Wow! This video was put together beautifully and I really appreciate you helping by making this topic simple for me to understand. This video has gotten me through the hardest times, every hurdle had in my life, I wouldn't be able to get through electrochemistry if it weren't for you Mr. Chad
I have already watched many of your chemistry lessons, they are of high didactic value. My compliments and all respect for your efforts. I am a retired engineer and still look with great passion to science (physics, mathematics, chemistry, computer science, etc.) Best regards!
thanks for simplifying this. when it comes down to it the math and the logic aren't that difficult, but i appreciate the clarity of your lecture (like all ur others)
ur a goat for this 🙏 thank you so much, your channel genuinely helps me sooooo much! you have a great talent for teaching that my professors don't have 😭😭
If you have a question that says /Hydrogen peroxide is added to an aqueous solution containing VO2+ ions. calculate the E cell value. Use your answers to predict wheather or not a reaction occurs. Basically if it doesnt tell me if something is feasable or not how do I tell what is being oxidised and what is being reduced
Question, (and thanks for answering my previous one!!!) Wouldnt technically Al+3/Mn be the one to react? Once i write the balanced equation for Al/Mn+² and calculate 3cell it comes out as negative voltage The balanced eq: 2Al + 3Mn+² → 2Al+³ + 3Mn. 1.66 x 2 = +3.32v (2Al) -1.18 x 3 = -3.54v (3Mn) Or these questions dont take into account a complete reaction and is rather 1Al reacting with 1Mn?
The coefficients in the balanced reaction will not affect the calculation. It should simply be: 1.66V - 1.18V = 0.48V A Volt is a Joule/Coulomb. So it is scaled per Coulomb. Doubling a half reaction will double the delta G value in Joules, but it will also double the number of electrons transferred and so also double the Coulombs. As a result, the Volts will NOT change at all. I worked an example in the lesson to demonstrate this also. Hope this helps!
Thank you this was very helpful but I'm curious if we need to cram the reduction table or it'll be given in the exam question cus idk if i can remember that table and all over the accurate values
Hi Chad i saw on my teachers slide that the oxidizing agents are the ones highest on the list and the reducing agents are the ones towards the bottom, but here it looks like its different so im a little confused
How does any of this work with organic batteries? Like the battery using the oxidation of hydroxyquinones to quinones? (I think it's otherwise known as the rutabager battery?) I do not see a charge change for =O vs -OH groups. Does it matter if it's in aqueous vs non aqueous solution? Is there a table of redox potentials of covalently bound functional groups in organic molecules? Would an aromatic sulphur ylide in dsmo work similar to a quinone in aqueous solution electrochemically?
I'm curious if you're a Christian because I noticed you wearing a shirt with a Bible verse on it in one of your videos. If you say yes, I'm even happier since you're a fellow brother in Christ, if not that is also fine. You are not only a genius, but also a man of God, who uses his God-given abilities to help us all. May the Lord bless you with many years of good health and success.
![19.5 How to Calculate Nonstandard Cell Potential [Nernst Equation] | General Chemistry](http://i.ytimg.com/vi/Ma0TC3V9bdI/mqdefault.jpg)
![19.5 How to Calculate Nonstandard Cell Potential [Nernst Equation] | General Chemistry](/img/tr.png)
One of these days I'll start watching videos like this *before* the last two days before the final. Thanks for making this easier to understand.
Very welcome.
possibly the best channel on youtube for this sort of information, explains everything needed to know, thank you a million times over man!!!!
You're welcome, DzzyHD!
Wow! This video was put together beautifully and I really appreciate you helping by making this topic simple for me to understand. This video has gotten me through the hardest times, every hurdle had in my life, I wouldn't be able to get through electrochemistry if it weren't for you Mr. Chad
Glad the video helped you!
I could never find a better Chad! Thanks for making chemistry awesome!
You're welcome and Thank You.
4:08 OMG TYSM i've been looking at my questions wondering why they didnt change the sign but u cleared it up! You're a chad for this!
Glad the channel has helped you!
I have already watched many of your chemistry lessons, they are of high didactic value. My compliments and all respect for your efforts. I am a retired engineer and still look with great passion to science (physics, mathematics, chemistry, computer science, etc.) Best regards!
Thank you and Glad the channel is of value!
Top two of the best chemistry channels out there! definitely helped me out alot!
Glad to hear it - Happy Studying!
What’s the second?😅
@@TheRooflesstoofless Organic Chem Tutor
@@chethiyabandaranayake1759 agreed 👍. I’ve used that one extensively
Thanks, Chad, your material has really helped me learn and understand my material in class better.
You're welcome, Katie - Happy Studying!
thanks for simplifying this. when it comes down to it the math and the logic aren't that difficult, but i appreciate the clarity of your lecture (like all ur others)
You're very welcome!
