Kinematics - Free Formula Sheet: bit.ly/4dtD4Ti Direct Link to The Full Video: bit.ly/3WZGbJW PDF Worksheet - 18 Questions: bit.ly/3Co9UEz Full 1 Hour 33 Minute Video: www.patreon.com/MathScienceTutor
Hey, I just graduated today. I used your videos for 3 years and I really appreciate all you've done for me. As I am no longer studying this will be the last time I need to rely on your videos. Goodbye old friend, thanks for everything
Learned more here than in my actual school... Well our physics and chemistry teachers arent bad but its easier with individual videos and you explain them well
Im teaching myself calculus with your videos i love it. Science is my passion with many opportunities very fascinating. Thank you for teaching and keep up the great lectures
Your voice set me in a motion of high speed and velocity Seeing the way you solve problems makes my heart accelerate Hoping that one day I'll see your face makes the Focal length of my eyes full with kinetic energy Making Newton's third law of motion real The force between me and your videos is a centrifugal force 🤣 Just to say I love you. Thanks a lot
Good Morning , I just wanted to thank you. Because of your awesome content, I was able to pass the General Science Praxis and change my certification to high school science. Keep up the great work, this is an awesome resource for all students, in person and virtual.
Hey org. Chemistry. I was one of your fun. I usually watching your videos whenever I don't understand my chemistry and physics module I hope you can help me at this problem in physics 🥺🥺 Problem: Smokestack scrubber removes undesirable particles by first adding some excess electrons and then using electric forces to pull the particles out of the air. Consider a soot particle of mass 𝑚𝑠𝑜𝑜𝑡 = 1.0 𝑥 10−12 𝑘𝑔 that travels upward in a smokestack and a charge of 𝑞𝑠𝑜𝑜𝑡 = 1.1 𝑥 10−17𝐶. Assume the electric field in the scrubber is produced by two parallel, square plates of width 𝐿 = 1.0 𝑚 and separation 𝑑 = 0.010 𝑚, with charges ±𝑄. What must be the value of the electric field between the plates so that the force on the soot particle is equal to the weight of the particle? (A real scrubber would use a collection of many pairs of such plates in parallel) What charge Q on the scrubber’s plates is required to produce the electric field in part (a)? Recognize the Principle (How will you find the magnitude of E) (5 points)
Sketch the Problem (5 points)
Identify the Relationships in part (a) (5 points) -“The formula”
Solution for part (a) (5 points)
Identify the Relationships in part (b) (5 points) -“The formula”
Solution for part (b) (5 points)
Conclusion: (5 points)
Hoping you will respond or make some videos about it. Many people having a hard time solving it🥺 Thank you in advance! Love from Philippines 💐
Thank you so much for well explained definition of and diffrences between distance and displacement, speed and velocity. keep up the great work and continue sharing more contents on uniformily accelerated motions
Hi! Good luck taking Physics next year! We have made a playlist of hundreds of worked out Physics problems so that you can full grasp the material! Check it out! Here is the link: ruclips.net/p/PL_3h4GvKc6GAniH6iyxOqX35ZI-tGEChJ Cheers! 😀
@@jhaixxinawaj1093 Basically, you can decide what is positive yourself depending on the situation. For example you can make north and east positive while south and west negative. You can also do north and west positive while the opposites are negative. Here, he made south and west positive for simplicity .
@@hmmnotsure hello, I know it's been 11 months since you said your comment but if you don't mind me asking for clarification, why is it not possible to put a positive on north to south and vice versa? I'm kind of confused, I'd be really grateful if you'd clear up my confusion, sorry for my English, it's my second language. Thank you!
Hi! We have made a playlist of hundreds of worked out Physics problems for students like you who want more practice problems! Here is the link: ruclips.net/p/PL_3h4GvKc6GAniH6iyxOqX35ZI-tGEChJ Cheers! 😀
Please how did you calculate the displacement for you to get that 250, because have try to calculate my and his giving me 62,500, please how did you calculate it thanks
K-F-C = Keep Flip Change is used when finding the difference between integers, 1. You have to keep the first term. 2. You have to flip the sign from "-" to "+" 3. You have to change the signs of the second term into its opposite, so for example (-) to + and + (-) 👍
At 6:16, I thought in order to get the displacement you have to subtract the final position to the initial position. Why is it not 6 - 10? Although it doesn't make any sense, the formula is confusing.
