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Sir (-1,1) kyu nhi le sakte C ki value ke liye

Thnx sir🙏🏻 🎉

Thnx sir 🙏🏻🎉

Thnx sir 🎉🙏🏻

Thnx sir 🙏🏻🎉

great👍

Thanks Sir

Thanks Sir

Truly well explained Sanjeev Sir!!!

Sir u r doing very great

Thanks 🙏 sir ❤

very relaxing and satisfying solution 😊

Thanks Sir ji

Quick trick: consider the limit as ‘a’ goes to 1. Taylor expand the denominator to see that for small x the integrand looks like ~ 1/x^2. Since the integration is from 0, it diverges. The only option with this divergence is D :)

Very nice question

Very tough question imo ,but you made it sound easy

Sir very thankful of you as I don't have much time for practise of last chapters of jee preparation. And get into confusion of 3 subjects questions. With you I solve every question which you solve on board .

Ghaziabad m kaha h apki coaching

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👍👍

🙏

Thanks Sir

best and relaxing solution

Thanks Sir 👍

thank you sir ive covered most of the good pyqs from your videos throughout my preperation

Wow ❤

Sir kitna sundar question h ❤ thanks sir 🙏

literally similar question in jee advnaced 2024....ab toh adv mains ka copy karna suru kar diya hai🤣🤣🤣

Sir wo integral kese solve hoga?

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good one👍...but sir my approach is different i differencate it w.r.t x as assuming the t as constant and get the same result and correct answer..... sir is this method is good to go or not????

Love the fact that you solved it like how a student would and what should one think .It would have been very easy to say x=i is a factor and start off .Well done .

beautiful question

Brilliantly solved. Discovering i and -i as factors was key to the solution.

Thanks Sir 👍

Thank you sir 😊 very helpful

मैंने 12वीं पास 2015 में किया है लेकिन आपका वीडियो देखना बहुत अच्छा लगता है आपका वीडियो देखने के बाद लगता है आज मैं 12वीं की पढ़ाई कर रहा हूं

Sir ye a+X kaise aaya focal length

A tough question

👍 yes sir aise hi x^5+x+1 aur x^5+x^4+1 ke factor karte hain x = w se zero milta hai isliye x^2+x+1 ek factor hoga.waise x^2 minus aur plus karke bhi kar sakte hain.a^3 - b^3 use karke ek aur hai x^4+12x-5 = x^4+12x+4-9 = (x^2+2)^2 - 4x^2 + 12x -9 = ( x^2+2)^2 - (2x - 3)^2 = (x^2+2x-1)(x^2 - 2x+5)

good question with best solution 👍

3x² = 2x² + x² (x⁴ + 2x³ + 2x²) + (x² + 2x + 2) =(x² + 2x + 2)(x² +1)

How many could solve it in a tensed exam environment?

The first substitution x+y+2 =t is the key to the solution.

Amazing sir Sir can u please upload more such videos on vector and 3 -D They are very highly rated

maza ich aagya easy q krke

Thank you sir ❤

Nice

Thanks Sir 👍

Enjoyed !