My background is biochem, and I need to understand the concept of B-E distribution before coming to my condensed matter physics tomorrow. I really appreciate your high quality lecture. Now I've become a big fan of nptelhrd channel. Keep up the good work, professor. You rock!
i know im asking the wrong place but does any of you know of a tool to log back into an instagram account..? I was stupid lost the login password. I would appreciate any tips you can give me
Thank you so much .......... I spent almost 4 hours on an almost 52-minute long video ..... Every word and sentences were explaining the best of the equation itself ........ I didn't even realize I have spent 4 hours. thank you for such a beautiful explanation......
I must say that the derivation at 35:01 seems illegitimate to me. The individual sums we got this greater sum from are true exactly because of offsets: so, total δn is conserved precisely because δn_i is to be offset by some δn_j. And the same goes for the energy. To speak of δns being fixed honestly just sounds like it’s the same as considering a macrostate that doesn’t change. And I also don’t think I see how any idea about δn being a high number approximation helps.
May I ask a stupid question? Presumably one is familiar with the BE medium here. So doesn't one have knowledge of the state spectrum, s_i? Why does it appear more like a variable
Higgs Boson is named after #Bengali scientist #SatyandraNathBose .must given #NobelPrize #Holiday for #SatyandraNathBose birthday. #He is really #God #Godaparticle
Another method (n1,n2,･･･nk):distribution (,,･･･,):disrribution in equilibrium probability P(n1,n2,･･･,nk)=(N!/Πni!)Πsi(si+1)･･･(si+ni-1)･exp{-(α1+α2･･･+αN)}･Πexp(-βεi)^ni αN:N is the subscript of α In equilibrium, P(,,･･･,)=Pmax Since P(･･･,+1,･･･)≒P(･･･,,･･･)=Pmax P(･･･,+1,･･･)/P(･･･,,･･･)≒1 Therefore P(･･･,+1,･･･)/P(･･･,,･･･)=(N+1)(si+)exp(-αN-βεi)/(+1)≒1
N+1≒N, +1≒ → N(si+)exp(-αN-βεi)/≒1 (1) Accordingly ≒N(si+)exp(-αN-βεi) And N=Σ=Nexp(-αN)Σ(si+)exp(-βεi) ∴ exp(αN)=Σ(si+)exp(-βεi)≡ZN ZN:N is the subscript of Z Therefore αN=ln(ZN) By using (1) /si≒1/{(1/N)exp(αN+βεi)-1}=1/{(ZN/N)exp(βεi)-1}
Suppose that / represent partition & 0 as the states case1) 5-/ & 5-0 this can be arranged as 0/0/0/0/0/_ or _/0/0/0/0/0 in above both _ gets left if we take same no. of states & partitions case2) 4-/ & 5-0 so 0/0/0/0/0 or 00/0/0/0/ or 0/0/0/0/00 here there is no _ left. So we take -1.
My background is biochem, and I need to understand the concept of B-E distribution before coming to my condensed matter physics tomorrow. I really appreciate your high quality lecture. Now I've become a big fan of nptelhrd channel. Keep up the good work, professor. You rock!
i know im asking the wrong place but does any of you know of a tool to log back into an instagram account..?
I was stupid lost the login password. I would appreciate any tips you can give me
Sir, your explanation about Maxwell-Boltsmann & Fermi Dirac & Bose-Einstein statistics--- all are Excellent.* Thankyou sir*
Thank you so much .......... I spent almost 4 hours on an almost 52-minute long video ..... Every word and sentences were explaining the best of the equation itself ........ I didn't even realize I have spent 4 hours. thank you for such a beautiful explanation......
Your lectures are very insightful. The story of 2.7K at 48:00 is very interesting.
Mathematics is such a beauty. thank you sir for the lecture.
The lecture is really good! A standard level of lecture.
The only video which satisfied me with the explanation of arrangements.. . Otherwise calculation are simple mathematics...
Fascinating presentation of Bose Einstein statistics
Excellent! Thank you so much!
I finally understood this theory, thanks a lot
Thanks for uploading...
Your explanation is the best to understand so far i have checked it in youtube....
Finally i have understood this theory.Thank you sir.
