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MIT Entrance Exam Problem from 1869
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- Опубликовано: 11 янв 2022
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I wish these kind of questions came in Indian entrance exams 😂😂
Probably did at some time, lol just like these came in mit entrance 200 years ago approx
No they didn't @@Blue_3987
Bro u just forgot about jee
Jee has nothing like these questions..they dump calculus@@user-dt1dr9ew6j
😂❤@@user-dt1dr9ew6j
This is proof that each year kids are expected to learn more at a faster pace. Thank you for 5000 likes.
Well it’s a good thing
Yes@@jjj-11
Yes even our parents generation has easier questions than us to study
@@jjj-11 Nope , it aint
@@Mari143 How will continued innovation come if future generations are never expected to surpass the previous?
Why is nobody in comment section understanding that this its from *1869* nearly 150 years ago
Yea but calculus was invented almost another 150 years before that.
@@mythily6374calculus was arguable invented in like 600
@@Jake-cc7ie yep to be exact it is 155 years
Because first human brain try to put there joke on comment after that they will notice there environment.
Not nearly 150, it's 155
To those saying it's too easy: well, that's the point. Back then, college admission wasn't competitive, because only a handful of people had the time and money to travel to Cambridge, Massachusetts and spend years without a job. So the only purpose of exams was to assess whether you have the basic aptitude needed to learn the stuff taught at MIT, not to decide which highly qualified candidate was better than the 100 other candidates vying for the same position.
Mit still too easy not just this old one
Americans are not very smart it's a common thing that people can bond over is making fun of Americans I did this level of mathematics I think when I was 16 lol imagine giving American high schoolers this work to solve in high school and they couldn't finish high school without passing math lol it'll be record high dropouts
Also since it was from 1869. It could be fucking hard as how many during those times had access to schools
@@HarrowKrodarius You know we weren't cavemen banging rocks together before the internet right? I get what you are saying but this is literally a regular algebra 2 question lol
Books existed, other knowledgable people existed...if nothing else, I'd still say those are the best resources to learn stuff given how trash google search results have been for like the past decade
@@HarrowKrodarius the vast majority
The average 12 year-old Indian schoolkid can solve this.
Edit : 7,000 LIKES !!!!! Oh My Gaaaa I'm famoooooos !
Turkish child too
Give them JEE advance problem
Bruhh yess I'm 14 and I could do it
It seemed easy
I wonder if it's really MIT question paper
I'm from 🇧🇩
its from 1869.and its an entrance exam question not the whole question paper. and people who are saying them to solve jee questions, i wanna ask them does jee gives you a chance in getting mit.nope.with time standards changes
@@Connie_999-h6w yes it is.and don't get cocky because this is just one question not the whole paper.its from 1869 standards back then were different from now
In 1869 there was no internet, good books , nor people were forced to study and course that u study this time wasnt developed like today so this was a high level question at that time and this question is at super hard level according to their standard
Vs now where we see this in algebra 2
This put a perspective on how for example those scientists were so good
@@cr7savage709Algebra 1 if your teacher is on a bad day
Are you out your mind? People were indeed forced to study and pretty advanced math was going on in late 19th century
Bruh just cuz there isn’t internet doesn’t mean u can’t learn from books
I guess I’m the only one who didn’t think this was easy
Me too buds lol
If you learned Algebra 2, you would find this problem pretty easy. Like a textbook problem the teacher just casually hands out.
@@unspecifiedunit9126 low key never did algebra 2. Did intermediate algebra in college then jumped straight into precalc/calc1
same but I have an excuse, I didnt go to school
Because your fucking dumb ass aneyone can solve this even my dog😂
I wish they would have entrance exams like these nowadays.
Maybe a hefty degree more difficult for good measure 😂
You wish not. If the questions are that easy, everyone will get it, but doing a mistake is going to be just a coin flip. You can't really outstudy an easy exam.
@@gteixeira Very true. For many of our school's science olympiad competitions, close to the end of the year, most of the students are so well-versed in the concepts tested that even one mistake can take you out of the top 5.
It was never easy, this same problem must have been real difficult for them at that time just like our difficult problems would be a piece of cake for a kid of 2300s
It will result in crazy cut off
If today's level was in 1869 then the difficulty increase in today's level exam paper would require everyone to become scientist to clear them.
