What does it mean to take a complex derivative? (visually explained)

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  • Опубликовано: 18 ноя 2024

Комментарии • 213

  • @vcubingx
    @vcubingx  2 года назад +123

    Some extra info:
    At 20:47, I mention that a function is holomorphic if it satisfies the cauchy-riemann equations. There's an extra condition: the partial derivatives have to be continuous as well.
    For example, f(z) = {0 if z=0, z^5/|z^4| if z!=0} satisfies the cauchy-riemann equations but is not differentiable at z=0.
    Thanks to Ge for pointing this out!
    Mistakes:
    3:15: The upper number line should still be labeled as "x" instead of "x^2"
    14:56 [z^n]' = nz^(n-1)

    • @mathmanindian
      @mathmanindian 2 года назад +2

      Bro, improve your thumbnail
      Try making it attractive
      I really like your work !

    • @josephkwong7388
      @josephkwong7388 2 года назад

      @@mathmanindian I kinda like the thumbnail tbh

    • @probablyapproximatelyok8146
      @probablyapproximatelyok8146 2 года назад +5

      Also, at 14:17, I think the example you gave for why the converse doesn’t hold seems off. If angles were preserved, then the arrows would stay at uniform angles from each other. But that clearly isn’t the case in the example you gave, since some arrows become close to 45° angles from each other, and others are clearly less than 30°.
      One example for why the converse doesn’t hold that is conformal but not complex differentiable at the origin is z -> conj(z).

    • @vcubingx
      @vcubingx  2 года назад +6

      You're right! I can't believe I didn't catch that either. Basically, what I wanted to animate was a rotation matrix applied to the dz, and then a scaling factor applied to two opposite dz vectors. I think I instead scaled all of them :p, but I (hopefully) think it can somewhat get the point across

    • @epicmorphism2240
      @epicmorphism2240 2 года назад

      Another small mistake at 9:01 holomorph isn‘t equivalent to complex differentiable

  • @mathemaniac
    @mathemaniac 2 года назад +246

    Welp - you beat me to it! I was planning a video which will exactly be about CR equations, and is going to be the next video for my complex analysis series. Would you mind me linking this video in my own Essence of Complex Analysis playlist?

    • @vcubingx
      @vcubingx  2 года назад +112

      I don't mind at all! Your videos are amazing, keep up the great work!!

    • @mathemaniac
      @mathemaniac 2 года назад +49

      ​@@vcubingx Thanks! Will add that now.

    • @glory6998
      @glory6998 2 года назад +25

      I follow both of you

    • @standowner6979
      @standowner6979 2 года назад +7

      @@glory6998 Okay.

    • @tanchienhao
      @tanchienhao 2 года назад +21

      You BOTH are awesome!! Competition/collaboration would do wonders for the youtube complex analysis videos landscape wonders :)))

  • @Krageon-Offline
    @Krageon-Offline 12 дней назад +2

    I don’t know what it is about this music, but it for some reason gave me a sense of true calmness for once in the last ~3 years… keep it up.

  • @frankansari3457
    @frankansari3457 Год назад +3

    This is really great stuff. From a real function you can always take a deriviative if the function has no gaps, jumps or poles. With complex functions you can not take it for granted that you can do this. This video explains why.

  • @aliscander92
    @aliscander92 2 года назад +10

    Brilliant! Great lecture! I'm radioelectronic engineer, so I regularly use complex functions theory in my calculations for radar applications. Your made me remember some details from our university course of complex functions. Thank you very much!

    • @vcubingx
      @vcubingx  2 года назад +1

      Thanks! Glad you enjoyed it

    • @hyperduality2838
      @hyperduality2838 2 года назад

      The integers or real numbers are self dual:-
      ruclips.net/video/AxPwhJTHxSg/видео.html
      Symmetric matrices (real eigenvalues) are dual to anti-symmetric matrices (complex eigenvalues) -- linear algebra, Gilbert Strang.
      Real numbers are dual to complex numbers.
      Complex numbers are dual.
      "Always two there are" -- Yoda.
      The spin statistics theorem:-
      Symmetric wave functions (Bosons, waves) are dual to anti-symmetric wave functions (Fermions, particles) -- wave/particle or quantum duality.
      Bosons are dual to Fermions -- atomic duality.
      Duality creates reality!

