thanks for all you do to provide a great education for completely free. i struggle on some topics in my physics class and i always get excited when i see you've done a vid on it. i appreciate it more than you know! keep up the fantastic work
Everything clicked once you said that no work is done by friction- I was so confused by this concept! Thanks for the video content, and thanks for all the hard work you put into these!
Why do we solve for the displacement in the parallel direction? is it because the velocity final is the velocity of the cylinder parallel to the incline. Using height initial wouldn't also work in the UAM equations (4:55) because everything is in the parallel direction right? So that is why we need the displacement in the parallel direction right? or is this the wrong reason.
I'm homeschooled by your videos and i'm learning ap physics a lot better than my friends who are going to schools , the reason is because you've tought me learn but they're being tought to memorize thank you
How did you gather data for the chart you drew in the illustration part? I am currently doing a term project on rolling without slipping on an inclined plane and got stuck on gathering data.
I would guess that he used video capture and tool like "Physics Tracker" to lot the position of the some part of the face of the cylinder that is facing toward us (knowing the length of the board).
There is static friction, there just is no work done by the force of static friction. Static friction is a force of constraint, rather than a force of work. The instantaneous center of zero velocity (ICV) is at the point of contact with the incline surface, where the object is locally and instantaneously at rest. Because the ICV has zero velocity, any force that acts on the object only at the ICV will do zero work on the object.
You might wonder, how does a car speed up, if the static friction force (the force of propulsion), does no work? The way this works, is the static friction force of the wheel pushing backward on the road is attempting to do work in the road. However, due to the fact that the road is ultimately attached to the Earth, and the Earth is significantly greater in mass, the Earth's motion is negligible, and so is the work done on the Earth. The Earth/road system reflects this work back onto the car, and thus the work done by the engine, ultimately becomes work done on the car. The net work done by the static friction force is close enough to zero, because the work is ultimately reflected back to the car.
@@carultchIf I attempt to solve this problem using Newton's Second law, then I end up getting a = g sin@ - û g cos@ where @ is the angle theta and û is the coefficient of static friction. Will this be a correct solution, only I didn't use the rotational inertia!
@@carultchBut I would like to ask how can work be reflected? What I endeavor to implicate here is that I have never heard such thing as reflection of work, except reflection in a wave! Does this notion even exist?
Mr. P, If I attempt to solve this problem using Newton's Second law, then I end up getting a = g sin@ - û g cos@ where @ is the angle theta and û is the coefficient of static friction. Will this be a correct solution, only I didn't use the rotational inertia?!
So you are saying that when you change the radius and keeping the angle the same, the acceleration will be constant every time because the radius and mass cancels each other out?
Because everybody brought m*R^2 to the party, the mass and radius both cancel out of the equation. In a rolling race among several different solid uniform cylinders, rolling without slipping, they all will have the same acceleration on the same incline. What ultimately matters is the factor in front of m*R^2 for calculating rotational inertia, when determining acceleration during rolling without slipping. Rotational inertia I = k*m*R^2, where k is a constant that depends on shape and distribution of mass. For a solid uniform cylinder, k=1/2. For a hollow cylinder, k=1.
Neha Shah mechanical energy is not conserved only when non-conservative forces do work on the system. Gravitational force is a conservative force. It is true that friction is a non-conservative force but the frictional force in the case of ‘ pure roll’ is static and hence does not to do any work on the system.
If you’re doing a lab and your predicted results agree perfectly with the tested results then anyone should be celebrating like that. It takes a miracle to make those two numbers equal each other
test's in one hour and this is the exact kind of problem i've been confused about that use of the kinematic equation blew my brain open i have ascended i will be getting a 6
Yeah I thought he had three brothers who happened to look similar to him. He has a "the making of" video that shows how he really does it. It is him in character playing the roles of each of his students, and he uses a green screen chroma key to clone himself in the video editing. Mr P the teacher, is what he ordinarily looks like out of character.
![Seungmin "그렇게, 천천히, 우리(As we are)" | [Stray Kids : SKZ-PLAYER]](http://i.ytimg.com/vi/kAzmhLHePqU/mqdefault.jpg)
Underrated! The production quality of this is amazing.
THANK YOU!
@@FlippingPhysics I'm a student preparing for jee and I've never seen a teacher making these kind of physics videos, u deserve millions of subs sir 👏👍
thanks for all you do to provide a great education for completely free. i struggle on some topics in my physics class and i always get excited when i see you've done a vid on it. i appreciate it more than you know! keep up the fantastic work
I will do my best!
your vid is so well done and means a lot to me . the clarity and the editing and the humor in the vid are all well planned and choreographed .
Glad you appreciate it!
Everything clicked once you said that no work is done by friction- I was so confused by this concept! Thanks for the video content, and thanks for all the hard work you put into these!
You're very welcome!
I used to watch this channel 2 years ago when I had AP Physics 1... your channel was one of the reasons I passed the exam! Thank you :-D
You are certainly welcome. Glad to have helped you out!
