1) Force= 5N Displacement=150 cm = 1.5 m Work= Force x Displacement =7.5 J/ Nm 2) Work done is 0 when the angle between the for and the displacement is 90 degrees. 3) Work is a scalar quantity because it doesn't have distance but only magnitude. Thanks for the tutorial really helped! :)
If I'm not mistaken, you can't change KG to N. Since the given is 5 kg, you will convert it to N, where N=((kg)(m)/(s^2). And F=mg. Where you will use the gravity in this situation. W=Fd F=mg F=(5kg)(-9.81m/s^2) F=49.05N Substitute, W=(-49.05N)(1.5m) W=-73.575Nm or -73.575J
@@brenzkimseysabado1675 I do not believe the work done by the boy is a negative value since the boy lifted the book in the direction of the displacement. The work done by gravity would be negative since it is opposite of displacement. Have to be careful to know who, or what is doing the work. Yes, gravity is doing work in this problem yet that is not what was asked.
@@brenzkimseysabado1675 yaa you're right! And since this is a 9th grade topic, you can use g=10m/s², it'll be easier So the answer actually is just 75J
Wow, from Nigeria, I started watching your video yesterday and I really like the way you teach, the best I have come across. May God continue to strengthen you.
Hello dear from nigeria can u do friendship with me . iam a very weak in english And for learning english plz friendship with me .and which language is spoken in your country .
Did anyone notice he said that he stole his daughter's toy for that demo 😂😂 Wish my teacher also will teach like you, absolutely amazing👏👏👏👏, now I understand everything about physics from your videos sir, thank you so much and God bless you😄😄
Sir your video on work is more convincing. Even you use simple indian pronunciation. That's why I am impressed. Thank you sir. You are doing hard work. Without the intension of fruit. Thank you again. Keep it up!
Thankyou sir The answer of the questions 1.75 J (5*10(accelaration due to gravity= 50 mass we have to convert 150 cm to meter which is 1.5 meter work=force*displacement 50*1.5=75J)) 2.When the force and displacement are perpendicular to each other 3.Work is a scaler quantity
Literally sir, if there would be the teachers like you then those days are not so far that our country will be a superpower country, I am not exaggerating sir, I am telling truth sir ji.
Congratulations to you teacher for your commitment,l was three days watching your videos and it is very interested for me.now I live from south Sudan, student for form three.
@@ManochaAcademyI really love your method of teaching I was avery dull student in science but I am now at the average Thanks Mulch love From Nigeria🥰👍💥🏆
Great video! I would like to add something to this lesson though...at around 7:33 you teach something that everyone says when they teach this unit, that since the arm that's holding the bag has to resist gravity, then *all* the force HAS to be going straight up, so there can't be any work acting on the bag. My issue with that is we know the bag gets pulled to the side by the arm that's carrying it. Since there's a change in the motion of the bag, there has to be some force directing that bag sideways, meaning the angle isn't perfectly 90 degrees (maybe it's 89 degrees) and thus there is a small amount of work happening to kickstart the sideways motion. Ultimately, this isn't really going to change much about the calculations on the system, but as a student I always found the answer of "you don't do work after lifting the object" satisfying, since we're moving the object forwards. The work done wouldn't even be very large, since (if the object was going at a constant speed, meaning no acceleration or net force) it would be the momentum of the object keeping it moving forwards, not the work your arm does, but this clarification would probably satisfy students more, and tie in several different units for discussion in class.
oh great teaching.I have ever seen like this before so my answer are here.1)7.5 J , 2) a toy car pushing by hand , 3) it is a vector quantity. If our sir like this than it is easier for student to score higher in physics.
Q1.Since mass and lifting i.e corelate with force of gravitation.g=10 SO,formula for work = mgh(m =mass,g=forceofgravitation,h= height or displacement) W=5kg^10^1.5m (150÷100=1.5m) W=75 joule or 75 Nm Q2.Work done is zero only if force is perpendicular to the object or when the angle between force and displacement is zero. Q3.Work is a SCALAR Quantity because it has magnitude only not direction. 😌Hope you all understand through my answers ,if your answers are wrong then do practice as it make the person PErfect💯 From 🇮🇳🇮🇳🪷🇮🇳🇮🇳🪷🇮🇳🇮🇳
thank you sir......you are the BEST TEACHER IN THE WORLD........and my request is to make all videos regarding MATHS,PHYSICS,CHEMISTRY....almost all you have covered sir.......but remaining topics also make videos sir.....PLEASE SIR.....