  • @alicesmith5361
    @alicesmith5361 2 года назад +50

    Wow, this is incredible! Now I understand way more about this than when I covered it in an independent project. Considering the differential, the condition of a linear mapping makes complete sense as you'd want any step away from the input to act in the same way (as it is being multiplied by a single number, the output of the derivative at that point) regardless of angle. What a wonderful video!

    • @vcubingx
      @vcubingx  2 года назад +2

      Thanks! Glad it helped

    • @hyperduality2838
      @hyperduality2838 2 года назад

      The integers or real numbers are self dual:-
      ruclips.net/video/AxPwhJTHxSg/видео.html
      Symmetric matrices (real eigenvalues) are dual to anti-symmetric matrices (complex eigenvalues) -- linear algebra, Gilbert Strang.
      Real numbers are dual to complex numbers.
      Complex numbers are dual.
      "Always two there are" -- Yoda.
      The spin statistics theorem:-
      Symmetric wave functions (Bosons, waves) are dual to anti-symmetric wave functions (Fermions, particles) -- wave/particle or quantum duality.
      Bosons are dual to Fermions -- atomic duality.
      Duality creates reality!

  • @unnamedemptiness2002
    @unnamedemptiness2002 2 года назад +6

    Your pronuntiation has improved insanely bro, and you keep covering topics that nobody animated before, thanks for that

  • @kamalalagarsamy2583
    @kamalalagarsamy2583 2 года назад +2

    I watched many videos, but they were not clear. This is the best explanation of complex functions.

  • @estebanmartinez4803
    @estebanmartinez4803 2 года назад +41

    Grwat video! Just to say that there is a little mistake at 14:56
    The derivative of z^n obeys, as you say, the same rule as for real values, so it should be nz^(n-1)

    • @vcubingx
      @vcubingx  2 года назад +29

      Oh god, how did I mess that up

    • @Caleepo
      @Caleepo 2 года назад +2

      @@vcubingx I have a feeling you are gonna reupload this video :p. Anyways awesome vid tho.

    • @ammyvl1
      @ammyvl1 2 года назад +13

      @@vcubingx mixed it up with the integral lmao

  • @smorcrux426
    @smorcrux426 2 года назад +5

    Oh my god! I knew literally nothing about this topic beforehand and I just thought about this question randomly yesterday, and now I feel like I understand this really well! Thanks a ton, you really do help people out.

  • @speeshers
    @speeshers 2 года назад +6

    WOW, what an amazing intuition you developed for the ideas presented, and the visuals are top-tier. Thanks so much!!

  • @Applied_Mathemagics
    @Applied_Mathemagics Год назад +2

    This is the best video on RUclips on the subject. As good as (and please forgive me if the comparison if found insidious) 3Blue1Brown. KEEP IT UP!!!

  • @NexusEight
    @NexusEight 2 года назад +4

    Fantastic visualisations! Some of the animations are rarely seen here on youtube, like the first most basic one, mapping the change in x to the change in y , each on their own number lines. Great work!

    • @hyperduality2838
      @hyperduality2838 2 года назад

      The integers or real numbers are self dual:-
      ruclips.net/video/AxPwhJTHxSg/видео.html
      Symmetric matrices (real eigenvalues) are dual to anti-symmetric matrices (complex eigenvalues) -- linear algebra, Gilbert Strang.
      Real numbers are dual to complex numbers.
      Complex numbers are dual.
      "Always two there are" -- Yoda.
      The spin statistics theorem:-
      Symmetric wave functions (Bosons, waves) are dual to anti-symmetric wave functions (Fermions, particles) -- wave/particle or quantum duality.
      Bosons are dual to Fermions -- atomic duality.
      Duality creates reality!

  • @willknipe2607
    @willknipe2607 2 года назад +1

    BEAUTIFUL. really intuitive explanation for how the cauchy-riemann equations follow from a function being analytic. DIdn't really click until now!

  • @actualBIAS
    @actualBIAS Год назад +1

    My friend. Thank you for visualizing this masterpiece. This just helped me to overcome the barrier i was stuck with.

  • @SubAnima
    @SubAnima 2 года назад +2

    This is such a great video. My lecturer made it seem like the Cauchy-Riemann equations just fell from the sky, this gave me some beautiful intuition. Thank you!!!!!!