बहुत बहुत धन्यवाद आपका।
@ 37:16 If the chemical potential is zero (for photons), we get back Planck's Law (BB-radiation = photons).
Thanks a lot Sir.
I liked the information at end.
Skillfully explained
amazing !! you have saved my grades...
just want to say thanks for this
I must say that the derivation at 35:01 seems illegitimate to me.
The individual sums we got this greater sum from are true exactly because of offsets: so, total δn is conserved precisely because δn_i is to be offset by some δn_j. And the same goes for the energy.
To speak of δns being fixed honestly just sounds like it’s the same as considering a macrostate that doesn’t change. And I also don’t think I see how any idea about δn being a high number approximation helps.
You have been a blessing ! Thank you
Excellent sir, may you recommended me what the textbook of statistical physics for undergraduation? Thanks a lot for your lecture
Thank you sir . You makes it easy to understand.
May I ask a stupid question? Presumably one is familiar with the BE medium here. So doesn't one have knowledge of the state spectrum, s_i? Why does it appear more like a variable
Excellent lecture. Thank you sir.
Higgs Boson is named after #Bengali scientist #SatyandraNathBose .must given #NobelPrize #Holiday for #SatyandraNathBose birthday. #He is really #God #Godaparticle
thank you sir
thanks sir ji and nptelhrd......
Thank you so much sir!
Sir you are excellent explain
What if n_i>s_i then probability of occupancy becomes larger than 1! 10:18
can you tell me the name of the probability formula you used ..
I'm confused,what does "sigma I" stand for in the final equation
Very well explained, thanks.
I feel guilty that I didn't search for this in youtube while I was taking the course.... 🤯
Very nice.
Good Lecture sir
thanks...keep uploading your lectures.
Thanks sir, it is very helpful
And finally UPSC has asked it !!
what
Thank you sir it was very useful lecture for d students
great lecture...
Another method
(n1,n2,･･･nk):distribution
(,,･･･,):disrribution in equilibrium
probability
P(n1,n2,･･･,nk)=(N!/Πni!)Πsi(si+1)･･･(si+ni-1)･exp{-(α1+α2･･･+αN)}･Πexp(-βεi)^ni
αN:N is the subscript of α
In equilibrium, P(,,･･･,)=Pmax
Since P(･･･,+1,･･･)≒P(･･･,,･･･)=Pmax
P(･･･,+1,･･･)/P(･･･,,･･･)≒1
Therefore
P(･･･,+1,･･･)/P(･･･,,･･･)=(N+1)(si+)exp(-αN-βεi)/(+1)≒1
N+1≒N, +1≒ →
N(si+)exp(-αN-βεi)/≒1 (1)
Accordingly ≒N(si+)exp(-αN-βεi)
And N=Σ=Nexp(-αN)Σ(si+)exp(-βεi)
∴ exp(αN)=Σ(si+)exp(-βεi)≡ZN ZN:N is the subscript of Z
Therefore αN=ln(ZN)
By using (1) /si≒1/{(1/N)exp(αN+βεi)-1}=1/{(ZN/N)exp(βεi)-1}
Very nice lecture
Thanku Sir !
how the temperature is related to the B-E distribution??
en.wikipedia.org/wiki/Bose%E2%80%93Einstein_statistics
Awsome
Watching this video after 12 years of uploading.🎉😂
Hi sir!
Sir plz email your this notes send plz I need bc tomarrow our assignment.
❤
Super
very good👍👍👍👍
All that fuss about (Si-1)..... and then when it comes to calculate it... you just say they are too large , lets just use Si .. :) :)
Nyc 👌👌
😊
no entender ingles
me gustaria que tubieran subtitulos en español para poder aprender en el idioma español tambien :(
Too long
oh too gud
STILL CAN'T understand y we less one state
Suppose that / represent partition & 0 as the states
case1) 5-/ & 5-0
this can be arranged as 0/0/0/0/0/_ or _/0/0/0/0/0
in above both _ gets left if we take same no. of states & partitions
case2) 4-/ & 5-0
so 0/0/0/0/0 or 00/0/0/0/ or 0/0/0/0/00 here there is no _ left.
So we take -1.
@@prachi579 Thankyou so much 👍
Such subtle grammatical errors are not welcome
Very bad video quality
Thank you sir
very nice lecture