If that is a MIT question, im Albert Einstein 😋
This was 1869
Lmao
😂
❤
Are you getting the credit for all your peers effort and get praise based on your ethnicity?
Education has gotten to a point where you see an easy question like this, proceed to overthink it, then realize it was actually not that hard after you struggle to approach it. School has traumatized a lot of students into doubting themselves when approaching questions and this is evidence of me being said student. Damn.
Well I always wonder why the hell they introduced Alphabets in Maths?
@@AnimeFusionUpdatesz 🤣
@@stephanedwards3083 I know it's for problem solving but what problem?
@@AnimeFusionUpdatesz letters are simply placeholders for unknown variables or constants that we would rather left unwritten. For example, g which represents acceleration due to gravity. 9.81 m/s^2. That’s pretty much all they’re useful for.
@@stephanedwards3083 I don't even understand any of this
I got 4 out of 15 in maths
But got 14 out of 15 in English
I don't understand why I can't do good in Maths
The fact that I have no idea what I’m looking at is concerning 😭
What age are you?
Dude i learned this when i was 12 😨
You made that so much more complicated than it needed to be 😭
its about showing your work
this is literally the quickest way to solve the question😂
What's a simpler way to solve it?
@@6IGNITION9we directly cancel them 😊😊😊
@@6IGNITION9 easy. cancel out the exponents and check what will be left.
these kids think by solving a qs from 1869 will make them smarter than MIT people. Ngga most modern mathematician nd physicists weren't even born at that time😭😭
So /real/ mathematics hasn't existed since modern mathematicians have been born?
Ask for an n word pass. Do not ask me, My response is no.
@@gteixeiraThat doesn’t make sense. So the field of math since 1869 hasn’t developed?
@@gteixeirawhat are you on about
Me being out of high-school for 4 years tryna figure out wtf he talking about.
It's factoring. Look at the numerator and denominator as separate. You're just rewriting and not doing any hard calculation.
math is all about practice really, 4 years no practice I would have forgotten everything. It's the way one SEES mathematics that allows success.
@@bungus49that’s the most recognizable cow…
Useless stuff.
@@windshearahead7012 lol don't feel too bad that u stupid.
Mathematics then : 🗿
Mathematics now : 💀
INDIANS in Exams🗿🗿.
Indians Practical Knowledge🤡🤡🤡
You've left unaccounted the case when (x^3 + a^2 y) = 0
why is there always some annoying asian kids flexing in the comments of these video. well done, you can solve a maths problem for high school students from the mid 19th century, so can everyone else.
Ikr. It’s so dumb. In 200 years from now, the same people will be laughing at how simple our current math is lol
@@Allenz2205 the math right now is actually very advance , even in colleges we read the math they did 200 years ago
It's mostly because around the world the education system actually teaches you a thing or two. I'm born and raised mostly in Canada but did a few years of school in Romania, and this problem I can tell you for certain that someone in grade 5 could solve without difficulty, whereas here I'm sure most people who even graduated highschool here might struggle. It's not necessarily that they're flexing, it's more that they're laughing at how stupid NA's education is.
Not just any Asian, it's ( most of the time) an Indian guy
@@canadianave7361 Hmmm then I wonder why NA continues to lead the world in technology and advancement
To simplify the given expression to its lowest terms, let's start by factoring the numerator and the denominator where possible.
The given expression is:
\[
\frac{x^6 + a^2 x^3 y}{x^6 - a^4 y^2}
\]
### Step 1: Factor the numerator
The numerator \(x^6 + a^2 x^3 y\) can be factored by taking \(x^3\) common:
\[
x^6 + a^2 x^3 y = x^3 (x^3 + a^2 y)
\]
### Step 2: Factor the denominator
The denominator \(x^6 - a^4 y^2\) is a difference of squares:
\[
x^6 - a^4 y^2 = (x^3)^2 - (a^2 y)^2 = (x^3 - a^2 y)(x^3 + a^2 y)
\]
### Step 3: Rewrite the expression with factored forms
\[
\frac{x^3 (x^3 + a^2 y)}{(x^3 - a^2 y)(x^3 + a^2 y)}
\]
### Step 4: Cancel the common factors
The term \(x^3 + a^2 y\) appears in both the numerator and the denominator, so we can cancel it out:
\[
\frac{x^3 (x^3 + a^2 y)}{(x^3 - a^2 y)(x^3 + a^2 y)} = \frac{x^3}{x^3 - a^2 y}
\]
Therefore, the simplified expression is:
\[
\frac{x^3}{x^3 - a^2 y}
\]
This is the expression in its lowest terms.