    • @vcubingx
      @vcubingx  2 года назад +1

      Thanks!! Glad you enjoyed it

    • @hyperduality2838
      @hyperduality2838 2 года назад

      The integers or real numbers are self dual:-
      ruclips.net/video/AxPwhJTHxSg/видео.html
      Symmetric matrices (real eigenvalues) are dual to anti-symmetric matrices (complex eigenvalues) -- linear algebra, Gilbert Strang.
      Real numbers are dual to complex numbers.
      Complex numbers are dual.
      "Always two there are" -- Yoda.
      The spin statistics theorem:-
      Symmetric wave functions (Bosons, waves) are dual to anti-symmetric wave functions (Fermions, particles) -- wave/particle or quantum duality.
      Bosons are dual to Fermions -- atomic duality.
      Duality creates reality!

  • @md.hamidulhaque5816
    @md.hamidulhaque5816 5 месяцев назад

    What a video that was!!!!!! I completed my post-graduation in Physics from a third world county. Always wanted to get deeper intuition, and this video is just amazing. Be blessed always.

  • @sour5blue
    @sour5blue 2 года назад +6

    Woah i never learned the intuition for calculus in complex numbers

  • @thatchessguy7072
    @thatchessguy7072 2 года назад +5

    I’ve just started complex analysis this semester. This is very helpful.

  • @いむならむ
    @いむならむ 11 месяцев назад

    Best ever!!! explanation on Cauchy Riemann equations of which "This matrix transformation can't be any linear transformation. It has to look like multiplying a complex number" has me convinced.

    • @vcubingx
      @vcubingx  11 месяцев назад

      Thank you!!

  • @cmilkau
    @cmilkau 2 года назад +3

    when visualizing rotations, please consider breaking high rotational symmetries so the rotation angle is more obvious

  • @darmok3171
    @darmok3171 5 месяцев назад

    This is an awesome video! I've spent a long time trying to understand why certain "smooth looking functions" (not in the mathematical sense) are not complex differentiable. I was especially stumped by |sin(|z|)| * e^(i*arg(z)) and conj(z)·sin(z) + cos(conj(z)).

  • @shashwatbhatnagar659
    @shashwatbhatnagar659 Год назад

    superb,I was searching the whole internet for this and you explained it in the most beautiful way possible

  • @TheFallenTitan
    @TheFallenTitan 2 года назад +2

    Lovely Video! Thank you so much, very well explained. I wish you will make a video on Wirtinger Derivatives--generalizing derivatives to non-holomorphic functions!!

    • @hyperduality2838
      @hyperduality2838 2 года назад

      The integers or real numbers are self dual:-
      ruclips.net/video/AxPwhJTHxSg/видео.html
      Symmetric matrices (real eigenvalues) are dual to anti-symmetric matrices (complex eigenvalues) -- linear algebra, Gilbert Strang.
      Real numbers are dual to complex numbers.
      Complex numbers are dual.
      "Always two there are" -- Yoda.
      The spin statistics theorem:-
      Symmetric wave functions (Bosons, waves) are dual to anti-symmetric wave functions (Fermions, particles) -- wave/particle or quantum duality.
      Bosons are dual to Fermions -- atomic duality.
      Duality creates reality!

  • @王劲飞-z4z
    @王劲飞-z4z Год назад +1

    Great video! Really inspred me when I am struggling to visually understand complex functions!

  • @cheesecak11857
    @cheesecak11857 2 года назад +1

    Let's gooooo! Can't wait to watch this Vivek!

  • @acamarocutcher8845
    @acamarocutcher8845 Год назад

    Thank you for the effort you put into making these videos. It's helping appreciate complex analysis more.

  • @mnada72
    @mnada72 Год назад

    Big thank you. This was really helpful specially that Cauchy-Reimann equation is a consequence of Jacobian matrix.

  • @tigranchtchyan1614
    @tigranchtchyan1614 2 года назад +4

    Wow, a great video!! Brilliant ideas and illustrations! Thanks for your effort.
    P.S. I work with manim too, so I know how hard it is to make such animations.

  • @susanariveracabrera764
    @susanariveracabrera764 2 года назад +2

    Wonderful explanation and great video! Thank you so much for clarifying things to us. Keep on going with this great videos, they are awesome!

    • @vcubingx
      @vcubingx  2 года назад

      Thanks! Glad you enjoyed it!

