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你啲片真係好正

FROM 0 TYO MATTHEW LEUNG

原來DSE同HKCE差那麼遠...

great

可唔可以教mean mode median 加咗k個人 然後改變咗+1/1%的mean/mode/median然之後估K嘅最大最細值類嘅嗰種邏輯題目😭😭😭

不講其他，但Polar coordinates 其實是重要的

Great Video!

有料

本心唔係舍生取義咩？

Good

❤

Angle Bisector Theorem在2019-I Q17考過了，找Γ的方程時可以用

cool and quick elaboration! Do you have notes provided? I feel confused about the syllabus for the 2025 exam.

點樣prepare中三TSA考試啊？😢

23:15 why sin(180-θ) = sin(θ)🙏🙏

快啲返黎打救我地2025dser😢😢😢

好清楚🙏🏼多謝

多謝你啊，救返我個exam😆，聽完明白晒

點解入晒6粒數會出syntax error?

9:07

The review is comprehensive and well presented. Giving formulae together with proof is much appreciated as knowning 'why' is as important as knowing 'how'. I would like to share a few points for the sake of students. 1. Formulae for inradius r and circumradius R are used together with Heron's formulae which gives area of triangle in formulae using given sides a, b, c: inradius r = area of triangle/semi-perimenter (S = 1/2 (a + b + c), circumradius R = abc/4 x area of triangle (Formula can be proved by area equation: area = (1/2) absinC and 2R = c/sinC) 2. Proof of angle bisector theorem can be done without using sine rule which needs further proof. With usual notation of triangle A, B, C for angles and a, b, c for sides. Let D be the point of intersection on side a formed with angle bisector from angle A, dividing side a into a1 near C and a2 near B. Prove b/a2 = c/a1 as the angle bisector theorem as follows: Areas of triangles ABD and ACD have ratio a2/a1 by equal height triangles with bases a2 & a1. Angle A is divided into two A/2 angles by the angle bisector. Areas of triangles ABD and ACD can be found alternatively using height bsinA/2 from angle B and height csinA/2 from angle C, with line AD as the base for both triangles. Hence the area ratio is b:c which is equal to a2:a1. The usual form of angle bisector theorem b/a2 = c/a1 is established.

本來今日幾傷心看你呢個片 突然開心到飛起 so funny

咁請問一下如果數入邊有A B C D E F G呢？何解？係唔係A =10 B =11 C =12 DEFG⋯⋯啱？

教得清晰易上手

Type 1 problem of subtitution into function - given f(x) = polynomial of x Example: f(x) = x^2 + 3x + 5 Subtitution of number into f(x) gets a number. f(-2) = (-2)^2 +3(-2) + 5 = 3 Substitution of polynomial into f(x) gets a polynomial. f(2x +1) = (2x + 1)^2 + 3(2x + 1) + 5 = 4x2 + 10x + 9 Type 2 problem of substitution into function - given f(polynomial of x) = polynomial of x Example: f((x + 3)/5) = x^2 + 3x + 5 Tranform to type 1 problem by changing f(polynomail) to f(variable): Let (x + 3)/5 be y. (x + 3)/5 = y => x = (5y - 3) f(y) = x2 + 3x + 5 = (5y - 3)^2 + 3(5y - 3) + 5 = 25y^2 - 15y + 5 f(1) = 25(1)^2 - 15(1) + 5 = 15 f(x) = 25x^2 - 15x + 5 f(7x - 2) = 25(7x - 2)^2 - 15(7x -2) + 5 = 1225x^2 - 805x + 135

其實呢題嘅style有啲似CE嘅题目😂C part要意識到cos3x=-cos2x不容易

可唔可以出廉頗藺相如列傳🙏🙏🙏🙏

結構的作用應該還有*引起懸念*

請問centroid條式考dse用係咪都會比分？因為教課書無教。

好似 2026 起 DSE 數學 Core 唔考16進制！ 16進制指一斤16両，許冠傑粵語歌的 “半斤八兩” 。

💪

支持!

想討論一下，「不宜妄自菲薄」 首先我認同日常直譯胡亂輕視自己，係出師表入面係有問題的。 但因為上文提到「侍衛之臣不懈於內忠志之士忘身於內」 以及下文多次提及 幾個忠臣「是以先帝簡拔以遺陛下」 所以，我覺得諸葛亮呢句有可能意思係叫後主唔好睇低自己的國力，自己人好多都係有心做事，好多都係有才幹。 加上最後諸葛亮係為左出師伐魏而同後主講「今南方已定，兵甲已足」來證明己方國家有足夠能力去同曹去對抗。 如果我解：不宜胡亂輕視自方國家的能力 。 這樣是否合當？

其實唔洗死背，一個直角三角形已經可以證明倒呢兩條式係啱

可唔可以share呢份pdf🙏🙏

讀ict個批人應該唔驚

支持麥老師

加油！d片質素咁高竟然咁少人睇😂一定要繼續出片❤

CCC

想問吓數學成個syllabus 可以喺邊度睇？

Log真係幾難

睇完都係覺得好混亂

Like🎉😊

Transformation of matthew leung

點解dselife話2006 LQ is 15.5*1.5 instead of 14.5*1.5?

Thx

又咁多免費嘢益人 希望啊sir管好你把嘴 如果唔係嘴埋去

大家會識做㗎啦！

3:14 k sub 9 nice

考評局看來會開始搞到coordinates geometry 用計數機program 算唔到。例如4點座標面積