I'm also kind of confused on that but displacement is basically how far you are from your starting position so from that definition, 4 miles is correct.
bruh u guys completly ignored how it works. displacement = final - initial. Initial was not 10 it was 0, the car just went +10 but started at 0. Final was 4 not -6, the car just went -6 from the +10. displacement = 4 - 0, displacement = 4.
Kinematics - Free Formula Sheet: bit.ly/4dtD4Ti
Direct Link to The Full Video: bit.ly/3WZGbJW
PDF Worksheet - 18 Questions: bit.ly/3Co9UEz
Full 1 Hour 33 Minute Video: www.patreon.com/MathScienceTutor
thanks
Hey, I just graduated today. I used your videos for 3 years and I really appreciate all you've done for me. As I am no longer studying this will be the last time I need to rely on your videos. Goodbye old friend, thanks for everything
dis so sad :(
@@berreyl1689 yeh 😭😭
Very good,. Congrats.
Good luck out in the world!
Congrats, all the best!
And when the world needed him most, he returned.
what do you mean return? he never left, did he?
@@ijustc0mment its an avatar reference...
@@wars4242 Yeah, I know. I was asking if he left because his video don't look like he left. Their gaps are not so big. 8months, 9 months
Literally one of the most helpful people on youtube when you have a test the next day, thank you
It's literally a 'last-minute-studying-before-exam' kind of video.😂😂😂😂
Learned more here than in my actual school...
Well our physics and chemistry teachers arent bad but its easier with individual videos and you explain them well
I wish you were my teacher for math, physics, and chemistry.
If all math, physics teachers were like him, no one would hate these subjects
The best teacher I have ever seen. The class was awesome. 🔥
watching your videos from South Africa, you're the best man you helped me get level 7 in Physical Science and Mathematics
Im teaching myself calculus with your videos i love it. Science is my passion with many opportunities very fascinating. Thank you for teaching and keep up the great lectures
I watch every single add of yours, you're getting me through school man
Words can't express my love for you,JG!! ❤️❤️
You are awesome ! It’s so easy to understand with you. Thank you!!
Wait, but tell me why this is exactly what I needed
Hi I just started high school I hope your videos would help me because so far, they definitely are!
i have to retake a test i know NOTHING about an this is the topic an i i swear u save me thanks
Your voice set me in a motion of high speed and velocity
Seeing the way you solve problems makes my heart accelerate
Hoping that one day I'll see your face makes the Focal length of my eyes full with kinetic energy
Making Newton's third law of motion real
The force between me and your videos is a centrifugal force 🤣
Just to say I love you.
Thanks a lot
BABES-
rizz
halo dude- math test tomorrow- ur a lifesaver, my guy
Good Morning , I just wanted to thank you. Because of your awesome content, I was able to pass the General Science Praxis and change my certification to high school science. Keep up the great work, this is an awesome resource for all students, in person and virtual.
Yeah u r right
I literally have a test in 4 hours & this is how I prepare, thank you
I appreciate you brother 🙏
You’ve done immensely well.
WELL DONE KING KEEP UP THE GREAT WORK ❤🎉🎉
You are the reason i exist as a student.
Thank you very much 🙏
We can buy Education, but wisdom is a gift from God, my Brother ur wisdom is exceptional 👌
thanks for breaking everything down most helpful video i came across so far
I just got in to highschool, I want to say thanks a lot for the tutos and I will continue to look forward for more, thanks😊
we literally have classes at my university so I just watch your videos and they help thanks for taking time with the explanation😙😗
I was wondering where this video went. I was relying on it last year. Really glad that it’s back! :-)
Man these videos are amazing good job u have helped me alot :)
Thank U so much this video is so much helpful
This video was very helpful for my exam
I was so idiet but know i am a top student thenks sir😊😊❤😊🎉🎉🎉🎉🎉🎉🎉
Now start watching grammar lectures too
Don't be so mean bro lol@@yusuf2638
@@yusuf2638 start taking critical thinking lessons because their first language might not be english
@@yubas77 so how did they understood the whole video?
