In the second example is the reason you didn't do the 3(c-H) and c-cl bonds on the reactant side is because on the product side there's also 3(c-H) and c-cl bonds?
I have a question. So basically what you while you use bond energy method, you do this ; Reactants - products, isn't it? So why you have written down products-reactants as another method. It is really confused me. Sorry if i have grammer mistakes or spellin mistakes that i might have
Make sure you always balance your equations. I just took a quiz and forgot to...
How do you know which bonds to break? Can someone please explain this to me
broken bonds are bonds that are not formed on the product side. And formed bonds are bonds that are not on the reactant side.
Great video to review with none the less. Thank you.
In the second example is the reason you didn't do the 3(c-H) and c-cl bonds on the reactant side is because on the product side there's also 3(c-H) and c-cl bonds?
How do you know which bonds to break?
How do you determine the bond energies of NH4Cl? the Chlorine isnt bonded to anything so do i ignore it?
which source did you use to obtain the the bond energies? can you share your reference?
for bond energies its reactants(bonds broken) - bonds formed(formed) why if the equation before is products - reactants?
wow!! thank you so much!! I finally understand this stuff!!
Awesome sir
Plz upload shortcut trick for organic reaction
Nice video, keep it coming! :)
Very helpful!
very very helpful
-4788 should be the correct answer for the last problem. I'm appreciative though.
I have a question. So basically what you while you use bond energy method, you do this ; Reactants - products, isn't it? So why you have written down products-reactants as another method. It is really confused me. Sorry if i have grammer mistakes or spellin mistakes that i might have
thanks 4 help us
NICE
Correction to video: in C6H6 + O2 -----> CO2 + H2O the correct way to balance the equation is
2 C6H6 + 15 O2 -----> 12CO2 + 6H2O
I thought the correct way was C6H6 + 7.5 O2 ---> 6 CO2 + 3 H2O
thanks
Break the ones that were on the reactant side but not on the product side.
yayay