Partitioning A Segment
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- Опубликовано: 12 сен 2024
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This video was inspired by a great explanation provided by Chris Rime at partiallyderiva... .
Thank you so much and I understand how to solve these types of problems.
You're welcome Srinidhi, glad it helped!
why are youtube teachers always better at explaining than teachers irl?
Hi Citrus! I don't know if I'd say "always," but I'm glad you found this one helpful.
the best explanation ever thank you
You're welcome!
This was very helpful. Easier than the way my teacher taught me. Thank you!
facts
What if the given is a fraction, not a ratio. How to use the fraction in the same way you did? Your idea is super easy to understand.
Thank you....thank you....thank you!! For some reason I have been struggling getting this in my college geometry course. My book is horrible....but you are WONDERFUL!!! God bless you!!
You're welcome, Kristine! Glad it helped!
I spent 20 minutes attempting the first question on my HW only to have my answer not be an option 😭 thank you for this
You're welcome!
thanks
Thank you so much! Cleared up all questions on the topic and showed an easier way to do the problem than what the textbook states.
Thanks Kartik, glad it helped!
Thanks a lot
You're welcome, glad it helped!
Thanks for the example. Really helped my daughter understand the topic.
Thanks Bruce, glad it helped!
Thank you! My 8th grade brain couldn’t grasp the idea until I watched this video. My Geometry teacher didn’t teach us anything and just assigned the assignment so I was quite confused
You're welcome! Glad it helped.
uh...ah... *actively comprehending he has just learnt something he has been struggling on for 2 weeks for in 13 minutes*...ah...I - ...I - ....thank you.
You're welcome! Glad it helped.
I know this a video from years ago but I’m so happy I found this to help me. Thanks sm! I don’t even remember getting taught this but it’s on my final review so
You're welcome! Glad it was helpful.
I can’t believe I finally solved my exercise with just watching this video!!! So glad I came across your video, honestly!!! 😃😃😃
Me too! Glad it helped, Anastasia!
the oval he draws at 3:08 is so satisfying
👍
thank you so much that was really helpful👍🏽
Thanks Sevinch, glad it was helpful!
Thank you so much
You're welcome!
Thank you so so so much!!!! I really needed this help!!!
You're welcome! Glad it helped!
I feel like the first step wasn’t necessary you probably could of done it a earlier way because I felt like this was way to long to get to the point but thank you!
Hi Tee! Do you mean the step where I draw segment AB and label it with the coordinates? I suppose you could get the solution without doing all the drawing that I do in the video, but many students struggle with visualizing the problem, and I find that drawing a diagram is often very helpful.
thank you and thank you from Thailand.I was spent my whole day finding a clips that make me clear about this until I found your clip :D.
You're welcome! Glad it helped.
This made me have a mental breakdown, why do people like math? Something i will never ever understand.
Omg same Im starting to hate math
Math helps us understand the world. Still hate this though
Hi Mallary! Sorry to hear about your breakdown. Different people like different things, I guess.
Thanks! Geometry regents coming up and this cleared up the topic.
You're welcome! Glad it helped!
Quick question you said.. you subtract 3x for x distance but when you got to y distance you said add 3y.. how do you know when to add or subtract?
Hi Imani! I'm really not sure what you're asking here. Can you tell exactly where in the video that I "subtract 3x for x distance" and where exactly do I "add 3y" for y distance?
thanks bro u helped with my test
You're welcome Maria! Glad it helped!
This was very nice work but it wont work for the problems i have, its unclear, no disrespect 😣😥
Hi Lordx, if you can be more specific about what was unclear, or what problems you have, I'll try to help.
@@lancebledsoe I guess Im confused on where you start talking about X - 7 and Y - 4 i just never seen that when i'm getting teached also the line is usally on a graph and had distance both vertically and horizontally and you would have to count the length of the line vertically and horizontally to find P, or C in your case. Is this better?
@@ryaan6177 these are great questions. If I get a chance I may try to make a video that addresses them more clearly, but until then here are some short answers:
1) Counting boxes is a great way to find the distance between two points, but it only works if you know both coordinates for *both* points. In this video, if I was told the coordinates of Point C, then I could calculate (or measure) the distance from A to C, and from C to B, and then I could calculate the ratio of those two distances. Since what I'm *given* is the ratio of those two distances, and what trying to *find* is the coordinates of Point C, I have to use a different method.