Be careful! You also need to make a note that this simplification excludes all cases where x^3 + a^2 y = 0. Of course, in the SAT won’t matter much, but in college it will when you must give handwritten answers.
Bro the denominator can't be 0
@@FervifIt can be, but since the question asks to reduce to the lowest terms, the existence of the denominator seems to be implied for a simplification to even take place, i.e. it doesn't matter for _symbolic_ manipulation.
You mean where (x^3 - a^2y) = 0
@@FervifThat’s the point in stating that all values where the denominator = 0 must be excluded for the simplification to be valid
you could also just subtract everything then flip what’s needed under/ over the denominator and you would get the same answer
Thank you. 🙏🏽
Trivial Factor x^3 from the numerator.
Factories th3 denominator using the identity a^2-b^2=(a-b)(a+b).
You’ll obtain x^3/(x^3-a^y)
As an mit applicant from 1869, i can confirm i have no idea what’s going on (but daddy’s a millionaire)
Did you live for 100 years or what?
😂😂😂😂😂😂
Did it in my head. Felt good about myself. Reassuring to know they haven’t admitted me for nothing. #MFin #ClassOf2017
As an average asian teen . This is too easy for me
1869 y
@@masterchiefpettyofficer1176 yeah
That is a reason
not really
super easy, barely an inconvenience
I'm literally 11 and this is easy lol
First problem I could actually solve
Every time you go on ANY math related video, especially around old entrance exams, SAT and ACT videos, you will without fail find some Indians say "bro so easy try Jee advanced". But its like they completely ignore context. In 1860 the common person did not go to university so competition was lower. SAT / ACT are not meant to be advanced mathematics tests for engineering students, its only function is to see if you meet the basic level to go to university and at the university, depending on your major, you will take advanced mathematics. Just taking some unnecessarily hard math test to try and get into a university thats not even a top contender in Asia doesn't mean anything.
Unfortunately, as an Asian, the focus is heavy on stem…but very light on critical thinking and reading comprehension. It’s why PhD/ and whole drs will believe random shit they see on whatsapp
As an 18yrs old Indian boy, I can confirm that I used to do this when I was in my mother's womb.
As an average indian boy, I can assure you that when my father screwed my mom, only the sperm that could solve this problem was allowed to impregnate my mom's egg
I agree 💯
😂😂😂
Feature of a fetus 😂😂😂
Good work mate 👍
Me as a designer: "Sooooo...does anyone need a logo?"
😂😂😂
Actually
There is one shortcoming.
You have to be sure that X^3+a^2*y is not zero l, otherwise the simplification is not correct.
This is the trick and the reason why people would fail such a test
wait but how would that affect the answer because youre cancelling it from both the numerator and denominator
Even if you are cancelling, the denominator can’t be 0 at any stage of the work
Well said
Click bait bullshitter - will be damned after our machine overlords have swamped the earth will bullshit to end the old and build something new and better. I'm just kidding. We'll just drown in it and that's that.
when x^3+a^2y is 0, the original fraction is 0/0 and therefore undefined. your simplification only has to match the original question on its domain (which it does), you just can't use your simplification's new domain to say things about the original version
Yeah but this is only the first question and it was from 1869 so this was a much higher-leveled question for back then
It's straight forward, yet it can be simplified even further.