Sir your explain is very easy to me and I improve in the physics class so thank you so much sir and I share the video to my friend also sir and my friend also improve ed sir so thank you so much sir 🙏
Sir is definitely doing great but plzzz don't compare between teacher... Physics wallah too is one of the best teacher.. Nd both of them are doing their best
@@ManochaAcademy i have a bacaloriate exam this year ,and i hope that i'm going to got the full mark ! A greeting from heart to such a great techers like you From Algeria ( north of Africa)
Only One thing I want to say that....teacher like you are required for every subject......for bright future of india.........Nowadays I am seeing students are just mugging concepts not even knowing where their knowledge used.......keep on teaching sir...... I am your huge fan
Sir how do you do these videos with patience you are such an amazing teacher I never I never hear this explanation one day unfortunately I open your video and the teaching is excellent and I went for comment section and all the comments are amazing excellent mind blowing super explanation all the comments are positively thank you sir you are such a great teacher and I am a big fan of you sir in studies thank you sir
Sir I want to ask another question on this topic.If I walk in a Circle many times then my body tired but due to zero displacement my work done is zero so where my body energy goes?
That's a great question! Yes the work done is zero due to zero displacement. But the body is doing work against the force of friction of ground. Which gets dissipated as heat energy. Plus work is being done at a muscular level. Here again some of the energy is dissipated as heat. So if we take into account these work dones and energy changes, that's where our body's energy is going. So we feel tired. Hope that helps :)
@@sivakumar-oh2if Coz that's how it is, work is the dot product of force and displacement. No offence, but your question is like asking why is sin/cos=tan.
Please make more videos on light and sound. And on chemistry. I love the way you teach with great demonstrations of concepts. I have started loving physics now.
You are amazing teacher 😍😍 I don't had any intrest in this topic but because of you I learnt it very clearly Thanku for it 🙏🙏 plz upload the answers of last 3 question
Thanks a lot :) Happy to hear that you liked the video!! Do check out more videos at www.manochaacademy.com . I have arranged the videos by subjects: Physics, Chemistry and Maths. I'll be uploading more videos!
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If all the teachers teach like you then the students will not face problems in studies
Great to hear that you liked the video!! Thanks a lot :)
S sir please upload detailed information with examples at that time student can easily understood.....
rad
Correct
@@chanduchayvlogs9548 that is rude he makes it very clear he is a good teacher
This is the best teaching i've ever seen thanks a lot sir.
You are most welcome
Sab dhoka baji ha
ruclips.net/channel/UCCtouuwYwq8Ostl5B4ZzomA
@@ayushmeerut43 e tu jjaa re
tere ko nahi padna to mat padh na
k
1) Force= 5N
Displacement=150 cm = 1.5 m
Work= Force x Displacement
=7.5 J/ Nm
2) Work done is 0 when the angle between the for and the displacement is 90 degrees.
3) Work is a scalar quantity because it doesn't have distance but only magnitude.
Thanks for the tutorial really helped! :)
If I'm not mistaken,
you can't change KG to N. Since the given is 5 kg, you will convert it to N, where N=((kg)(m)/(s^2). And F=mg. Where you will use the gravity in this situation.
W=Fd
F=mg
F=(5kg)(-9.81m/s^2)
F=49.05N
Substitute,
W=(-49.05N)(1.5m)
W=-73.575Nm or -73.575J
@@brenzkimseysabado1675 I do not believe the work done by the boy is a negative value since the boy lifted the book in the direction of the displacement. The work done by gravity would be negative since it is opposite of displacement. Have to be careful to know who, or what is doing the work. Yes, gravity is doing work in this problem yet that is not what was asked.
@@brenzkimseysabado1675 yaa you're right! And since this is a 9th grade topic, you can use g=10m/s², it'll be easier
So the answer actually is just 75J
Wow, from Nigeria, I started watching your video yesterday and I really like the way you teach, the best I have come across. May God continue to strengthen you.
Thanks a lot :) Do check out more Videos, Quiz and Top 3 Questions on my website: www.manochaacademy.com
Where are the answers?
ruclips.net/channel/UCCtouuwYwq8Ostl5B4ZzomA science channel
Hello dear from nigeria can u do friendship with me . iam a very weak in english And for learning english plz friendship with me .and which language is spoken in your country .
@@danishmushtaqdraboo5729 English
Did anyone notice he said that he stole his daughter's toy for that demo 😂😂
Wish my teacher also will teach like you, absolutely amazing👏👏👏👏, now I understand everything about physics from your videos sir, thank you so much and God bless you😄😄
agreeed gurl
Yes 🤣
Word
YA DUDE...