2) While counting boxes is one way to find the distance between two coordinates, you can also express the distance between coordinates by subtracting, which is what I'm doing in this video. For example, for points Q(5,7) and R(9, 15), the distance between the x-coordinates is 9-5, and the distance between the y-coordinates is 15-7. If I didn't know the actual numerical coordinates for point R, I could assign them variable names (like maybe "b" and "c"), and I could say the distance between the x-coordinates is b-5, and the distance between the y-coordinates is c-7.
3) You *can* solve this problem on graph paper, but it's not really necessary (unless you just want to see what the line will look like when it's graphed).
How do you partishon x
Hi William! I'm not sure I understand your question. In this video I'm showing a way to partition a line segment into a given ratio, which means to "break the line segment down" into two smaller segments whose lengths will be in the given ratio. When you say "How do you partition x," does the "x" in your question refer to a line segment?
I love this.
***** Thanks Neil!
it really helped my niece !!
Thanks Annette, glad it was helpful.
I still don't understand why you added "+3X".
Added "+3X" where?
@@lancebledsoe 5:47
You added 3x, subtracted -14 and divided by 5.
Where did those come from?
I'm sorry, I'm not very good at mathematics.
@@durganaveen4152 Gotcha. From 5:47 to 6:26 I'm just solving the equation I set up, i.e., finding the numerical value of "x", the x-coordinate of the point I'm looking for. "Solving an equation" can be thought of as performing a series of steps to a true statement. The "true statement" is the equation you want to solve (in this case, 2x+14=24-3x).
Solving an equation essentially means manipulating the numbers and variables in the equation so that you get your variable on one side of the equation by itself, and everything else (i.e., the numbers) on the other side of the equation. When you do that, your equation will look like "x= [some number]" and you will have your solution.
The most basic idea in equation-solving is the idea of "keeping the equation balanced"; in other words, if you do something to one side of the equation (as you're trying to get all your variables together, or all your numbers together), you have to do the same thing to the other side. As long as you always do that, your equation will remain "balanced"; it will remain a true statement.
The reason I added 3x, subtracted 14 and divided by 5 (in that order) is because by performing those operations (to each side of the equation), I was able to change my equation into a statement that said "x=2". And since the statement I started with was true, and since every time I did an operation to one side of the equation, I did the same operation to the other side, I know that the final statement (x=2) is true. And that gives me the solution to my equation.
Did that help?
@@lancebledsoe yeah i guess i got it 😅. Thanks
It doesn’t work for all problems 😣
Hi BellPepper! Not sure what you mean when you say it doesn't work for all problems. You mean like, "This method doesn't work for problems involving graphing functions, or probability, or geometric transformations", or did you mean "There are some 'partitioning a segment' problems for which this method doesn't work"? If it's the former, I agree; if it's the latter, please share some examples.
Lance Bledsoe hi, sorry for being unclear. This is the problem I’m stuck on:
Given points A(3,-5) and B(19,-1), find the coordinates of point C that sits 3/8 of the way along AB closer to A than to B.
I used your method and I just got large fractions. Maybe I’m doing something wrong ?
@@bellpepper6697 Interesting. I can't immediately see any reason why this method wouldn't work. Let me try it and I'll get back to you.
Lance Bledsoe alright, thank you 🙏
@@bellpepper6697 Take a look at this and let me know what you think: ruclips.net/video/7yOuX-aVCxA/видео.html
can you also use this method when it’s shown on a graph ?
Hi Savanna! You absolutely can. The first thing I would do is just identify the coordinates of the endpoints of the given line segment (that is, read the coordinates from the graph), and then rewrite the problem so that it matches the wording in the problem I show in the video. Now you can solve it the same way!
Lance Bledsoe also, if it was asking to find point c instead of point b, could you still use this method or would you need any added steps ?
Lance Bledsoe Essentially, if it was asking you to find the coordinates of the other endpoint, could this way still be used ?
Yes, this method can still be used. Referring again to the video, if you were looking for the coordinates of endpoint B, and were given the coordinates of endpoint A and midpoint C, then you would use (x, y) to represent the coordinates of endpoint B; all the other steps would essentially be the same.
Hello sir...would like to recommend easier formula.
Hi Spyro's Adventures! Did you mean that you would like for ME to recommend an easier way/formula to solve these types of problems? If so, this is the easiest/clearest way that I know. But if you meant that YOU would like to recommend an easier formula, please do! I'd love to hear about other/easier ways to solve these types of problems.
THANKYOU I LOVE IT !!!!!!!!!!!!!!!!!!!!!
It is not working
Hi V10, what exactly is not working?
I still don't get it I'm not good at math can go little slower next time
Hi Ashano! Here's a pro tip: pausing the video, or rewinding it to rewatch a segment multiple times, is kind of like having the instructor go slower. Hope this helps!