Explain it
No, no it can't.
no you can’t simplify it further since it is addition. only if it was multiplication would it work
Omg I solved this in my head while driving! Awesome
Jealous of people like u
Katt Williams - “uhhh did you know that some of them is letters”
Everyone gansta until someone cancels out the final x³
I used entrance exams all the way from back in the 1930s to study for my entrance exam in 2006 and I hadn't seen much change in the level. Back in Massachusetts in 1869 most people could afford going to school and having public libraries to study further. MIT, however, is a private institution so the major entrance barrier was always the tuition fees, not the smartness of admited students.
my brain is fried
and my brain ain't braining
same İ got x^3/-2y somehow
x^6 + a^2 x^3 y
---------
x^6 - a^4 y^2
x^6 + a^2 x^3 y
---------
x^6 + - a^4 y^2
x^6/x^6 = 1
1 (a^2 x^3 y)
-------
1 (- a^4 y^2)
a^2 x^3 y
------
- a^4 y^2
a^2/-a^4 = 1/-2
1 (x^3 y)
------
-2 (y^2)
x^3 y
----
-2y^2
(x^3 y)
----
y
-----
( -2y^2)
----
(x^3 y)/y = x^3
(-2y^2)/y = -2y
x^3
--
1
--
2y
--
1
x^3/1 = x^3
2y/1 = 2y
x^3
---
- 2y
u must be pretty slow 💀
An average 12 year old Indian can do this in a minute.
@@user-rx4sv9kx9d don’t say that, they might be younger, or may not practice math regularly.
I've forgotten basic o level mathematics...thanks for the revision jeez
Do you really think this is basic 😂😂
O level? Are you talking about kumon?
@@aryansharmajiYour right.
This is below that
😂😂😂
You can simplify it further by multiplying both the numerator and the denominator by x^-3, so you will end up with 1 / (1 + a^2*y*x^-3), which is convenient to do in applications like DTFT and z-Transform
Why are so many people trying to flex, the question is from 150 years ago and its a basic algebra question, it doesnt mean you can get into mit now or your some genius for solving it.
Inferiority complex and lack of reading comprehension skills/critical thinking skills. In Asia, our schools focus on stem and little on critical thinking. Forget analytical essays lol. It’s why people are so quick to believe propaganda
Factoring is important in here ..
as a 12 year old, cross canceled and got it correct
No one gives a shit buddy
Once I was working as a janitor for a college and a professor wrote this problem on a board in the hall and I solved it. He wanted to take me on as his protege, but I really just wanted get drunk with my buddies and get into fights… Until I met this girl. After going through a number of therapists, I realized that the bad things that happened to me in my life weren’t my fault. I had a good cry and went after the love of my life and accepted a job as a literal genius.
Assume Value Of X = 1 In Question And Also in the other options , The One Who gets matched with Question Will be the correct Option.
This method Can be used if you don't know How to factories 😂😊
As a 40 yrs old who has last seen an algebraic problem for 15 years. I honestly solved it in 10 seconds.
You’re not 40 lol
@@saveit4519 40 yr olds don't exist on this site, apparently
why lie on the internet for no reason
@@deeegeeekay exactly. like what do you gain from it? it's not even like you got a lot of likes, you got 32 💀
Wow so impressive!
As someone who stinks at math, just thinking about doing this problem in permanent marker is giving me a heart attack
It’s all about repetition and practice man. Having a strong mindset where you value the subject certainly helps too.
People in this comment section are trying really hard to get the unlikable person award.
4 cubed to the X factor of 1.5 squared over .3 to the power of 8 quadralaticly rooted in 4s
After the multitude of repetition of this video, I've finally grasp the knowledge...
there was a time when these type of questions were so easy to solve now i don't even know the approach
If you substitute a2y => k and X3 => z then the solution seams more evident => z(z + k) / (z+k)(z-k)
I would probably be able to do it 10 years ago, but now I have forgotten almost everything.
This is why, Sheldon Cooper doesn't respect MIT scholars.
it's from 1869 bruh
Sheldon doesn't like MIT because of paige
Sheldon doesn't like MIT because it is a "trade school" where engineers actually get their hands dirty. Although, in the TV show Young Sheldon they claim it is because it snowed when he landed in Boston, so he turned around and left back for California.
I literally didn't even lift my pen
Whoopdee doo - good for you.
I didn't even watch the video, I solved it through this guy verbally explaining the rational expressions
Nor did anybody. This problem from 1869 would be a cinch for any 6th grader, regardless of where their from.