+ you're so dumb tbh
@@yubas77 too long didn't read
I may only be a freshman, but that doesn't stop me from wanting to learn this XD
KEEP DOING WHAT YOU'RE DOING!!!!1
Hey org. Chemistry. I was one of your fun. I usually watching your videos whenever I don't understand my chemistry and physics module I hope you can help me at this problem in physics 🥺🥺
Problem: Smokestack scrubber removes undesirable particles by first adding some excess electrons and then using electric forces to pull the particles out of the air. Consider a soot particle of mass 𝑚𝑠𝑜𝑜𝑡 = 1.0 𝑥 10−12 𝑘𝑔 that travels upward in a smokestack and a charge of 𝑞𝑠𝑜𝑜𝑡 = 1.1 𝑥 10−17𝐶. Assume the electric field in the scrubber is produced by two parallel, square plates of width 𝐿 = 1.0 𝑚 and separation 𝑑 = 0.010 𝑚, with charges ±𝑄. What must be the value of the electric field between the plates so that the force on the soot particle is equal to the weight of the particle? (A real scrubber would use a collection of many pairs of such plates in parallel) What charge Q on the scrubber’s plates is required to produce the electric field in part (a)?
Recognize the Principle (How will you find the magnitude of E) (5 points)
Sketch the Problem (5 points)
Identify the Relationships in part (a) (5 points) -“The formula”
Solution for part (a) (5 points)
Identify the Relationships in part (b) (5 points) -“The formula”
Solution for part (b) (5 points)
Conclusion: (5 points)
Hoping you will respond or make some videos about it. Many people having a hard time solving it🥺
Thank you in advance! Love from Philippines 💐
Thank you so much for well explained definition of and diffrences between distance and displacement, speed and velocity. keep up the great work and continue sharing more contents on uniformily accelerated motions
Watching your video from 2019...
Easy explanation 👍👍love from Indian students
Thank you for this amazing video!
oh thank God you uploded this today. Next year am taking physics
Hi! Good luck taking Physics next year! We have made a playlist of hundreds of worked out Physics problems so that you can full grasp the material! Check it out! Here is the link: ruclips.net/p/PL_3h4GvKc6GAniH6iyxOqX35ZI-tGEChJ Cheers! 😀
@@GlaserTutoring tysm
it all makes sense NOW oh god this was so helpful tanks
Good video.
Can’t be that easy…
Bro you legendary, i feel you have lived since ancient Egypt’s time.
On the example at 7:13 why don’t you use the Displacement = Xf - Xi formula ? Isn’t that what u need to do to find displacement always?
Omg I have the same problem did u find the answer?
Thank you so much I finally understand
This helped sooo much 😭😭🤝thank you
Refreshing my brain 😀
ur saving me in phys 124 omg
good complete sir and we will support you don't worry
Thank you so much now I understand
Who else is studying for a physics final exam?😂
thank yoooou
God bless you Sir
Thank u for sharing knowlage!
My lesson hayss thank u
thanks for the video this was really helpful
love you chemistry daddy
This is Physics
@@Hanin-u2r 💀
2a. The average speed is 62.5mi/hr
2b. The average velocity is 37.5mi/hr
the right triangle trick is good
saving my ass in BIG 2024 is much-appreciated brotha he carries me in high school now in uni 😭😭😭😭🙏🙏🙏🙏
thank you so much🥹
Thank you sooo much♥️♥️♥️
Wonderfull ....... thank you sir
I am an indian . I really like to listen u r classes
Thank you good sir
ba't kasi nag engineering pa ako eh. haha charot lang, lods
Thx I am going to read my 9th grade physics and this is gonna help me a lot :D
wait u got physic as a freshmen 0-0
What application to draw is it? Btw very nice video
When should i use final - initial and when shall i not
Man I love you
Good thing that I still have two years left to graduate
im just going to ask why did u use law of attraction or smth in the displacement
Thanks you helped me a lot 🤩
Well explained...can you do a video about rawl's law
hey Mr JG I always use your videos they are very helpful
I just love you brother
whats the difference between the net displacement and the delta x which is the change in position? Are they the same?
