Solving systems of linear equations - Harder example | Math | SAT | Khan Academy
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- Опубликовано: 18 ноя 2024
- Watch Sal work through a harder Solving systems of linear equations problem.
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just do 9/2 = 4.5 and then divide 14y by 4.5 to find the answer.
3:23 why did we Multiple each side by 2?
To get rid of 2 in denominator in left hand side
@@sarthaksonawane2911 oh thank you, and why did we flip the sides and made reciprocal?
@@zyadammar6448 it's cuz 'a' was in denominator........your wlc
ruclips.net/video/pBN9951GcNg/видео.html with the test being digital luckily it can be solved this way too now.
What I don't think this problem will not take more than 20 sec .we can do it by using A1/A2=b1/b2≠c1/c2
Please explain me
Class 11 Mai padhe hai😂
Btw I'll give my SAT next year, wish me luck
@@sarthaksonawane2911 that's great! Which university are you gonna apply to?
@@sarthaksonawane2911 that's great, I'm planning for MIT, Stanford,UC Berkeley, Carnegie Mellon... Or JEE😂😂😂
@@sarthaksonawane2911WelL what was ur result?
M 150