Badass alert weeewoooo
Want a cookie🍪
👉🏻This is too easy
X⁶ cancelled out with x⁶
Then, a² divided with a⁴ gives a² in denominator
After that , y² divided with y gives y
Ans: x³/a²-y👈🏻
Tooo easy try easy method 👋
Just bring all the numbers from the denominator up, making them negative and then combine with the others. The variables with a positive exponent stays on the numerator and the variables with negative go down to denominator.
Why yall tryna flex in here. Congrats. You solved an algebra problem. Do something elsr
We can simply it to x^3/(1-a^2y) . Right ?????
Right
If it was objective question,I would like to prefer Value putting ,like x = 1 ,y = 2 ,a = 3 ,and check the answer
Imao *JEE has far tough problems than MIT ENTRANCE* 😂😂
Bruh this is 155 years old question.
apparently you couldn’t even pass a primary school reading test. 150 years ago, these were the exams. You commenters are doing more to embarrass JEE than make it look good
😂😂 poor indians always comparing jee with anything.haha
My brain hurts
Is the solution to the mathematical equation finished? This surprises me because I am from Iraq 🙂🇮🇶
makes sense to have such easy exams that far in the past
I understand nothing and i am proud of that😅😅😅😅
😂
Tells you a lot about how the average intelligence of people has increased over the years. Great video.
That’s not true at all. Intelligence has remained relatively stable.
There are more people with access to information, that part has changed.
to be honest ,it is easier than senior high school test weekly in my country
It's amazing how things have changed. What was once an MIT entrance exam question is now standard high school or middle school curriculum (depending on location).
To be more precise you can only cancel that factor if x³≠a²y but since x⁶-a⁴y² is in the denominator therefore x³≠a²y and we can cancel it out.
Even as someone who sucks at math, I was still able to solve that question in way fewer steps than that guy took
This.😂
Nah bruh, i dont believe that there was any entry test idea in 1860's
This is actually something to expose young kids to!!! Make it fun not scary!
I don’t understand anything but it’s just good to see it ..........
If you are younger than 12 it will be difficult for you to solve..for ones who are above 12 years of age this problem shall not be difficult according to me
@@kate6401 yeah , it's very simple
@@thewolverine7516 not for one's below 12...in my school we do this
@@kate6401 hmm
@@thewolverine7516 yeah… now…. This problem is from 1869, I think most people didn’t even know what algebra was back then.
bhai 1869 ki problem hai wo 😭, at that time there were less people who could crack the paper. with internet now sab padh sakte hai, that time sabko khud se padhna hota tha
@Vedant Srivastava iit baad ma establish hoa hai 😆
Fr lol💀😭. People really be saying MIT is easy and sht💀. Would love to see them get into MIT
the only actually smart indian in this comments section
Just remember that you can use different methods to arrive at the same thing, some ppl learn this in different ways.
So you might not understand what's going since ur not used to his methods
I thought this was a SAT question or something even easier until i looked at the title. I think even most high school should be able to solve this.
Damn I would have gotten into MIT easily back in 1869 🤣
You didn't have the same access to resources back then
yes you would have because acceptance rate was much higher.
Make sure you bring some money with you when you get in the time machine because tuition fees would be probably $700 for the whole program with board included.
@@nuclearwarhead9845It was Massachusetts. There were public libraries at any town even back then. It is not like this was in 1649, when people were still sharing a turkey with the natives.
@@gteixeira Last I checked the Internet didn't exist in
1869
bro really did 3 extra steps just to make it more confusing
You're tripping if you think those steps made it more confusing.
@@onddu2254he wrote it really close making it confusing. Need more distance between steps
Good, we're not going backward
What a gift of contribution to humanity.
These comment sections are always so incredibly toxic. You are all extremely insecure
this is a really easy question though, no clue how it is an MIT entrance exam
@@ConstantDerivative It's 1869 where education isn't common
@@soralee1910 thats fair
What is so bad about it? People seem to be mostly pointing out that in developing countries people learn this at middle school level.
@@soralee1910 In Massachusetts people could afford going to school or using a public library even in 1869. And if you were applying to MIT, your family could afford the tuition fees, so they were probably very rich.
