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You're welcome! Glad you enjoyed it.

I'm so sorry to hear that you're experiencing some issues and have burned out your transistor. I'd be happy to help you troubleshoot the problem. Could you please provide some more details about your circuit? Specifically, I'd like to know: - What is the input and output voltage difference (i.e., what are the input and output voltages)? - Which transistor model did you use? - What was your load (e.g., resistance, current, etc.)? - Did you use a heat sink with the transistor? I'm here to assist you in resolving the issue.

Thank you for your detailed feedback and insights into the limitations and potential issues with the circuit design. You've raised valid points regarding the lack of protective features and the potential for power loss and overheating, especially with higher input voltages and currents. I appreciate your suggestions for improvements, such as considering the use of fuses for protecting the power transistor. Regarding the simulation and load values, you're correct that using a 1 ohm load simplifies calculations based on Ohm's law. I'll ensure to provide more realistic load scenarios in future demonstrations. Thank you for taking the time to share your insights.

Some time ago, I created a simple linear regulator using the LM7805 IC. When subjected to a heavy load at the output transistor, the LM7805 ceased providing current to the base of the transistor. This occurred because the large current demanded by the load surpassed the capability of the LM7805 to supply it to the transistor base. Regarding the MJ11016's power dissipation of 200W, I've included a note stating that it will deliver 20A only when the voltage difference is 10V or less. Typically, linear regulators are utilized for voltage differences of up to 10V. Special applications might include scenarios like stepping down from a 20V solar PV to a 12V load or from a 12V battery to a 5V load. I've previously uploaded videos on linear regulators, demonstrating that as the input-output difference increases, efficiency significantly decreases, sometimes to as low as 20 or 30%. For input source protection, I've installed a 25A fuse, particularly beneficial when using a car battery. As for a fuse on the output, I've left it to the viewers' discretion, depending on the specific input-output voltage difference and load requirements.

@@technologywithconcept Hello, the specifications of the Darlington transistor are in the datasheet. A MOSFET might be an alternative. It is normal that the efficiency of a linear regulator falls as the voltage difference increases, because all unneeded energy is converted into heat. The efficiency can only be improved by adjusting the input voltage (transformer with two or more output voltages) or with a switching regulator.

@@wernerpeter9706 Considering MOSFETs as an alternative is a valid point, given their different characteristics. Regarding the efficiency of linear regulators, you're absolutely right. The conversion of excess energy into heat can indeed affect efficiency, especially with larger voltage differences. Your suggestions for improving efficiency, such as adjusting input voltage or using switching regulators, are insightful and practical. Thanks for sharing!

You're absolutely right. Ensuring proper heat dissipation for Q1 is crucial in such scenarios. Implementing effective cooling mechanisms or selecting a transistor with higher power handling capabilities can help mitigate overheating issues. This supply can deliver up to 20A when the input and output voltage difference is 10V or less. Maximum power dissipation is 200W.

Thank you so much! I'm thrilled to hear that you find the project interesting.

Yes, you can utilize the 7824v regulator to generate a 24V output from a source with 25 volts or higher input. However, I want to ensure clarity: Do you intending to derive 24V from a 12V battery? If so, this circuit will only reduce the voltage, not elevate it. For stepping up from 12V to 24V, a boost converter is required. I have a video on boost converters available on my channel. Please provide further details about your specific requirements so I can offer tailored assistance. Also, it's crucial to ensure proper heat dissipation by adequately sizing the heat sink for the regulator to guarantee safe operation.

