Thank u for reiterating this sir. It's interesting the cube table compared to the squares table. With squares there are repeated digits, so some digits are not used. But no repeats in the cubes, only the reversing of 2,3,7 &8. I've also come across methods which work for all cubes, odd and even, one method uses digital sums, and the method you've shown before for even numbers. Maybe some of your viewers would be curious as to the steps used in calculating cube roots of even more digits, as I would be. (If not knowing automatically the roots of 4-6 digits)
Sir here is a small doubt to clear: At the step of subtracting the last part of the number and the cube of the unit digit, in this video you didn't get any kind of borrowing. What if we get it? How do we do it? Eg: 260,917,119. (Odd number) Step 1: We take 9 ( Because the unit digit ends in 9 ). Step 2: 260 is between 216 and 343 (6³, 7³), we take 6 here. Step 3: 117 - 9³ = 117 - 729 = ? We can't get 1 - 2, and also 729 > 117. How do we do it?
the method is bs anyway. there is no utility in being able to find the cuberoot of a perfect cube. you will never use this talent for anything, why not just teach yourself a real method to evolve cube roots?
Thank u for reiterating this sir. It's interesting the cube table compared to the squares table. With squares there are repeated digits, so some digits are not used. But no repeats in the cubes, only the reversing of 2,3,7 &8. I've also come across methods which work for all cubes, odd and even, one method uses digital sums, and the method you've shown before for even numbers. Maybe some of your viewers would be curious as to the steps used in calculating cube roots of even more digits, as I would be. (If not knowing automatically the roots of 4-6 digits)
Simultaneously everybody can learn maths as well as English spoken.
Sir here is a small doubt to clear:
At the step of subtracting the last part of the number and the cube of the unit digit, in this video you didn't get any kind of borrowing. What if we get it? How do we do it?
Eg: 260,917,119. (Odd number)
Step 1: We take 9 ( Because the unit digit ends in 9 ).
Step 2: 260 is between 216 and 343 (6³, 7³), we take 6 here.
Step 3: 117 - 9³ = 117 - 729 = ?
We can't get 1 - 2, and also 729 > 117.
How do we do it?
Add 10 to the 1 and ignore the other 2 digits. 11-2=9; 3x9^2= 243, 24(3) x X= _9, X=3; ans 639
639 is correct answer
Dear sirr the method u discussed is not working for cube root of 33698267 my ans is coming 383 but ans is 323?
Ha yaar mujhe bhi same problem ho rhi is question ke liye jab mai try kiya abhi
Bro you get only one answer!!!
so the answer is 323!!
as you will get 27x = __4 as x=2 only!!!
the method is bs anyway. there is no utility in being able to find the cuberoot of a perfect cube. you will never use this talent for anything,
why not just teach yourself a real method to evolve cube roots?