Hi Chad. Is there any way we can donate through patreon or something? You've helped me so much :)
His website
Love this video and chanel... I'm so excited about the physics videos also being released, because I start that journey next semester.
Love the enthusasim!
CHAD YOU'RE THE GOAT
Thank you
This is wonderful 😭, I was super confused. God bless you ❤
Glad the channel helped you!
Did you get a new camera? This video looks real sharp brotha. Thank you for doing what you do man
Indeed I did and I LOVE it! Glad you find these helpful!
Very Very Helpful. Thank you so much for such a good explanation. Now I completely understand REDOX reaction.
You are welcome!
ur a goat for this 🙏 thank you so much, your channel genuinely helps me sooooo much! you have a great talent for teaching that my professors don't have 😭😭
Glad I can help! Happy studying 😊
Chad!You really are a CHAD👑
Happy Studying!
Chad is my hero! I wish that he was my chemistry professor.
Thank you.
Youre amazing you exactly said things i was struggling in
Excellent!
This video was really helpful. ❤️
Excellent!
You're the hero of my grades
All the best!
at 10:50, I'm confused on why the number is -0.74 and not -0.41 because that's what's shown in the data booklet
If you have a question that says /Hydrogen peroxide is added to an aqueous solution containing VO2+ ions. calculate the E cell value. Use your answers to predict wheather or not a reaction occurs.
Basically if it doesnt tell me if something is feasable or not how do I tell what is being oxidised and what is being reduced
Hello do you have a playlist for electrochemistry
Question, (and thanks for answering my previous one!!!)
Wouldnt technically Al+3/Mn be the one to react?
Once i write the balanced equation for Al/Mn+² and calculate 3cell it comes out as negative voltage
The balanced eq: 2Al + 3Mn+² → 2Al+³ + 3Mn.
1.66 x 2 = +3.32v (2Al)
-1.18 x 3 = -3.54v (3Mn)
Or these questions dont take into account a complete reaction and is rather 1Al reacting with 1Mn?
The coefficients in the balanced reaction will not affect the calculation. It should simply be:
1.66V - 1.18V = 0.48V
A Volt is a Joule/Coulomb. So it is scaled per Coulomb. Doubling a half reaction will double the delta G value in Joules, but it will also double the number of electrons transferred and so also double the Coulombs. As a result, the Volts will NOT change at all. I worked an example in the lesson to demonstrate this also.
Hope this helps!
Thank you this was very helpful but I'm curious if we need to cram the reduction table or it'll be given in the exam question cus idk if i can remember that table and all over the accurate values
The only value I've seen students required to memorize is zero for the Standard Hydrogen Electrode. Hope this helps!
Can you please give the link of the video where you have explained di substituted, tri substituted alkenes ?
Hi Chad i saw on my teachers slide that the oxidizing agents are the ones highest on the list and the reducing agents are the ones towards the bottom, but here it looks like its different so im a little confused
Then those where the oxidation potentials
How does any of this work with organic batteries? Like the battery using the oxidation of hydroxyquinones to quinones? (I think it's otherwise known as the rutabager battery?)
I do not see a charge change for =O vs -OH groups. Does it matter if it's in aqueous vs non aqueous solution? Is there a table of redox potentials of covalently bound functional groups in organic molecules? Would an aromatic sulphur ylide in dsmo work similar to a quinone in aqueous solution electrochemically?
ur the reason why im not failing ap thank you
You're very welcome - Happy Studying!
Very helpful thank you very much teacher.
You are very welcome.
Chad is my light in the darkness,
Glad the channel is helping to illuminate!
Thank you brother the first part of the video probably saved 50% of my grade on this test. My teacher explained that concept so badly 😢
Glad it helped!
how do you know that the Zn is the cathode??
It's the strongest reducing agent thus it gains electrons at the cathode (cations)
Nice explanation frm 🇮🇳
Thanks from AZ
awesome video!
Thanks, Brent - glad you think so!
Love ❤from india sir
Thanks from USA!
Thank u professor 😊
You're very welcome!
Thank you!
Welcome!
great video
Thank you
you are the best!!!!
Thanks!
Very Helpful! Thanks
You're welcome!
thank you
you're welcome
Nice sir!
Thanks!
so nice
GOAT!
Thanks!
I'm curious if you're a Christian because I noticed you wearing a shirt with a Bible verse on it in one of your videos.
If you say yes, I'm even happier since you're a fellow brother in Christ, if not that is also fine.
You are not only a genius, but also a man of God, who uses his God-given abilities to help us all.
May the Lord bless you with many years of good health and success.
I luv u💋
Thanks!
Thank you, very helpful!
You're welcome!