1), and then you take the 2 out, so its 2/20 integral of 1/ (u^2+1) du, so both ways will get you to the same answer. Hope this helped!
The Adel that doesn’t change anything lol, taking out the 5 just makes it easier to work with. You only made it harder for yourself also you solved a problem while already knowing the answer which is much easier btw.
You just made things a bit complicated. You can actually proceed on doing the u-substitution after you complete the square, you'll still get the same answer. No more re-engineering.
Great video as always! Although the intermediate with taking the 1/2 out to make the 1/20 coefficient wasn't necessary. I guess this was just to get us familiar with more complex solutions?
Beautiful integral! Thanks for the help!
Finally i found a video tht helps a lot
wow, thank you for this
Thank you so much!!!
At 4:16, why did he multiply the numerator by 1/2 but then didn't do the same outside the integral? Instead of doing "1/20 x 1/2" outside, he did "1/20 x 2". Im confused....
if you substitute dx = 2du, you get 2/(u^2+1), and then you take the 2 out, so its 2/20 integral of 1/ (u^2+1) du, so both ways will get you to the same answer. Hope this helped!
me too I don't understand
If you want both sides stay equal you must do what Sal did. Try it yourself. First it was 1 x 1/20 = 1/20. Theo he changed it to 1/2 x 1/10 = 1/20.
Thank you for explaining this so well. I found so many videos that skipped steps in the same type of calculation.
Why wouldn't you take the natural log of the denominator?
Thank you. This was very helpful. :)
why cant you have 5x^-2 -30x^-1, etc. why cant it all just be negative powers?
I love you man. I love your work. God bless you a million.
How can we intregal dx/x2+6×+8
u do partial fraction
a/(x+2) + b(x+4)
Great explanation - clear and precise
thanks
Thanks sir
great from egypt
thanks egypt
Wow . that was really nice
You saved my mind. I was getting closer to a collapse trying to solve a similar question.
Greaat👌
What happens if there is an X on the top
You just do regular U-substitution. Letting the trinomial be u. You should then be able to integrate using substitution.
just a bit complicated huh...
I bet there’s an easier way but sal presents the complicated ways most of the time
I solved it without taking 5 and 2^2 out
The Adel that doesn’t change anything lol, taking out the 5 just makes it easier to work with. You only made it harder for yourself also you solved a problem while already knowing the answer which is much easier btw.
You can use the formula int(1/(x^2+a^2)=arctan(x/a)
You can actually perform the U-substitution right after you complete the square. No need to factor a 4 on the denominator like the one in the video.
I love hairy!
Thanks, that was sweet.
Can you also please make a video for the integral of sin(6x)cos(3x)dx.
........and we are done. Drum row
you're a rad, mad, thunder attack
I’m going to fail...
same bro
lool same here
lmaao same energyy
F
same
You just made things a bit complicated. You can actually proceed on doing the u-substitution after you complete the square, you'll still get the same answer. No more re-engineering.
life sava brah
di 3:13, bukankah 1/5 diluar integral menjadi 4/5 ,karena kedua sisi dikalikan 1/1/4, tolong bantuannya kawan, agak membingungkan 😔
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Thanks