    • @hyperduality2838
      @hyperduality2838 2 года назад

      The integers or real numbers are self dual:-
      ruclips.net/video/AxPwhJTHxSg/видео.html
      Symmetric matrices (real eigenvalues) are dual to anti-symmetric matrices (complex eigenvalues) -- linear algebra, Gilbert Strang.
      Real numbers are dual to complex numbers.
      Complex numbers are dual.
      "Always two there are" -- Yoda.
      The spin statistics theorem:-
      Symmetric wave functions (Bosons, waves) are dual to anti-symmetric wave functions (Fermions, particles) -- wave/particle or quantum duality.
      Bosons are dual to Fermions -- atomic duality.
      Duality creates reality!

  • @dirichlettt
    @dirichlettt 2 года назад +2

    Needham will always be my favorite complex analysis book

  • @carmelpule8493
    @carmelpule8493 7 месяцев назад

    When considering complex differentials, we could consider navigation and directions followed on a field. If one is following a path where each position is a vector then the differential is the present position ,minus the old position divided by the time taken ( the function is with respect to time. Hence the rate of change of the walk in this situation.
    If we consider a field where wheat is growing , each stub of wheat is the vector field and if we subtract two nearby stubs of wheat in their vector form we get the rate of change of the vector field of wheat, which has magnitude and direction. The important issue is to understand what is RATE OF CHANGE with respect to some variable.

  • @_tgwilson_
    @_tgwilson_ 2 года назад +6

    Superb video. More please! It really helped me with some of the concepts in The Road to Reality. I'm sure Roger Penrose would love it : )

    • @hyperduality2838
      @hyperduality2838 2 года назад +1

      The integers or real numbers are self dual:-
      ruclips.net/video/AxPwhJTHxSg/видео.html
      Symmetric matrices (real eigenvalues) are dual to anti-symmetric matrices (complex eigenvalues) -- linear algebra, Gilbert Strang.
      Real numbers are dual to complex numbers.
      Complex numbers are dual.
      "Always two there are" -- Yoda.
      The spin statistics theorem:-
      Symmetric wave functions (Bosons, waves) are dual to anti-symmetric wave functions (Fermions, particles) -- wave/particle or quantum duality.
      Bosons are dual to Fermions -- atomic duality.
      Duality creates reality!

  • @Abbas-fl3bw
    @Abbas-fl3bw Год назад

    the animations are so smooth bro wtf

  • @Spandan_Ghoshal
    @Spandan_Ghoshal 2 года назад +3

    Hats off to you 🙏🙏🙏 you have given immense amount of effort to make this video and i found this really really helpful... thanks again ❤️❤️❤️

  • @tanchienhao
    @tanchienhao 2 года назад +3

    your channel is awesome!!! keep the great videos coming! i would love to see some info on riemann surfaces and their classification if u are into that :)

  • @lowerbound4803
    @lowerbound4803 Год назад

    Your explanation is unreal!!! 💫💫

  • @Djake3tooth
    @Djake3tooth 2 года назад

    this is so much more fun to watch when i need to do homework

  • @isaigordeev
    @isaigordeev 2 года назад +1

    great job and keep going
    at the moment you decided to do this kind of stuff you definitely did not mess up :)
    also would like to see something advanced about conformal maps on the complex plane

    • @hyperduality2838
      @hyperduality2838 2 года назад

      The integers or real numbers are self dual:-
      ruclips.net/video/AxPwhJTHxSg/видео.html
      Symmetric matrices (real eigenvalues) are dual to anti-symmetric matrices (complex eigenvalues) -- linear algebra, Gilbert Strang.
      Real numbers are dual to complex numbers.
      Complex numbers are dual.
      "Always two there are" -- Yoda.
      The spin statistics theorem:-
      Symmetric wave functions (Bosons, waves) are dual to anti-symmetric wave functions (Fermions, particles) -- wave/particle or quantum duality.
      Bosons are dual to Fermions -- atomic duality.
      Duality creates reality!

  • @jimlbeaver
    @jimlbeaver 2 года назад +1

    Excellent video…very clear and well-paced. Nice job and thanks!

  • @isakhammer6558
    @isakhammer6558 2 года назад +1

    So good quality, you are great! I may also appreciate a video about laurent series and the relations to tayler expansions!

    • @vcubingx
      @vcubingx  2 года назад +2

      Thanks! As for Laurent series, maybe, I'll have to see. I added it to my list of topics though!

  • @valerierit2003
    @valerierit2003 2 года назад +1

    Nice.. Plss do post frequently

  • @rxphi5382
    @rxphi5382 2 года назад

    Those are some beautiful animations!

  • @mauriciocaviedes4552
    @mauriciocaviedes4552 Год назад

    Great, great video!
    I didn't get the deriv of e^z. Tomorrow I'll try again.

