> the massless property of photons can be accounted for by de broglies equation as the mass of photons becomes negligible and tends towards zero when the particles velocity approaches c I don't think I understand what you meant with this
photons have momentum its because e = mc^2 is for stationary objects the real formula is e^2 =(pc)^2+(mc^2)^2 since photons have energy (e=hf) then they must have a momentum if they dont have a mass since e^2 =(pc)^2+(mc^2)^2 describes all the particles energy this allows it to have a debroiglie wave length > for m = 0 > e = pc > sub e = hf > (hf) = pc > sub f = c/λ >hc/λ = pc >λ = h/p as required
For the question at the end, you needed to multiply the denominator by gamma to account for relativistic momentum dilation
Yes, you can do this but the ‘gamma’ value is 0.99 at 0.15c which means you may assume the effect of special relativity is negligible.
> the massless property of photons can be accounted for by de broglies equation as the mass of photons becomes negligible and tends towards zero when the particles velocity approaches c
I don't think I understand what you meant with this
photons have momentum
its because e = mc^2 is for stationary objects
the real formula is e^2 =(pc)^2+(mc^2)^2
since photons have energy (e=hf) then they must have a momentum if they dont have a mass since e^2 =(pc)^2+(mc^2)^2 describes all the particles energy
this allows it to have a debroiglie wave length
> for m = 0
> e = pc
> sub e = hf
> (hf) = pc
> sub f = c/λ
>hc/λ = pc
>λ = h/p as required
@@blackman123official3 i dont think you answered my question
I think he got this wrong... As velocity approaches c, mass tends to increase, not decrease