Thank you so so so much for this tutorial . I have been working on this function for the past two hours. I watched your video and in one minute this issue of evenly spacing decreases was solved.
Thank you, Heather for this very clear and helpful video. It was exactly what I needed to learn and communicate for my Level 1 Mitten decreases in the round. Very sincerely, J
Can you work this out as I’m getting mixed up. I have 135 stitches decrease 3 stitches evenly across row so I should have 132 stitches left on the needle. Could you please help
I have a handy calculator on my website that can help! heatherstorta.com/resources-2/knitting-calculators/ It'll depend on if you are working flat or in the round, and then how many plain sts you want on the sides if working flat, but the calculator factors all that in for you!
Right, so if you are working flat, here's the math. Take 211 divided by 65 (64 plus one). That gives you 3.246, so round down to 3. You'll need to decrease in every set of 3 sts (and then end up with 3 sts after the last decrease.) Since we rounded down, there are going to be some sections where you need to decrease in every set of 4 sts. To figure out those, take 3x65, which equals 195, then subtract 195 from your 211, which gives 16, so 16 of your sections will need to use the 4 sts. You can either just throw those 4 st sections randomly in, or you can get even more precise by taking 65 divided by 16, which is 4.06 (round down to 4) -- so about every 4 decreases work the 4 st sections. Because the decrease takes up 2 sts, you'll have something like this: K3, k2tog, k1, k2tog, k2, *(k2tog, k1) four times, k2tog, k2; rep from * to last 9 sts, k2tog, k2, k2tog, k3. You can adjust that a bit to get something you like, but it's a start. (Making sure there are 64 decreases within the row -- there will be 60 inside the * *, and then another 4 outside the * *.) Hopefully that was helpful and not more confusing!!
Are you working flat or in the round? because the answer will be different for each of those. Flat - you take 60/(24+1) = 2.4, so you'll have some spaces of 2 sts -- 60% of the decreases (and you'll need both of those to work a decrease) and some of 3 sts -- 40% of the decreases (which would be knit one then decrease). You won't want a decrease at the selvedges, so the beginning and end will be a k1 or a k2. 25x0.4 = 10 (that will be the number of times at the higher number, but subtract one for the edge spaces), and 0.6 (what's left after 0.4) x25 = 15 (that will be the number of times at the lower number). So, you'll work 15 times as a k2tog (or other single decrease) and 9 times as a (k1, k2tog). There are 3 sts left for the edges, one edge will have a k1, the other will have a k3. You'll want to alternate the (k2tog) and the (k1, k2tog) as evenly as possible across the row. In the round, you instead take 60/24 = 2.5. You'll have half the decreases (12 of them) as (k1, k2tog) and half of them (12 of them) as (k2tog). You can alternate them nicely since they're evenly split. So, you'd work (k2tog, k1, k2tog) around the circumference. Hopefully that is helpful and not just a wall of math that makes no sense!
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Thank you for explaining this so clearly and demonstrating right after each explanation. I learn best by watching so that's very helpful.
You're very welcome!
Thank you so so so much for this tutorial . I have been working on this function for the past two hours. I watched your video and in one minute this issue of evenly spacing decreases was solved.
I'm so glad it was helpful!!
Excellent instructions, thank you! This is exactly what I was looking for!
Glad it was helpful!
Thank you, Heather for this very clear and helpful video. It was exactly what I needed to learn and communicate for my Level 1 Mitten decreases in the round.
Very sincerely,
J
I'm so glad it was helpful!
Can you work this out as I’m getting mixed up. I have 135 stitches decrease 3 stitches evenly across row so I should have 132 stitches left on the needle. Could you please help
I have a handy calculator on my website that can help!
heatherstorta.com/resources-2/knitting-calculators/
It'll depend on if you are working flat or in the round, and then how many plain sts you want on the sides if working flat, but the calculator factors all that in for you!
Thankyou, that was as clear as mud
If I know I need to decrease 64 stitches from 211, I'm not understanding how to figure the evenly spaced decreases. Can u assist?
Right, so if you are working flat, here's the math. Take 211 divided by 65 (64 plus one). That gives you 3.246, so round down to 3. You'll need to decrease in every set of 3 sts (and then end up with 3 sts after the last decrease.) Since we rounded down, there are going to be some sections where you need to decrease in every set of 4 sts. To figure out those, take 3x65, which equals 195, then subtract 195 from your 211, which gives 16, so 16 of your sections will need to use the 4 sts. You can either just throw those 4 st sections randomly in, or you can get even more precise by taking 65 divided by 16, which is 4.06 (round down to 4) -- so about every 4 decreases work the 4 st sections. Because the decrease takes up 2 sts, you'll have something like this:
K3, k2tog, k1, k2tog, k2, *(k2tog, k1) four times, k2tog, k2; rep from * to last 9 sts, k2tog, k2, k2tog, k3. You can adjust that a bit to get something you like, but it's a start. (Making sure there are 64 decreases within the row -- there will be 60 inside the * *, and then another 4 outside the * *.)
Hopefully that was helpful and not more confusing!!
I have 60 stitches and have to decrease24 evenly please help me
Are you working flat or in the round? because the answer will be different for each of those.
Flat - you take 60/(24+1) = 2.4, so you'll have some spaces of 2 sts -- 60% of the decreases (and you'll need both of those to work a decrease) and some of 3 sts -- 40% of the decreases (which would be knit one then decrease). You won't want a decrease at the selvedges, so the beginning and end will be a k1 or a k2.
25x0.4 = 10 (that will be the number of times at the higher number, but subtract one for the edge spaces), and 0.6 (what's left after 0.4) x25 = 15 (that will be the number of times at the lower number).
So, you'll work 15 times as a k2tog (or other single decrease) and 9 times as a (k1, k2tog). There are 3 sts left for the edges, one edge will have a k1, the other will have a k3.
You'll want to alternate the (k2tog) and the (k1, k2tog) as evenly as possible across the row.
In the round, you instead take 60/24 = 2.5. You'll have half the decreases (12 of them) as (k1, k2tog) and half of them (12 of them) as (k2tog). You can alternate them nicely since they're evenly split. So, you'd work (k2tog, k1, k2tog) around the circumference.
Hopefully that is helpful and not just a wall of math that makes no sense!