  • @davidhicks8290
    @davidhicks8290 2 года назад

    Underrated! Amazing video thank you!

  • @leotimm6805
    @leotimm6805 2 года назад

    It's always a great pleasure to watch your videos ! Thank you so much !!!

    • @vcubingx
      @vcubingx  2 года назад

      Thanks for watching!

  • @nafrost2787
    @nafrost2787 2 года назад +1

    So because complex differentiability requires that the linear transformation we use to approximate the function to consist solely from scaling and rotating, and because we can always convert a function from a domain of C to a domain of R^2 bijectively, can we say that complex differentiability is a stronger property of a function than regular differentiability? Which allows the linear transformation we use to approximate the function to be any linear transformation?

    • @vcubingx
      @vcubingx  2 года назад +1

      Ignore my previous reply, from my understanding yes, complex differentiation is a stronger property than differentiation over R^2 -> R^2

  • @djredrover
    @djredrover 2 года назад

    Wow, Grant's visualization software is all over youtube!

  • @valor36az
    @valor36az 2 года назад

    Amazing explanation

  • @蒋正-k6u
    @蒋正-k6u 2 года назад

    very good video, approaching 3b1b level

  • @christophem6373
    @christophem6373 2 года назад +1

    do hope you could illustrate complex integration !!!
    Thank you a lot !

    • @vcubingx
      @vcubingx  2 года назад +1

      That's the plan! I mainly want to cover the Cauchy Integral Theorem and the Residue Theorem, and how it can be used to evaluate improper integrals

  • @BigEpsilon
    @BigEpsilon 2 года назад

    Very insightful. Thank you.

  • @SamiulIslam-vv5vc
    @SamiulIslam-vv5vc 2 года назад

    It was really a great one!!! I really loved it!!!

  • @ycombinator765
    @ycombinator765 2 года назад +2

    لیجنڈ واپس آگیا ہے. ❤️❤️🌹

  • @AJ-et3vf
    @AJ-et3vf 2 года назад

    Awesome video! Thank you!

  • @luphiax4239
    @luphiax4239 2 года назад

    How did you come up with that!!! you are a genius

  • @swastikkalsi9586
    @swastikkalsi9586 2 года назад

    3blue1brown and now this🤩

  • @VisuallyExplained
    @VisuallyExplained 2 года назад +1

    Hey there, nice video! For reasons I can't really explain, I really like the title. :-)

  • @NovaWarrior77
    @NovaWarrior77 2 года назад

    Vivek with the sponsorships!!!!

  • @chingizarystanbekov151
    @chingizarystanbekov151 Год назад

    amazing work,

  • @isakdupreez6201
    @isakdupreez6201 2 года назад

    If you consider a complex differentiable function as a 2D vector field over the same 2D domain, the real part of the derivative is divergence and the imaginary part of the derivative is curl (which in 2D can be defined as a signed scalar)*
    * Except that both are scaled by a factor of 2.

    • @angeldude101
      @angeldude101 2 года назад

      If you try doing this with a 3D vector, what you end up with is a quaternion as the derivative, with the imaginary curl being the 3 "vector" components.

  • @RohanDasariMinho
    @RohanDasariMinho 2 года назад

    Great work!

  • @bulat314
    @bulat314 2 года назад

    Amazing! This helps a lot👍

  • @suyashpatni4032
    @suyashpatni4032 Год назад

    brilliant video!

  • @ronakpatel6530
    @ronakpatel6530 2 года назад

    Damn dawg you explained the shit outta that topic good

  • @animewarrior7
    @animewarrior7 2 года назад

    thanks a lot brotha!

  • @tedsheridan8725
    @tedsheridan8725 9 месяцев назад

    Great video! Question I've always had: It seems if you take any real, differentiable differentiable function f(x), and make it complex, i.e f(z), you get a holomorphic function. Is this an 'if and only if' condition? In other words can every holomorphic function be thought of as f(z) for some real differentiable function f(x)?

  • @proxxyBean
    @proxxyBean 2 года назад

    Is there a way to use animation to visualize the output space using the timeline to stand in for the imaginary part?

  • @s.m.m99203
    @s.m.m99203 7 месяцев назад

    Hi. Thank you.
    May I ask how you make such animations?

  • @Zonox-ml4jq
    @Zonox-ml4jq Год назад

    ¿Which software do you use? it's amazing, i mean, i'd love to try myself and dig into complex functions!

