Co-variance of a data Matrix Dimensionality reduction and visualization Lecture 8 @Applied AI Course

[@snake1625b]

Your entire series on this is 10/10!

[@helloshifna4532]

clarity of concepts and simple explanations...Thank you very much sir

[@shreeshapr7207]

Is n in the denominator is missing in the final equation?

[@lix2k3]

Excellent explanations!

[@samcool6569]

The final eqn at the end of the video, @ 23:23, is it also missing the 'n' in denominator?

[@amanoswal7391]

Please provide the link for your correlation video

[@questforprogramming]

@ 12:50 is that 'xi2' or it should be 'xj1'? Also
@ 16:08 is that 'xi2' or it should be 'xj1'?
As per my view it should be( 1/n sigma... xi1 * xj1 )
Please correct me if I am wrong..!!

[@rana31ify]

The gist is if a matric is square & symmetric then you corresponding calculations are equal xD. But well explained.