Stole toy for thousands of students to understand work
Thanks sir, this video really helped me for my exam! From the Philippines🇵🇭
"Pause the video and get a book right now"
Me: Holds my phone
What a coincidence bro I also hold a phone..
Sir your video on work is more convincing. Even you use simple indian pronunciation. That's why I am impressed. Thank you sir. You are doing hard work. Without the intension of fruit. Thank you again. Keep it up!
I don't know what is the magic behind your teaching.👍 But you are really great
Wow, thank you
Idk why this channel is not growing 😔 He teaches too good in very simple language. Anyone can understand him. HE IS THE BEST TEACHER ❤
This type of energy and Intresting teachers should be there in our school .
what
it should be in ALL schools
i had many doubts in this subject sir but it got clarified now thanks to you sir
Iam a teacher.i learned a lot from your teaching in this holidays.thank you sir
If all sciences teacher are like you...we will have many scientist
Great to hear that you like the videos!! Thanks :)
You are one of the best teacher
Thanks.
You are a great teacher, sir, the best one I have known. If only I had a nice teacher like you.
Wow, thanks
Thankyou sir
The answer of the questions
1.75 J
(5*10(accelaration due to gravity= 50 mass
we have to convert 150 cm to meter which is 1.5 meter
work=force*displacement
50*1.5=75J))
2.When the force and displacement are perpendicular to each other
3.Work is a scaler quantity
Me who wasted so much time in calculation by reading the 75 J as 1.75 J 😭
@@fathimamuzammil8818😂😂😂😂😂😂
Literally sir, if there would be the teachers like you then those days are not so far that our country will be a superpower country, I am not exaggerating sir, I am telling truth sir ji.
Sir your teaching is so great it even helped me to understand work and force I really adore your teachings sir like really!👍
Glad to hear that
👍👍keep it up
Congratulations to you teacher for your commitment,l was three days watching your videos and it is very interested for me.now I live from south Sudan, student for form three.
Thanks for liking.
teachers should be like you sir,Superb Explanation I like it
Thanks a ton
👍
Im learn future grade syllabus,thank you so much sir, I love the way you teach.
Excellent learning of physical science happily
Best way of teaching 🙂☺️
Best teaching method.
Thanks a lot!!
7 star teacher that I have ever seen
Thanks a lot :) Do share our videos with your friends!!
I wish every teacher of every subject could be as clear and perfect as u 👍👌🏼❤️
Thanks a lot :) Happy to hear that you liked the video!! Do check out more videos on my RUclips channel page or on my website: www.manochaacademy.com
If what you said was real, you would have watched this vid.
@@ManochaAcademyI really love your method of teaching
I was avery dull student in science but I am now at the average
Thanks
Mulch love
From Nigeria🥰👍💥🏆
sir after watching your video i am fallen in love of physics. thank sir. you are a great blessing
Thanks and welcome
If you'll teach me physics I'm gonna to become a best student. You are mind-blowing teacher
Yes yes ✅👍
Lol you are wrong
🦍🦍🦍🦍🦍🦍🦍
Yes yes👍👍
Yes sir
U r the best teacher in the world...
Sir really we are very lucky to listening ur videos.
It's my pleasure
Great video! I would like to add something to this lesson though...at around 7:33 you teach something that everyone says when they teach this unit, that since the arm that's holding the bag has to resist gravity, then *all* the force HAS to be going straight up, so there can't be any work acting on the bag. My issue with that is we know the bag gets pulled to the side by the arm that's carrying it. Since there's a change in the motion of the bag, there has to be some force directing that bag sideways, meaning the angle isn't perfectly 90 degrees (maybe it's 89 degrees) and thus there is a small amount of work happening to kickstart the sideways motion.
Ultimately, this isn't really going to change much about the calculations on the system, but as a student I always found the answer of "you don't do work after lifting the object" satisfying, since we're moving the object forwards. The work done wouldn't even be very large, since (if the object was going at a constant speed, meaning no acceleration or net force) it would be the momentum of the object keeping it moving forwards, not the work your arm does, but this clarification would probably satisfy students more, and tie in several different units for discussion in class.
Your way of teaching is excellent.
Every student should have a teacher like you 😇
Wow, thanks
Good
@@ManochaAcademy good
oh great teaching.I have ever seen like this before so my answer are here.1)7.5 J , 2) a toy car pushing by hand , 3) it is a vector quantity. If our sir like this than it is easier for student to score higher in physics.