  • @lagrangian143
    @lagrangian143 2 года назад +1

    will you do videos on harmonic analysis and operator theory?

    • @vcubingx
      @vcubingx  2 года назад +1

      Maybe! I was planning a video covering some topics from harmonic analysis, but it's a tricky one to make, so I may put it off

  • @Neme112
    @Neme112 Год назад

    13:26 I don't get this. It seems like the angles are not preserved. For example, the angle between the x and y axes is initially 90 degrees, but it grows to 180 degrees.

  • @izzapz
    @izzapz 2 года назад

    Great video! Do you use any particular software to graph the plots in the videos?

    • @vcubingx
      @vcubingx  2 года назад +1

      Sorry for the late reply, but I use manim! Check the desc for the code

    • @izzapz
      @izzapz 2 года назад

      @@vcubingx thanks!!!

  • @pawejedrejko7398
    @pawejedrejko7398 2 года назад

    What is the function (of time) you use to represent the dynamics of e^z mapping?

  • @gauthierruberti8065
    @gauthierruberti8065 Год назад

    Thank you so much

  • @manstuckinabox3679
    @manstuckinabox3679 Год назад +1

    I always felt complex derivatives were highly similar to the divergence of a vector feild.

  • @agrajyadav2951
    @agrajyadav2951 2 года назад

    Bruh ur a legend

  • @mahmoudalbahar1641
    @mahmoudalbahar1641 2 года назад +1

    Thank you for your great videos
    And I want to ask you to:
    Please make bijection between:
    1)irrational numbers and real numbers.
    2)real numbers and complex numbers.

  • @bennicholl-kv4ex
    @bennicholl-kv4ex 6 месяцев назад

    how do you choose u and V vector functions?

  • @hyperduality2838
    @hyperduality2838 2 года назад

    The integers or real numbers are self dual:-
    ruclips.net/video/AxPwhJTHxSg/видео.html
    Symmetric matrices (real eigenvalues) are dual to anti-symmetric matrices (complex eigenvalues) -- linear algebra, Gilbert Strang.
    Real numbers are dual to complex numbers.
    Complex numbers are dual.
    "Always two there are" -- Yoda.
    The spin statistics theorem:-
    Symmetric wave functions (Bosons, waves) are dual to anti-symmetric wave functions (Fermions, particles) -- wave/particle or quantum duality.
    Bosons are dual to Fermions -- atomic duality.
    Duality creates reality!

  • @balasavenedintulashabalbeoriwe
    @balasavenedintulashabalbeoriwe 7 месяцев назад

    Hey, can you please help me? I am with you until 13:37 I'm not able to see how the angles involving the origin are preserved (it seems like pi/2 angle becomes pi) is this because the derivative is 0 there or some other reason? Thank you

  • @geoffrygifari3377
    @geoffrygifari3377 2 года назад

    One thing i'm a bit confused about with conformal map in this video is that its definition implies angles are preserved, but to preserve angles you need to have crossing lines to form those angles. complex function maps a set of points in the complex plane to another set of complex points.
    does conformality imply that we define (arbitrary) line equations first in the complex plane, then the function preserves the angles between those lines?

    • @monny1815
      @monny1815 2 года назад

      Essentially, the point is that, zooming in very close to a point, the function will look like a linear transformation, which sends lines into lines. Now take two arbitrary lines, as you said, and look at them close to their point of intersection ,these will form an angle between their direction vectors. The fact that the linear transformation rotates every vector at the same rate, implies that it rotates the line vectors at the same rate hence the angles are preserved. Note that this is a local property and not global, in general a complex derivative will NOT send lines into lines, but zooming close enough this will happen, and if we look at the portions of lines then the angles of those portions of lines will be preserved.

    • @vcubingx
      @vcubingx  2 года назад

      Right basically what Monny said. If a function is conformal at a point, the zoomed in transformation preserves angles as well - this means that for any choice of curves intersecting at that point, the angle (here, angle is the tangent angle) is preserved

  • @Ganerrr
    @Ganerrr 2 года назад +3

    anyone else kinda hoping he would try and somehow explain the C'th derivitive of a function, sorta like how you can take the 0.5th derivitive lol

    • @connorhayes2374
      @connorhayes2374 2 года назад

      he has

    • @vcubingx
      @vcubingx  2 года назад

      I've covered this already! Check out my "fractional derivative" video from a couple years back. Although I doubt I'll cover topics like that again, it's ridiculously hard to come up with good visual intuition for those topics

  • @CyclesAreSingularities
    @CyclesAreSingularities Год назад

    aha! so the derivative of a complex function is the complex number you can multiply a small change of z with to get the actual transformation of the function so that the difference in the input z and dz is equal to the difference in the output z and dz

  • @hannesstark5024
    @hannesstark5024 2 года назад

    Fantastic!

