Product of chords?
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- Опубликовано: 30 июн 2024
- This short animation shows chords connecting n equally space points to one of those points on a unit circle and computes the product of the chord lengths. Do you have a conjecture based on this? Can you prove it?
If you’re interested, check out the related video at • Products of Chords in ... .
This animation is based on a famous problem that has been discussed in numerous places. In particular, a great reference for this problem and related ones (with a fantastic bibliography) is the source Chords of an Ellipse, Lucas Polynomials, and Cubic Equations in Issue 8 of the 2020 American Mathematical Monthly (doi.org/10.1080/00029890.2020...) by Ben Blum-Smith and Japheth Wood. You can also find the source here: arxiv.org/abs/1810.00492.
#math #mathvideo #manim #circle #chords #visualproof #trigonometry #sine #cosine #tangent #rootsofunity #complexanalysis #complexnumbers #products #geometry
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I’d love to see an explanation/proof for this!
ruclips.net/video/8GPy_UMV-08/видео.htmlsi=8I89MK0V8FCePpXx
See linked video. 😀
Check also this video!
Title: Proving Grant's little theorem.
@@MathVisualProofsit is called the power of point with respect to circle
Am I correct??
The Chanel name covers it, but for anyone who’s wondering the bottom number says “chord length product”
Ugh. One day I’ll figure out how to optimize for all the RUclips shorts clutter. Thanks.
Wow! Very cool! I was not aware of this property of chords.
Grant's liitle theorem!
Best content creator 😎❤
At first I thought you said best concert creator, and I’m like, well yes, with the music, and the “chords”, absolutely.
@@bradleyday2777 🤣🤣🤣🤣🤣🤣🤣🤣
I wonder if there is a proof for this using roots of unity! Each chord would have length of abs(1-[root]).
Yes!
Huh???
Wait so
4 points has
2×(√2)² soo maybe which us 4 chords
So if we back track
The chord would be a triangle with a base of 1+|cos120| or 3/2 and a height of √3/2 so Pythagorean theorem it comes out as 9/4+3/4 which comes down to 3sq
Then √3
Then realization kicks in
I'm not smart enough to conclude anything with this
Google is my trusted navigator
😎🆒🆒