Work is a scalar quantity
1) 75 J (Taking g=-10m/s^2)
2) Work done is zero , when force and displacement are perpendicular to each other
3) Scalar Quantity
the first one taking g as 9.8m/s^2 is 73.5 J
❤
Mass (m)= 50 kg
Displacement(s)=150cm=>1.5 m
Work Done(w)=F.s.
W= 50*1.5
= 75J
Q1.Since mass and lifting i.e corelate with force of gravitation.g=10
SO,formula for work = mgh(m =mass,g=forceofgravitation,h= height or displacement)
W=5kg^10^1.5m (150÷100=1.5m)
W=75 joule or 75 Nm
Q2.Work done is zero only if force is perpendicular to the object or when the angle between force and displacement is zero.
Q3.Work is a SCALAR Quantity
because it has magnitude only not direction.
😌Hope you all understand through my answers ,if your answers are wrong then do practice as it make the person PErfect💯
From 🇮🇳🇮🇳🪷🇮🇳🇮🇳🪷🇮🇳🇮🇳
Try to get used to using 9.8 for gravitational potentil strength
Wonderful teaching technic .I❤️ your classes
Same
Your teaching methods are awesome sir . Love from ranchi
Thanks a ton
Excellent explanation sir 👍👏
Very good explanation sir 👍. Thank you 😊😊😊
Most welcome
Thank you so much sir! You have made the introduction to this chapter so smooth!
thank you sir......you are the BEST TEACHER IN THE WORLD........and my request is to make all videos regarding MATHS,PHYSICS,CHEMISTRY....almost all you have covered sir.......but remaining topics also make videos sir.....PLEASE SIR.....
😊
you are the teacher which i like the most
Thanks
Thank you sir..❤️
3:14 my favourite part in this video...😂
Please give a Heart❤️ Sir.
from Bangladesh..
I started watching your video from today..
I so much like your class... You are very intelligent...
Sir your explain is very easy to me and I improve in the physics class so thank you so much sir and I share the video to my friend also sir and my friend also improve ed sir so thank you so much sir 🙏
Keep it up
Excellent explanation
Love your teaching from Uganda
Sir your way of explaining is great 🙏🙏🙏
Thanks and welcome
Excellent way to learning sir all basics are clear
Thank you ,you're great teacher go forward
Happy to hear that you liked the video!! Thanks :)
U are the best teacher .....
Thank you so much, videos like these really help during online school. Keep it up!!!
You r the best sir. Better than all those fellows like physics wallah. Thanks sir
Great to hear that you liked the video :) Thanks!! Do check out more videos at www.manochaacademy.com
Sir is definitely doing great but plzzz don't compare between teacher... Physics wallah too is one of the best teacher.. Nd both of them are doing their best
Sir you're superb...I like your teaching always , as I like spending time with my frnds ...It's really a fantastic experience for me ...😀🙂
Amazing teacher & learning process is wonderful .
Thank you for your support Sir. U explained it so easily. U don't even know that how much I was worried about this chapter and topic as well.
Happy to help
Thnx sir.
@@ManochaAcademy i have a bacaloriate exam this year ,and i hope that i'm going to got the full mark !
A greeting from heart to such a great techers like you
From Algeria ( north of Africa)
Best tutorial ever
Thanks for liking
wow what a style of teaching||New subscriber here💖||@Amazing
Welcome aboard!
You are the best teacher
THANKS
Thank you sir you are the best
Great to hear that you liked the video! Thanks :)
In teaching ur the best sir
I understand very well 👌👌
Only One thing I want to say that....teacher like you are required for every subject......for bright future of india.........Nowadays I am seeing students are just mugging concepts not even knowing where their knowledge used.......keep on teaching sir......
I am your huge fan
Thanks for liking
Amazing teaching Sir👍🏻✨
Thanks and welcome
Sir how do you do these videos with patience you are such an amazing teacher I never I never hear this explanation one day unfortunately I open your video and the teaching is excellent and I went for comment section and all the comments are amazing excellent mind blowing super explanation all the comments are positively thank you sir you are such a great teacher and I am a big fan of you sir in studies thank you sir
Wow, thanks
@@ManochaAcademy you're the best teacher we've ever seen on RUclips
Sir u r really very good..... And a very practical mind of people.. So u can xplain everything very well and very practically..
Thanks glad to hear that
Sir I want to ask another question on this topic.If I walk in a Circle many times then my body tired but due to zero displacement my work done is zero so where my body energy goes?
