Can you Pass Stanford University Admission Interview ?✍️🖋️📘💙

[@wes9627]

Substitute x=y+3/2 into the given equation and rearrange to (y^2-9/4)(y^2-49/4)-24=y^4-(29/2)y^2+441/16-384/16=y^4-(29/2)y^2+57/16=0.
y^2=(29/2±28/2)/2=57/4 or 1/4; y=±√57/2 or ±1/2 and x=3/2+y=(3±√57)/2 or 2 or 1.

[@superacademy247]

Thanks for your insightful contribution to the discussion! 🎉🎁

[@ChavoMysterio]

(x-5)(x-3)=[24/(x(x+2))]
Domain
x(x+2)≠0
x≠{-2, 0}
x(x+2)(x-5)(x-3)=24
(x²-3x)(x²-3x-10)=24
Let y=x²-3x
y(y-10)=24
y²-10y=24
y²-10y-24=0
(y+2)(y-12)=0
y-12=0
x²-3x-12=0
4x²-12x-48=0
4x²-12x+9=57
(2x-3)²=57
|2x-3|=√57
2x-3=±√57
2x=3±√57
x=½(3±√57) ❤❤
y+2=0
x²-3x+2=0
(x-1)(x-2)=0
x-1=0
x=1 ❤
x-2=0
x=2 ❤