  • @erumaaro6060
    @erumaaro6060 2 года назад

    So, loosely speaking, complex numbers (Re + i*Im) can't "represent de derivative" of non-holomorphic functions.
    Is there any other type of number (quaternion etc) that could express the "derivative" for some of those functions?

    • @vcubingx
      @vcubingx  2 года назад

      The Jacobian Matrix!

    • @erumaaro6060
      @erumaaro6060 2 года назад

      @@vcubingx I see.
      So, for functions that maps C to C, that would give 4 partial derivatives, which give 4 real numbers for a given input, right?
      So it could technically be represented by a quaternion.
      I see no need nor use for it though.😅

  • @sitrakaforler8696
    @sitrakaforler8696 2 года назад

    great job m8

  • @ゾカリクゾ
    @ゾカリクゾ 2 года назад

    Top quality.

  • @rudranshgoel3301
    @rudranshgoel3301 2 года назад

    Aren't cauchy reimann equations just necessary condition and not sufficient for a function to be complex differentiable. (This is what my prof told in the course on complex analysis)

  • @gurkiratsingh7tha993
    @gurkiratsingh7tha993 2 года назад

    Great video, I have a doubt, why can't we just solve for s in Zeta(s) = 0 by using the analytic continuation of the zeta function.

    • @ammyvl1
      @ammyvl1 2 года назад +2

      how would you propose we do this?

  • @geoffrygifari3377
    @geoffrygifari3377 2 года назад

    hmmm.... i have difficulty reading the values when we transform the coordinate axes from the complex variable z to the complex function f(z).
    Is it right to say that, after transformation, the values read from cartesian axes are f(z) and the values read from the wonky transformed coordinate axes are the original z?

    • @vcubingx
      @vcubingx  2 года назад

      Not sure I understand what you're asking. Give me a timestamp and example

    • @diribigal
      @diribigal 2 года назад

      @Geoffrey yes, I think what you said is correct.

  • @NeerajVerma786
    @NeerajVerma786 Год назад

    You said that scaling and rotating (-1+2i) according to (-2+4i) will give (-3-4i) but (-1+2i).(-2+4i)=(-6-8i) not (-3-4i) also Scaling (-1+2i) by 2 root 5 is 10 but magnitude of (-3-4i) is 5. I am not able to understand how the transformation leads (-1+2i) to (-3-4i)????

  • @vanadium4603
    @vanadium4603 2 года назад

    what is the song in the background?

    • @vcubingx
      @vcubingx  2 года назад

      It's in the description

  • @vaguebrownfox
    @vaguebrownfox Год назад

    Heyy, did anyone tried to figure out the proof for equations in 14:49 ?

  • @akf2000
    @akf2000 10 месяцев назад

    This is embarrassing but your explanation of the real derivative was the first time it clicked with me

    • @vcubingx
      @vcubingx  9 месяцев назад +1

      Not embarrassing at all!! That perspective of the real derivative is just never taught, but gives a great way to understand more intricate versions of the derivative :)

  • @abhisheksamal1970
    @abhisheksamal1970 2 года назад +2

    Also make a video on the convolution operator..... We want to visualise the
    Convolution
    Found this video:--
    ruclips.net/video/QmcoPYUfbJ8/видео.html
    This doesn't have visual solution

  • @Akshaylive
    @Akshaylive 10 месяцев назад

    @14:45 has an error in the last equation

  • @kasugaryuichi9767
    @kasugaryuichi9767 2 года назад

    It's pretty beautiful

  • @wugionyoutube
    @wugionyoutube Год назад

    Nicely done, congratulations.
    With that "visually explained" though, I was given a wrong impression, expecting visuals of a surface representing a complex function, together with its tangent planes representing its derivative. These can be seen in the video *Derivatives* of my 4D complex functions channel, here: ruclips.net/video/zuwObgLTda8/видео.html

  • @tuongnguyen9391
    @tuongnguyen9391 Год назад

    Is this wirtinger calculus ?