That's a great question! Yes the work done is zero due to zero displacement. But the body is doing work against the force of friction of ground. Which gets dissipated as heat energy. Plus work is being done at a muscular level. Here again some of the energy is dissipated as heat. So if we take into account these work dones and energy changes, that's where our body's energy is going. So we feel tired. Hope that helps :)
@@ManochaAcademy why cont we use distance instead of displacement sir please help thanks
@@sivakumar-oh2if Coz that's how it is, work is the dot product of force and displacement. No offence, but your question is like asking why is sin/cos=tan.
Manish kumar Sharma
@@ManochaAcademy sir can u say which guide is best for 11 cbse because my sister is going to study 11 please
Thanks you sir best teacher
Its a very useful.video.i got all the answers of my questions from it.Love from Bangladesh..
Excellent teaching ❤❤❤
Q1: -75J
Q2: when F & S mutually perpendicular each other.
Q3: Scalar quantity
Sir, You are mind blowing teacher and thanks for the video.
isn't the first answer 7.5? like 150/100?
@@hetvi9639 yes its 7.5J
@@hetvi9639 when you'll multiply 1.5m to 50N , it will be 75J.
How to find acceleration?
@@Mascot17
Acceleration a= 9.81 m/s2 approximately 10m/s2. F=mxa=5x10=50N.
Thanks sir of the global school :);)
Thanks sir, this video is very helpful for me
Glad to hear that
Q1) -75 J
Q2) When the Q is 90°. When force is equal to zero and displacement is equal to zero
Q3) It is a scalar quantity
Did you use g= -10?
You are correct only but that is .75J
750 j work aara ha mera koi btao sahi ha ya glat
I got Q1) 750
Q1 = 75 J
Best teacher of physics as ever I've seen
Even though I forgot something on this chapter, i can easily rewatch your video. Thank you
thanks sir for helping us well when we come to the question 1, 75 J
2, the angel is equal to 90 degree
3, Work is scalar physical quantity
Thank you so much sir
for Your explnation clearly and praticlly
And also thank to you done good job for us
Great to hear that you liked the video :) Thanks!
3:14 So funny!!! You teach the concepts very well!!
i love this you explain things very clearly slowly. i am naturally a slow learner it drives people crazy
Sir! your explanation is just WOW!!!!!!
THANKS A LOT TO MAKE STUDENTS LIFE EASY
You are most welcome
Please make more videos on light and sound. And on chemistry. I love the way you teach with great demonstrations of concepts. I have started loving physics now.
Ur concept delivery is awesome sir
Thanks a ton
3:14 daughter be like : dad where is my toy
the best teaching
Thanks
Yes, - 7.5 joule q2 at right angled q3 scaler quantity
Now the topic is very clear sir.
Thank you so much sir.
Always welcome
I enjoyed watching your videos! Amazing.
Thanks! Glad you liked the videos :) I'll be posting more videos regularly!
Hi how are yuo sir yuor all teaching is very nice
Very nice explanation.simple explanation of difficult concepts in a simple way🙏
Thanks and welcome
Nice sir u r great
Thanks! Happy to hear that you liked the video :)
I'm becoming a good science student with your video. I'm in Nigeria. Thanks.
You are amazing teacher 😍😍 I don't had any intrest in this topic but because of you I learnt it very clearly
Thanku for it 🙏🙏 plz upload the answers of last 3 question
using your daughter's toys show how amazing teacher and father you are. congratulations sir!
Thank you very much!
Thanks Sir
Welcome
Best teacher in the World
Thanks a lot :) Do share the videos with your friends and family!!
Thank you for teaching in such a clear and structured manner. It really helped me to understand the topic!
U are amazing great teacher that every students will love to have
1)7.5J
2)when the direction force and displacement are perpendicular to each other
3)vetor quantity
U R Amazing!!👌👌👌 Plz Upload Class 10th Science all chapters!!!!
Thanks a lot :) Happy to hear that you liked the video!! Do check out more videos at www.manochaacademy.com . I have arranged the videos by subjects: Physics, Chemistry and Maths. I'll be uploading more videos!
@@ManochaAcademysir I have shared ur video s to my friends
#diwakarphysics
👌👌👌👌 Very good display of the topic...
Thanks a lot!
Thank you so much sir for your videos, the way you explaining the concept its awesome and you make physics very easy.
No one like u In the world u are the best teacher and iam watching this video from yesterday I saw all the vedio s of u it's awesome
Great to hear that :) Thanks a ton!! Do share it with your friends and family! Also see my website: www.manochaacademy.com
Ok sir definitely