Why not this question in JEE Advanced 😂
First go learn some English
@@RishantKarn-ws3ceEnglish and critical thinking skills.
1869
use your brain for once.
Because it’s almost 2024 and not 1869
As An average Indian School Kid solving JEE Advanced questions,this is tooo hard for me😁
In the last step don't you have to reduce the exponents?
HOW COULD you?? Indont think there is a way..
@@leif1075 this was a while ago when I was learning advanced algebra. I now see that you can't reduce if you have + or - without parentheses
@@jasonyeszkonis8364 I'm not sure what you mean bybthat but in this case you can't because there are no other common factors or smaller powers to write in terms of..donest have tonso with parentheses or adding kr subtracting..unless I misunderstood you
@@leif1075 yeah that's what I mean because there is a +/- in the equation below you can't cancel out the cubed x because +/- removes the common denominator
How did we move from (x^3)^2 - (a^2 y)^2 = (x^3 + a^2 y) (x^3 - a^2 y)
What is the idea behind the difference of squares in a denominator?
Why do we write x^6 = x^3(^3) in the first step? Please can someone explain? 🙏🏾
Provided x³+ay should not be equal to zero..
Partial fraction decomposition.
Actually, considering how there are polynomials in the numerator and dominator, us mathematicians refer to this "fraction" as a rational expressions
@@ugIybot I'm a chemical engineer not a mathematician.
That's like the easiest algebra question from a class 8 icse school
Also it was difficult in 1869
Is everyone gonna ignore that the square root of a^4y^2 isn't a^2y
This equation was like taught to me when i was in 7th or 9th standard. In mathematics subject algebra was too much added. Lots of identities to remember.
Asian kids doing this in half sleep….
Asian kids living in slums
Asian kids thinking their so good at math but miss the number 1869:
Me: hey albert!
Albert Einstein: yes?
Me: can you solve this?
If you genuinely think the guy who came with relativity and Photoelectric and predicted Black Holes before it was even seen, to be weak at Math. You are something else.
The guy went to the Institute for Advanced Study in Princeton, New Jersey. From what I can gather in some source, he's dealt his discoveries with the heavy Math to which an undergraduate course would cover superficially or not tackle altogether, only approached with rigor required at the PhD level.
12th class:This is easy.
5th class:Oh I am dieing **dies out**
Avg 12 year kid from india : 😮💨
MIT ENTRANCE 🤡
JEE MAIN ☠️
JEE ADVANCED👽
Mit in 1869 🗿🗿
Jee In 1869 does not exist..🤡
Mit now 🗿🥶🎇
Jee now 🗿🗿
You know getting into MIT is crazy hard now lol shows that you are the real clown
Yet u prob failed all
Good job, you solved a problem in 1800’s where most people stopped school at the 8th grade :D
Good job being salty for no reason
@@oliver_958good job for not understanding that this is critical for calling this a hard question when an 11 y old could solve it
Reminder that this is at a time when people still went to college to learn classical history and languages. And you could pay for your tuition by keeping fires lit and sweeping. And there were no calculators or internet to find practice questions.
These are the types of problems that once you know how to answer it, it's all easy. Just practice
That’s definitely the hard way lol
yeah wtf if i tried to do it the way he did it i would get it wrong. no idea why he made it 1000x harder on himself
@@AefaxThey just factored it then simplified. It is important to factor the numerator and denominator to eliminate like terms and that’s what they did.
I didn’t recognize the difference of squares though 😬
Can’t you just cross out numerator vs denominator from the start?
What are the 7 hardest math problems?
Le mee: Clay “to increase and disseminate mathematical knowledge.” The seven problems, which were announced in 2000, are the Riemann hypothesis, P versus NP problem, Birch and Swinnerton-Dyer conjecture, Hodge conjecture, Navier-Stokes equation, Yang-Mills theory, and Poincaré conjecture.
Easy: TOP: x^3 (x^3 + a^2 y)
BOTTOM: (x^3 - a^2 y)(x^3 + a^2 y)
cancel like terms:
x^3 / (x^3 - a^2 y)
Did in my head in about 30 seconds-ish.. took me far longer to type than to figure it out