3h before my Cambridge maths exam... 😂
How'd you do?
@@iranianintelligenceagency9337 I was aiming for A* but got an A… 🤷♂️still 👌
@@matthieuoogur8750 well done!👍
broo you are the best ))
11:27
thanks
To the lef to the righ to the eas to the Wes
may i asked what is the answer of the last given problem which is a bus travels 400miles.............?
I want to know too
Is the velocity for north positive and south negative? What about NE, SE, etc?
14:35, shouldn't this displacement be - 130 since Sally moved west and south which are in the negative directions?
Hi i know it's been a year but can you help me if you know why is it postitve instead of negative?
@@jhaixxinawaj1093 Basically, you can decide what is positive yourself depending on the situation. For example you can make north and east positive while south and west negative. You can also do north and west positive while the opposites are negative. Here, he made south and west positive for simplicity .
@@hmmnotsure Thank you!!
@@jhaixxinawaj1093 Just make sure you don't make both North and South positive, or both East and West positive, because that's not possible
@@hmmnotsure hello, I know it's been 11 months since you said your comment but if you don't mind me asking for clarification, why is it not possible to put a positive on north to south and vice versa? I'm kind of confused, I'd be really grateful if you'd clear up my confusion, sorry for my English, it's my second language. Thank you!
My teacher didn't teach this part well so I got the problem wrong😢 thnk u for thiss
4:40 15:50
i have a question thou at the last problem, why do we need to multiply it by 60 mins?
6:00 I’m so confused
Wasn’t the displacement Calformula
Final position - initial position?
Why did we add then ?
Keep Flip Change/ Keep Change Change
Its a short cut, he explained it in the previous prob.
what app are you using?
11:34
26:13 is it not 272.72 repeating
That's what I was thinking as well, considering when I plugged the variables on my calculator, i got 272.7272...
Does anyone know where I can find practice questions?
Hi! We have made a playlist of hundreds of worked out Physics problems for students like you who want more practice problems! Here is the link: ruclips.net/p/PL_3h4GvKc6GAniH6iyxOqX35ZI-tGEChJ Cheers! 😀
does this playlist for AS Level Physics (9702) covers all the requirements of the syllabus set up by cambridge examinations??
Please how did you calculate the displacement for you to get that 250, because have try to calculate my and his giving me 62,500, please how did you calculate it thanks
Nice
Will you be doing videos on Physics 2 material? Or differential equations?
Can someone please explain to me why at 1:55 it was minus but he added it??? I learned this before but I forgott
K-F-C = Keep Flip Change is used when finding the difference between integers, 1. You have to keep the first term. 2. You have to flip the sign from "-" to "+" 3. You have to change the signs of the second term into its opposite, so for example (-) to + and + (-) 👍
At 6:16, I thought in order to get the displacement you have to subtract the final position to the initial position. Why is it not 6 - 10? Although it doesn't make any sense, the formula is confusing.
I'm also kind of confused on that but displacement is basically how far you are from your starting position so from that definition, 4 miles is correct.
Displacement = Final - initial so it supposedly D= -6-10 , the answer is -16 , I confused on that I had relied to the formula .
@@Thrive2024 me too i think he made a mistake
bruh u guys completly ignored how it works. displacement = final - initial. Initial was not 10 it was 0, the car just went +10 but started at 0. Final was 4 not -6, the car just went -6 from the +10. displacement = 4 - 0, displacement = 4.
@@hamed7071 can you elaborate a little more?
The second example is wrong because the distance between -4 and 4 is 8 units therefore the distance is equal to 15
Btw he said it’s -4, and 5 so therefor the distance is equal to 16
3:16 -4 initial position to 5 final position is 11 not 9 😅
Why do we use 12 as the initial postion instead of -8