Sim, você pode utilizar o regulador 7824 V para gerar uma saída de 24 V de uma fonte com entrada de 25 volts ou superior. No entanto, quero garantir a clareza: você pretende obter 24 V de uma bateria de 12 V? Nesse caso, este circuito apenas reduzirá a tensão, e não a aumentará. Para passar de 12V para 24V, é necessário um conversor boost. Tenho um vídeo sobre conversores boost disponível no meu canal. Forneça mais detalhes sobre seus requisitos específicos para que eu possa oferecer assistência personalizada. Além disso, é crucial garantir a dissipação de calor adequada dimensionando adequadamente o dissipador de calor do regulador para garantir uma operação segura.

ruclips.net/video/k_iW9QnTyvU/видео.htmlsi=tU1hv3RLOHzlPQ6G

I appreciate your feedback. Could you please specify what aspects of the video you found to be incorrect or problematic? Constructive criticism helps us improve. Thank you! 😊

Thank you for your feedback! I'm glad you found the content straightforward. Yes, typically, operations can be performed within the voltage range of 5-24 V, depending on the specific requirements of the system. Remember that BJTs are current-controlled devices (controlled by base current), whereas MOSFETs are voltage-controlled devices (controlled by gate voltage). For an input voltage range of 5-24V, you can utilize a potentiometer (variable resistor) or an LM317 IC to regulate the output to some extent. If you need further clarification or assistance on implementing this, feel free to ask.

ruclips.net/video/NNd303i97TE/видео.htmlsi=nTQY6MaqXjcVRePl

The TIP142 transistor has a peak current rating of 20A and a continuous maximum current rating of 10A. Achieving the maximum rated current depends on various factors such as circuit design, thermal management, and operating conditions. In real-world applications, it's important to consider factors like thermal dissipation and voltage drop across the transistor, which can affect its ability to handle the rated current continuously. Based on what specific reasons are you asserting that we will never achieve 10A?

To effectively implement reverse polarity protection in your circuit, you should connect the diode in series with the positive supply line. This involves connecting the cathode (marked with a stripe) of the diode to the positive voltage source and the anode to the rest of the circuitry. This configuration guarantees that current flows exclusively in the correct direction, safeguarding your components from potential damage caused by reverse polarity. Ensure to select a diode with an appropriate forward voltage and current rating suitable for your specific application.

I am using SB540 DIODE

SB540 has a maximum continuous reverse voltage (Vr) of 28V and a peak reverse voltage of 40V, along with a forward continuous current of 5A, making it suitable for loads with those ratings.@@arman4234

Yes, they are essentially the same transistor in terms of functionality and specifications. The only difference lies in their environmental compliance, with the TIP142G being lead-free to meet certain regulatory standards. In terms of electrical characteristics and usage, they are identical. It's always advisable to refer to the datasheet provided by the manufacturer for specific details.

Thank you for reaching out and bringing this to my attention. I'm sorry to hear that the circuit isn't working as expected with a 14-volt input. I'd be happy to help troubleshoot, but I'll need more information. Could you please provide details such as the specific components used, the circuit diagram, any error messages encountered, or any other relevant details? This will help me better understand the issue and assist you more effectively. Thanks!

I have created a circuit using the LM7805 voltage regulator IC that produces a stable 5V output, and it is working perfectly.

Yes, you can use it as a voltage regulator for your small amplifier. Ensure that you use a heatsink with the transistor to manage heat effectively. This setup will regulate the voltage to 12V.

@@technologywithconcept Thank you😊

This simulation is conducted using Proteus software.

Yes, it does work. You can increase the number of TIP142 transistors or use other transistors with a higher ampere rating. However, its efficiency will be low at higher currents, especially when the difference between input and output voltage is high. To address this: Heat Dissipation: A large heat sink with an accompanying fan is essential to manage the increased heat generated by the transistors. Current Handling: Indeed, ensuring that the 7812 regulators can provide sufficient current to the bases of each transistor is crucial for stable operation. Blocking Diodes: Adding blocking diodes to each transistor's output is a wise choice to prevent reverse current flow and protect the transistors. If efficiency is your concern, I would suggest using a switch mode/flyback converter/supply for higher efficiency.

@@technologywithconcept What is the strongest MOSFET I can put on it? In order for lm7812 not to decrease, can I prepare 10 of your circuits and connect them in parallel to make 100 amps?!