I was focused then I realized everyone was the same person 😂
I have no idea what you are talking about.
The demonstrations you use are very helpful, I hope your channel grows exponentially
I hope so too!
reallyyy helpfull . amaziingglyy demonstrated
Thank you so much ! Now I know the process of solving the problem that came up in the test today..:)
Why do we solve for the displacement in the parallel direction? is it because the velocity final is the velocity of the cylinder parallel to the incline. Using height initial wouldn't also work in the UAM equations (4:55) because everything is in the parallel direction right? So that is why we need the displacement in the parallel direction right? or is this the wrong reason.
I'm homeschooled by your videos and i'm learning ap physics a lot better than my friends who are going to schools , the reason is because you've tought me learn but they're being tought to memorize thank you
Wonderful!
How did you gather data for the chart you drew in the illustration part? I am currently doing a term project on rolling without slipping on an inclined plane and got stuck on gathering data.
I would guess that he used video capture and tool like "Physics Tracker" to lot the position of the some part of the face of the cylinder that is facing toward us (knowing the length of the board).
Does gravity impact acceleration of a rolling object?
Why is there no static friction? Without static friction how can the object rotate?
There is static friction, there just is no work done by the force of static friction. Static friction is a force of constraint, rather than a force of work.
The instantaneous center of zero velocity (ICV) is at the point of contact with the incline surface, where the object is locally and instantaneously at rest. Because the ICV has zero velocity, any force that acts on the object only at the ICV will do zero work on the object.
You might wonder, how does a car speed up, if the static friction force (the force of propulsion), does no work?
The way this works, is the static friction force of the wheel pushing backward on the road is attempting to do work in the road. However, due to the fact that the road is ultimately attached to the Earth, and the Earth is significantly greater in mass, the Earth's motion is negligible, and so is the work done on the Earth. The Earth/road system reflects this work back onto the car, and thus the work done by the engine, ultimately becomes work done on the car. The net work done by the static friction force is close enough to zero, because the work is ultimately reflected back to the car.
@@carultchIf I attempt to solve this problem using Newton's Second law, then I end up getting a = g sin@ - û g cos@ where @ is the angle theta and û is the coefficient of static friction. Will this be a correct solution, only I didn't use the rotational inertia!
@@carultchBut I would like to ask how can work be reflected? What I endeavor to implicate here is that I have never heard such thing as reflection of work, except reflection in a wave! Does this notion even exist?
Nice content, awesome illustrations
Thank you so much 😀
is this assuming the maximum force of static friction at the point of contact between the incline and cylinder? If not, would the equation be a
Much thankful from Denmark
You are welcome from The USA!
Mr. P, If I attempt to solve this problem using Newton's Second law, then I end up getting a = g sin@ - û g cos@ where @ is the angle theta and û is the coefficient of static friction. Will this be a correct solution, only I didn't use the rotational inertia?!
Mr. P is amazing!!!!!!
Amazing Video but I have a question. How did you measure the velocity of the cylinder rolling down?
Just Awesome !!!
So you are saying that when you change the radius and keeping the angle the same, the acceleration will be constant every time because the radius and mass cancels each other out?
Because everybody brought m*R^2 to the party, the mass and radius both cancel out of the equation. In a rolling race among several different solid uniform cylinders, rolling without slipping, they all will have the same acceleration on the same incline.
What ultimately matters is the factor in front of m*R^2 for calculating rotational inertia, when determining acceleration during rolling without slipping. Rotational inertia I = k*m*R^2, where k is a constant that depends on shape and distribution of mass. For a solid uniform cylinder, k=1/2. For a hollow cylinder, k=1.
Thanks a lot Sir.
You are welcome, as always.
wait, why doesn’t the parallel component of the weight do work on the cylinder and change its mechanical energy?
Neha Shah mechanical energy is not conserved only when non-conservative forces do work on the system. Gravitational force is a conservative force. It is true that friction is a non-conservative force but the frictional force in the case of ‘ pure roll’ is static and hence does not to do any work on the system.
I've had students in class do exactly what Billy did!
"The physics works!" part?
If you’re doing a lab and your predicted results agree perfectly with the tested results then anyone should be celebrating like that. It takes a miracle to make those two numbers equal each other
test's in one hour and this is the exact kind of problem i've been confused about
that use of the kinematic equation blew my brain open
i have ascended
i will be getting a 6
Enjoy that 6 my friend!
These skits really give me a "Community" vibe.
arigato sir
Hahaha the physics works!
Why yes, it does.
Why did Bobby "fake cough"?
😂🤣 does it physics
eyyyy quadruplets😃😃😃
Yeah I thought he had three brothers who happened to look similar to him. He has a "the making of" video that shows how he really does it. It is him in character playing the roles of each of his students, and he uses a green screen chroma key to clone himself in the video editing. Mr P the teacher, is what he ordinarily looks like out of character.