@@technologywithconcept I plan to make money by making and selling this circuit, but I don't want it for personal use

@@technologywithconcept My customer wants 100 amps and I thought I could parallel 10 of your circuits and increase the 10 amps to 100 amps?🤷

@@technologywithconcept I would be grateful if you could help me to increase the amperage of the circuit. If it is possible, tell me in detail the MOSFET model that gives a higher amperage. Thank you very much.

Replace 7805 IC with an adjustable voltage regulator IC LM317 and use a variable resistor of 22K Ohm instead of the diode in the circuit above.

​@@technologywithconceptdoing this voltage remain 24v and amp will boost to...? 5A or 6A..does it have fix value of ampere in output?

It seems like your question is a bit unclear, but I'll do my best to provide a general response. if your input is 24V, 2A (P=VxI, P=24Vx2A=48Watt) then it's not possible to convert it to 24V, 5A, or 6A, because output power will never be more than the input power.@@PrabhatKumar-tg8zn

@@technologywithconcept okay i get it. Now my question is can we control or regulate both voltage and ampere using potentiometer(knob) to get desired volt and ampere at same time keeping source power constant.? If i regulate volt say decrease then ampere should increase to make power of source remains constant.. Is it possible?

Yes, it is possible to control or regulate both voltage and current using a potentiometer (knob) in certain electronic circuits. I will make a video of it where a potentiometer will control the output voltage and another potentiometer will control the output current. you can also study and search for constant voltage sources and constant current sources. @@PrabhatKumar-tg8zn

I'm sorry to hear that you're feeling frustrated with your animation. If you'd like, I'm here to help. Whether you need technical advice or creative suggestions, feel free to share more details about what's bothering you, and I'll do my best to assist you.

please email on technologywithconcept@gmail.com

It seems like your comment is a bit unclear. If you could provide more details or context, I'd be happy to help you with whatever you're looking for. The video is clear, make sure to choose the highest quality option in your RUclips browser for an even better viewing experience.

Of course, we can add a TIP42 transistor in parallel to increase the output current rating but remember the LM7805 regulator should be capable of providing sufficient current on the base of each transistor or we should add more LM7805 ICs. Very soon i will make a video on it. thanks for your comment.

The output will be slightly less than 10A, a few mA current will flow through the 7812 regulator IC.

From 12V to 30V and 10A supply needed for input.

12v input will never get you 12v out. You need at least 15v and even more

Yes, you can use an N channel MOSFET, just connect the gate with the base, drain with input, and source with output.

Better to connect a capacitor (especially in case of motor load) but it also works without a capacitor.

yes, but must use a large heat sink with the transistor.

Certainly, this circuit will maintain a constant 5V output as long as the 7805 voltage regulator provides a constant 5V on the base of the TIP142 Transistor.

thank you.

in case of a short circuit more current will be required at the base of the TIP142 transistor, where the 7812 regulator has a maximum of 1A output current and has short circuit protection (also thermal protection), this will provide protection to some extent.

सदस्यता लेने और मेरे वीडियो को पसंद करने के लिए धन्यवाद। भाई, मैं विंडोज़ सिस्टम पर स्थापित माइक्रोसॉफ्ट द्वारा निर्मित एक निःशुल्क कंप्यूटर प्रोग्राम 'पेंट' का उपयोग कर रहा हूँ।

MS Paint

Proteus 8 Professional

@@technologywithconcept ok thanks

depend upon the relay rating, but the max current should be less than the short circuit current.

email on technologywithconcept@gmail.com

Yes

Thanks 👍

Hi, Bhabesh kumar Shaw If you are looking for a linear voltage regulator watch my other videos on this channel. Very soon i will upload a switch mode power supply video, where you will find a power supply of your requirement.

ruclips.net/video/FByv21aGg3g/видео.html

Thanks for your suggestion. Very soon we will make videos with voice-overs.